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Prove that the inequality \\[\frac{N_{2}}{N_{\text {total }}}<\frac{1}{2}\\] impiies that \(N_{2} / N_{1}\), is iess than \(1 .\) ( Hint: Use the fact that \(1 / a>1\) / b if \(a< b\).)

Short Answer

Expert verified
The inequality \(\frac{N_2}{N_{\text{total}}} < \frac{1}{2}\) implies \(\frac{N_2}{N_1} < 1\) because \(N_2 < N_1\).

Step by step solution

01

Understand the Given Inequality

We are given the inequality \(\frac{N_2}{N_{\text{total}}} < \frac{1}{2}\). This means that the portion of \(N_2\) out of the total \(N_{\text{total}}\) is less than half. We need to show that this implies \(\frac{N_2}{N_1} < 1\).
02

Relate Terms using Total Part

Note that \(N_{\text{total}}\) is the sum of \(N_1\) and \(N_2\): \(N_{\text{total}} = N_1 + N_2\). Replace \(N_{\text{total}}\) in the inequality: \(\frac{N_2}{N_1 + N_2} < \frac{1}{2}\).
03

Manipulate the Inequality

By cross-multiplying, we get \(2N_2 < N_1 + N_2\). Simplify this to obtain \(N_2 < N_1\).
04

Conclude the Relationship

Because \(N_2 < N_1\), it follows that \(\frac{N_2}{N_1} < 1\). This confirms what we needed to prove, using the hint that if \(a < b\), then \(\frac{1}{a} > \frac{1}{b}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportions and Ratios
In physical chemistry, proportions and ratios are vital as they help us compare quantities, providing insights into the relationship between different components in a system. When dealing with ratios such as \(\frac{N_2}{N_{\text{total}}}\), we assess how one part of the system compares to its entirety. This specific ratio indicates what fraction of the total is comprised of \(N_2\).

Ratios are crucial since they allow chemists to predict system behaviors and changes when subjected to different conditions. They are expressed in simplest forms to clearly show the relationship between quantities. For the given problem, the proportion being less than \(\frac{1}{2}\) tells us that \(N_2\) is less than half of \(N_\text{total}\). This understanding helps lay the groundwork for further mathematical exploration, such as inequality proofs.
  • Ratios signify the comparative size of two quantities.
  • Proportions describe how a part relates to the whole.
  • Simplifying expressions provides clearer insight.
Mathematical Manipulation in Chemistry
Chemical equations and inequalities often require manipulation to reveal hidden relationships between quantities. In the exercise, the critical step involves manipulating the inequality \(\frac{N_2}{N_1 + N_2} < \frac{1}{2}\). Let's break it down.

First, identify and understand the components of the equation: \(N_\text{total} = N_1 + N_2\). Substituting this into the original inequality simplifies it and makes it more workable.

Cross-multiplying is a useful technique to isolate and compare the terms. For example, multiplying each side of the inequality \(\frac{N_2}{N_1 + N_2} < \frac{1}{2}\) by \(2(N_1 + N_2)\) leads to \(2N_2 < N_1 + N_2\).
  • Substitution helps reveal relationships between variables.
  • Cross-multiplication simplifies comparisons.
  • Breaking down equations leads to clearer, concise conclusions.
Understanding Inequalities
Inequalities play a pivotal role in physical chemistry, as they allow for predicting unknown limitations or constraints within a chemical system. An inequality like \(\frac{N_2}{N_\text{total}} < \frac{1}{2}\) implies a condition where \(N_2\) must be proportionally less than half of the total. By exploring this inequality, we arrive at another: \(\frac{N_2}{N_1} < 1\).

The inequality \(a < b\) implies that \(\frac{1}{a} > \frac{1}{b}\), often helpful in rearranging terms to show relationships. This fundamental concept aids in concluding that \(N_2 < N_1\), thereby establishing \(\frac{N_2}{N_1} < 1\).

Understanding such inequalities helps prevent errors in assumptions about the behavior of chemical systems.
  • Inequalities are essential tools for interpreting system dynamics.
  • They provide conditions that restrict possible values within chemical systems.
  • Grasping them facilitates accurate predictions in laboratory and theoretical scenarios.

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Most popular questions from this chapter

The Einstein coefficients can also be derived using quantum mechanics. If the ground state and the excited state have a degeneracy of \(g_{1}\) and \(g_{2}\), respectively, the Einstein \(A\) coefficient is given by $$ A=\frac{16 \pi^{3} v^{3} g_{1}}{3 \varepsilon_{0} h c^{3} g_{2}}|\mu|^{2} $$ where \(|\mu|\) is the transition dipole moment (see Section 13-11). Now consider the \(1 s \rightarrow 2 p\) absorption of \(\mathrm{H}(\mathrm{g})\), which is observed at \(121.8 \mathrm{~nm}\). The radiative lifetime (see Example 15-3) of the triply degenerate excited \(2 p\) state of \(\mathrm{H}(\mathrm{g})\) is \(1.6 \times 10^{-9} \mathrm{~s}\). Determine the value of the transition dipole moment for this transition.

Consider the nondegenerate three-level system shown in Figure \(15.8\). Suppose that an incident light beam of energy \(h v=E_{3}-E_{1}\) is turned on for a while and then turned off. Show that the subsequent decay of the \(E_{3}\) level is given by $$ N_{3}(t)=N_{3}^{0} e^{-\left(A_{32}+A_{31}\right) t} $$ where \(N_{3}^{0}\) is the number of atoms in state 3 at the instant the light source is turned off. What will be the observed radiative lifetime of this excited state?

Hydrogen iodide decomposes to hydrogen and iodine when it is irradiated with radiation of frequency \(1.45 \times 10^{15} \mathrm{Hz}\). When \(2.31 \mathrm{J}\) of energy is absorbed by \(\mathrm{HI}(\mathrm{g}), 0.153 \mathrm{mg}\) of \(\mathrm{HI}(\mathrm{g})\) is decomposed. Calculate the quantum yield for this reaction.

The frequency of laser light can be converted using nonlinear optical materials. The most common form of frequency conversion is second harmonic generation, whereby laser light of frequency \(v\) is converted to light at frequency \(2 v\). Calculate the wavelength of the second harmonic light from a \(\mathrm{Nd}^{3+}:\) YAG laser. If the output pulse of a \(\mathrm{Nd}^{3+}: \mathrm{YAG}\) laser at \(1064.1 \mathrm{nm}\) has a radiant energy of \(150.0 \mathrm{mJ}\), how many photons are contained in this pulse? Calculate the maximum number of photons that can be generated at the second harmonic. (Hint: Energy must be conserved.)

A mole of photons is called an einstein. Calculate the radiant energy of an einstein if the photons have a wavelength of \(608.7 \mathrm{nm}\).

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