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A titanium sapphire laser operating at \(780 \mathrm{~nm}\) produces pulses at a repetition rate of \(100 \mathrm{MHz}\). If each pulse is \(25 \mathrm{fs}\) in duration and the average radiant power of the laser is \(1.4 \mathrm{~W}\), calculate the radiant power of each laser pulse. How many photons are produced by this laser in one second?

Short Answer

Expert verified
Each pulse has a radiant power of \(1.4 \times 10^{-8} \mathrm{~J}\), and the laser produces about \(5.49 \times 10^{18}\) photons per second.

Step by step solution

01

Calculate the Energy per Pulse

The average power \(P_{avg}\) of the laser is given as \(1.4 \mathrm{~W}\), and the repetition rate \(f\) is \(100 \mathrm{MHz}\). Since power is energy per unit time, the energy per pulse, \(E_{pulse}\), can be calculated using \(E_{pulse} = \frac{P_{avg}}{f}\). First, convert the repetition rate to \(1/s\): \(100 \mathrm{MHz} = 100 \times 10^6 \mathrm{Hz}\). Then:\[E_{pulse} = \frac{1.4 \mathrm{~W}}{100 \times 10^6 \mathrm{Hz}} = 1.4 \times 10^{-8} \mathrm{~J}\]
02

Calculate the Energy of Each Photon

The energy of a single photon \(E_{photon}\) can be calculated using the formula \(E_{photon} = \frac{hc}{\lambda}\), where \(h\) is Planck's constant \((6.626 \times 10^{-34} \mathrm{~Js})\), \(c\) is the speed of light \((3 \times 10^8 \mathrm{~m/s})\), and \(\lambda\) is the wavelength \(780 \mathrm{~nm} = 780 \times 10^{-9} \mathrm{~m}\). Substituting the values:\[E_{photon} = \frac{6.626 \times 10^{-34} \mathrm{~Js} \times 3 \times 10^8 \mathrm{~m/s}}{780 \times 10^{-9} \mathrm{~m}} \approx 2.55 \times 10^{-19} \mathrm{~J}\]
03

Calculate Number of Photons per Pulse

The number of photons in each pulse \(n_{pulse}\) is determined by dividing the energy per pulse by the energy per photon: \(n_{pulse} = \frac{E_{pulse}}{E_{photon}}\). Using the values calculated:\[n_{pulse} = \frac{1.4 \times 10^{-8} \mathrm{~J}}{2.55 \times 10^{-19} \mathrm{~J}} \approx 5.49 \times 10^{10} \text{ photons}\]
04

Calculate Total Photons Produced in One Second

To find the total number of photons produced in one second, multiply the number of photons per pulse by the number of pulses per second \(f\):\[N_{total} = n_{pulse} \times f = 5.49 \times 10^{10} \text{ photons} \times 100 \times 10^6 \text{ pulses/s} \approx 5.49 \times 10^{18} \text{ photons/s}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Photon Energy
Photon energy is the fundamental concept that describes the energy carried by a single photon, which is a particle of light. This energy can be quantified using the equation: \[E_{photon} = \frac{hc}{\lambda}\]where:
  • \( h \) is Planck's constant, approximately \(6.626 \times 10^{-34} \text{ Js}\).
  • \( c \) is the speed of light, \(3 \times 10^8 \text{ m/s}\).
  • \( \lambda \) is the wavelength of the photon in meters.
This formula shows that the energy of a photon is inversely proportional to its wavelength. The shorter the wavelength, the higher the energy of the photon, which is crucial in understanding how different types of light carry energy. In the provided exercise, the wavelength is \(780 \text{ nm}\), and when plugged into the formula, this yields a photon energy of approximately \(2.55 \times 10^{-19} \text{ J}\). This calculation is important for determining how much energy is emitted by the laser in each photon.
Radiant Power
Radiant power refers to the total energy emitted by a light source per unit time and is usually measured in watts (W). In laser optics, radiant power is essentially the average power that the laser emits. It tells us how strong the laser is in terms of energy output over time. In the original problem, the average radiant power of the laser is given as \(1.4 \text{ W}\). This value indicates that each second, the laser emits energy equivalent to \(1.4\) joules. This parameter is crucial for applications where the energy delivery rate is important, such as in cutting or engraving processes using lasers. To determine the energy per pulse, you utilize the average power and the repetition rate of the laser: \[E_{pulse} = \frac{P_{avg}}{f}\]This equation means that the radiant power is divided over each pulse that the laser produces, giving insight into how much energy is packed into each individual burst of light.
Pulse Energy
Pulse energy is a measure of the energy output of a laser during a single pulse. It plays a critical role in determining the performance and impact of a laser, especially in short pulse lasers like the titanium sapphire laser described in the exercise. In this context, the calculation for pulse energy is derived from the total radiant power divided by the repetition rate, revealing how much energy that laser delivers with each pulse:\[E_{pulse} = \frac{P_{avg}}{f}\]
  • \( P_{avg} \) is the average power of the laser.
  • \( f \) is the repetition rate of the laser, or how many pulses are produced each second.
With a radiant power of \(1.4 \text{ W}\) and a repetition rate of \(100 \text{ MHz}\), the pulse energy calculated for the laser is approximately \(1.4 \times 10^{-8} \text{ J}\). Understanding this value is pivotal for applications requiring precise energy delivery, such as in medical and industrial laser systems.
Repetition Rate
The repetition rate is the frequency at which a laser emits pulses of light, typically measured in megahertz (MHz) or hertz (Hz). It is a crucial parameter because it determines how often pulses are produced and influences the average power output over time. In the exercise, the titanium sapphire laser operates at a repetition rate of \(100 \text{ MHz}\), which means it emits pulses at the extremely rapid rate of 100 million pulses per second. The repetition rate impacts:
  • The pulse energy - With more frequent pulses, the energy per pulse can be lower to maintain a consistent average power.
  • Applications - Different applications require varied repetition rates, depending on the desired outcome (e.g., precision cutting, material ablation).
In the context of the calculation, the repetition rate is used to determine both the energy per pulse and the total number of photons produced per second. By multiplying the number of photons per pulse with the repetition rate, the total photon output of the laser is assessed, amounting to approximately \(5.49 \times 10^{18}\) photons per second in this case.

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Most popular questions from this chapter

The spectral radiant energy density was expressed in terms of the frequency of the electromagnetic radiation. We could have chosen to express the spectral radiant energy density in terms of the wave number or wavelength of the electromagnetic radiation. Recall that the units of \(\rho_{v}(v)\) are \(\mathrm{J} \cdot \mathrm{m}^{-3} \cdot \mathrm{s}\). Show that the units of \(\rho_{\tilde{v}}(\tilde{v})\), the spectral radiant energy density in terms of wave numbers, are \(\mathrm{J} \cdot \mathrm{m}^{-2}\) and that the units of \(\rho_{\lambda}(\lambda)\), the spectral radiant energy density in terms of wavelength, are \(\mathrm{J} \cdot \mathrm{m}^{-4}\). What are the units of the Einstein \(B\) coefficient if we use \(\rho_{\bar{v}}(\tilde{v})\) to describe the spectral radiant energy density? What are the units of the Einstein \(B\) coefficient if we use \(\rho_{\dot{\lambda}}(\lambda)\) to describe the spectral radiant energy density?

The ground-state term symbol for \(\mathrm{O}_{2}^{+}\)is \({ }^{2} \Pi_{g}\). The first electronic excited state has an energy of \(38795 \mathrm{~cm}^{-1}\) above that of the ground state and has a term symbol of \({ }^{2} \Pi_{u}\). Is the radiative \({ }^{2} \Pi_{u} \rightarrow{ }^{2} \Pi_{g}\) decay of the \(\mathrm{O}_{2}^{+}\)molecule an example of fluorescence of phosphorescence?

Which laser pulse contains more photons, a 10 -ns, 1.60 -mJ pulse at 760 nm or a 500 -ms, \(1.60-\mathrm{mJ}\) pulse at \(532 \mathrm{nm} ?\)

Hydrogen iodide decomposes to hydrogen and iodine when it is irradiated with radiation of frequency \(1.45 \times 10^{15} \mathrm{Hz}\). When \(2.31 \mathrm{J}\) of energy is absorbed by \(\mathrm{HI}(\mathrm{g}), 0.153 \mathrm{mg}\) of \(\mathrm{HI}(\mathrm{g})\) is decomposed. Calculate the quantum yield for this reaction.

The upper level of the \(\mathrm{H}_{2}(\mathrm{~g})\) laser is the lowest excited state of the molecule, the \(B^{1} \Sigma_{u}^{+}\) state, and the lower level is the \(X^{1} \Sigma_{g}^{+}\)ground state. The lasing occurs between the \(v^{\prime}=5\) level of the excited state and the \(v^{n}=12\) level of the ground state. Use the following spectroscopic data to determine the wavelength of the laser light from the \(\mathrm{H}_{2}(\mathrm{~g})\) laser. \begin{tabular}{lccc} State & \(\tilde{T}_{e} / \mathrm{cm}^{-1}\) & \(\tilde{\nu}_{e} / \mathrm{cm}^{-1}\) & \(\tilde{v}_{e} \tilde{x}_{e} / \mathrm{cm}^{-1}\) \\ \hline\(B^{1} \Sigma_{u}^{+}\) & \(91689.9\) & \(1356.9\) & \(19.93\) \\ \(X^{1} \Sigma_{g}^{+}\) & 0 & \(4401.2\) & \(121.34\) \end{tabular} A \(1.0 \mathrm{~ns}\) pulse can be generated with a pulse radiant power of \(100 \mathrm{~kW}\). Calculate the radiant energy of such a laser pulse. How many photons are there in this pulse?

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