27\. In this problem, we will derive a general relation between \(C_{P}\) and
\(C_{V}\). Start with \(U=U(P, T)\) and write
$$
d U=\left(\frac{\partial U}{\partial P}\right)_{T} d P+\left(\frac{\partial
U}{\partial T}\right)_{P} d T
$$
We could also consider \(V\) and \(T\) to be the independent variables of \(U\) and
write
$$
d U=\left(\frac{\partial U}{\partial V}\right)_{T} d V+\left(\frac{\partial
U}{\partial T}\right)_{V} d T
$$
Now take \(V=V(P, T)\) and substitute its expression for \(d V\) into Equation 2
to obtain
$$
d U=\left(\frac{\partial U}{\partial V}\right)_{T}\left(\frac{\partial
V}{\partial P}\right)_{T} d P+\left[\left(\frac{\partial U}{\partial
V}\right)_{T}\left(\frac{\partial V}{\partial
T}\right)_{P}+\left(\frac{\partial U}{\partial T}\right)_{V}\right] d T
$$
Compare this result with Equation 1 to obtain
$$
\left(\frac{\partial U}{\partial P}\right)_{T}=\left(\frac{\partial
U}{\partial V}\right)_{T}\left(\frac{\partial V}{\partial P}\right)_{T}
$$
and
$$
\left(\frac{\partial U}{\partial T}\right)_{P}=\left(\frac{\partial
U}{\partial V}\right)_{T}\left(\frac{\partial V}{\partial
T}\right)_{P}+\left(\frac{\partial U}{\partial T}\right)_{V}
$$
Last, substitute \(U=H-P V\) into the left side of Equation (4) and use the
definitions of \(C_{P}\) and \(C_{V}\) to obtain
$$
C_{P}-C_{V}=\left[P+\left(\frac{\partial U}{\partial
V}\right)_{T}\right]\left(\frac{\partial V}{\partial T}\right)_{P}
$$
Show that \(C_{P}-C_{V}=n R\) if \((\partial U / \partial V)_{T}=0\), as it is for
an ideal gas.