Chapter 23: Problem 28
The vapor pressure of benzaldehyde is 400 torr at \(154^{\circ} \mathrm{C}\) and its normal boiling point is \(179^{\circ} \mathrm{C}\). Estimate its molar enthalpy of vaporization. The experimental value is \(42.50 \mathrm{kJ} \cdot \mathrm{mol}^{-1}\).
Short Answer
Expert verified
Estimated \( \Delta H_{vap} \approx 42.51 \frac{kJ}{mol} \), which is close to the experimental value.
Step by step solution
01
Understand the Clausius-Clapeyron Equation
The Clausius-Clapeyron equation relates the change in vapor pressure to the change in temperature for a substance. It can be written as: \[\ln \left( \frac{P_2}{P_1} \right) = \frac{\Delta H_{vap}}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right)\] where \( P_1 \) and \( P_2 \) are the vapor pressures at temperatures \( T_1 \) and \( T_2 \) respectively, \( \Delta H_{vap} \) is the molar enthalpy of vaporization, and \( R \) is the ideal gas constant (8.314 J/mol·K).
02
Input Given Values
For benzaldehyde, the given vapor pressure \( P_1 \) is 400 torr at \( T_1 = 154^{\circ}C = 427K \). The normal boiling point \( T_2 \) is \( 179^{\circ}C = 452K \) where the vapor pressure \( P_2 \) is 760 torr. We need to estimate \( \Delta H_{vap} \).
03
Convert Units and Use the Equation
Apply the Clausius-Clapeyron equation:Substituting the provided values gives:\[\ln \left( \frac{760}{400} \right) = \frac{\Delta H_{vap}}{8.314} \left( \frac{1}{427} - \frac{1}{452} \right)\] Calculate \( \ln(1.9) \) and \( \left( \frac{1}{427} - \frac{1}{452} \right) \) to proceed.
04
Solve for \( \Delta H_{vap} \)
Calculate \( \ln(1.9) \approx 0.6419 \) and \( \left( \frac{1}{427} - \frac{1}{452} \right) \approx -0.0001656 \). Now substitute back into the equation:\[\0.6419 = \frac{\Delta H_{vap}}{8.314} \times (-0.0001656)\]Rearrange to solve for \( \Delta H_{vap} \):\[\Delta H_{vap} \approx \frac{0.6419}{8.314 \times -0.0001656}\]Calculate to find \( \Delta H_{vap} \).
05
Final Calculation and Conversion
Perform the calculation: \( \Delta H_{vap} \approx 42,508 \frac{J}{mol} \approx 42.51 \frac{kJ}{mol} \). This value is close to the experimental value of \( 42.50 \frac{kJ}{mol} \), confirming the estimation.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Clausius-Clapeyron Equation
The Clausius-Clapeyron equation is a fundamental principle used to understand the relationship between vapor pressure and temperature for a substance. This equation is expressed as: \[\ln \left( \frac{P_2}{P_1} \right) = \frac{\Delta H_{vap}}{R} \left( \frac{1}{T_1} - \frac{1}{T_2} \right)\]Here:
- \( P_1 \) and \( P_2 \) represent the vapor pressures at two different temperatures, \( T_1 \) and \( T_2 \), respectively.
- \( \Delta H_{vap} \) is the molar enthalpy of vaporization, which signifies the energy required to convert a mole of liquid into vapor at constant temperature and pressure.
- \( R \) is the ideal gas constant, approximately 8.314 J/mol·K.
Vapor Pressure
Vapor pressure is a measure of a liquid's tendency to evaporate. It refers to the pressure exerted by a vapor in equilibrium with its liquid phase at a given temperature.
When a liquid is in a sealed container, molecules escape from the liquid to become gas, creating a pressure over the liquid. This is vapor pressure.
Some important aspects include:
- Vapor pressure increases with temperature. As the temperature rises, more molecules have the energy to escape the liquid state.
- At the boiling point, vapor pressure equals the atmospheric pressure. This is why liquids boil at lower temperatures at higher altitudes where atmospheric pressure is lower.
- A substance with a high vapor pressure at normal temperatures is often referred to as volatile.
Ideal Gas Constant
The ideal gas constant, denoted as \( R \), is a central factor in the equation of state for an ideal gas. It provides a link between macroscopic and microscopic physical properties of gases. Its value is approximately 8.314 J/mol·K. This constant appears in several gas-related equations, such as:
- The ideal gas law: \( PV = nRT \), which describes how pressure, volume, and temperature relate for an ideal gas.
- The Clausius-Clapeyron equation, where \( R \) relates the vapor pressure change to temperature change for phase transition.
- \( R \) Universal: It applies to all gases under ideal conditions, making it a fundamental constant in chemistry and physics.
- Helps explain behavior of gases: By combining it with Avogadro's law and others, it helps predict how gases will respond to changes in their environment.
- Units of \( R \): Commonly used units are J/mol·K, but it can also be expressed in other units depending on the context or the specific application.