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In the troposphere carbon monoxide and nitrogen dioxide undergo the following reaction: \\[ \mathrm{NO}_{2}(g)+\mathrm{CO}(g) \rightarrow \mathrm{NO}(g)+\mathrm{CO}_{2}(g) \\] Experimentally, the rate law for the reaction is second order in \(\mathrm{NO}_{2}(g),\) and \(\mathrm{NO}_{3}(g)\) has been identified as an intermediate in this reaction. Construct a reaction mechanism that is consistent with these experimental observations.

Short Answer

Expert verified
A possible reaction mechanism for the given reaction between \(\mathrm{NO}_2(g)\) and \(\mathrm{CO}(g)\), forming \(\mathrm{NO}(g)\) and \(\mathrm{CO}_2(g)\), consists of two elementary steps: 1. \(2 \ \mathrm{NO}_2(g) \xrightarrow{k_1} \mathrm{NO}_3(g) + \mathrm{NO}(g) \) 2. \( \mathrm{NO}_3(g) + \mathrm{CO}(g) \xrightarrow{k_2} \mathrm{NO}(g) + \mathrm{CO}_2(g) \) This proposed mechanism is consistent with the given experimental rate law, which is second order in \(\mathrm{NO}_2(g)\), and the presence of the \(\mathrm{NO}_3(g)\) intermediate.

Step by step solution

01

Understanding Reaction Mechanism

A reaction mechanism is comprised of a series of elementary reactions or steps that take place one after another, leading to the overall balanced chemical equation. Each elementary step has its own rate law, which reflects the order of the reaction for each reactant involved in that step. The overall rate law is determined by the slowest step or rate-determining step (RDS) in the mechanism, while the intermediate is produced in one of the steps and then decomposed in a subsequent step.
02

Identifying the Given Information

We are given that the rate law for the overall reaction is second order in \(\mathrm{NO}_2(g)\). This means that the rate-determining step must involve 2 molecules of \(\mathrm{NO}_2(g)\). Additionally, we know that \(\mathrm{NO}_3(g)\) is an intermediate in the reaction. Let's use this information to propose a mechanism and then verify whether our proposed mechanism is consistent with the experimental data.
03

Proposing a Reaction Mechanism

Let's propose the following two-step reaction mechanism: 1. \( 2 \ \mathrm{NO}_2(g) \xrightarrow{k_1} \mathrm{NO}_3(g) + \mathrm{NO}(g) \) 2. \( \mathrm{NO}_3(g) + \mathrm{CO}(g) \xrightarrow{k_2} \mathrm{NO}(g) + \mathrm{CO}_2(g) \) First, we need to confirm that the addition of these two steps yields the overall reaction. Adding the steps, we get: \( 2 \ \mathrm{NO}_2(g) + \mathrm{CO}(g) \rightarrow \mathrm{NO}_3(g) + \mathrm{NO}(g) + \mathrm{NO}(g) + \mathrm{CO}_2(g) \) Canceling the intermediate, \(\mathrm{NO}_3(g)\), we get: \( \mathrm{NO}_2(g) + \mathrm{CO}(g) \rightarrow \mathrm{NO}(g) + \mathrm{CO}_2(g) \) which is the overall balanced equation.
04

Verifying the Rate Law

Since \(\mathrm{NO}_2(g)\) is second order in the rate law, the first step must involve the collision of two molecules of \(\mathrm{NO}_2(g)\) and must be the rate-determining step. Let's write the rate law for the first step: Rate = \(k_1\mathrm{[\!NO_{2}]}^2\) Because our mechanism indicates that the first step is the slowest step and is second order in \(\mathrm{NO}_2(g)\), this proposal is consistent with the given experimental observations.
05

Conclusion

In conclusion, we have proposed a reaction mechanism for the given reaction between \(\mathrm{NO}_{2}(g)\) and \(\mathrm{CO}(g)\), which forms \(\mathrm{NO}(g)\) and \(\mathrm{CO}_{2}(g)\). The proposed mechanism consists of two elementary steps and is consistent with the given experimental rate law and the presence of the \(\mathrm{NO}_{3}(g)\) intermediate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics is the branch of chemistry that deals with the rates of chemical reactions and the mechanisms by which they occur. It seeks to understand the steps involved in the transformation of reactants to products, the differing speeds at which reactions occur, and how various factors such as temperature, pressure, and concentration influence these rates.

To grasp chemical kinetics, consider the reaction between carbon monoxide and nitrogen dioxide in the troposphere. The speed at which this reaction progresses, and what governs this speed, are central questions answered by chemical kinetics. By dissecting the reaction step by step, kineticists can gather information about the reaction rate and deduce a rate law that scientifically defines these observations.
Rate Law
The rate law is a mathematical relationship that describes the reaction rate as a function of the concentration of reactants. It is unique to every chemical reaction and must be determined experimentally. In this case, the rate law for the reaction between nitrogen dioxide and carbon monoxide is second order in \(\mathrm{NO}_{2}(g)\), meaning that the rate of the reaction depends on the concentration of \(\mathrm{NO}_{2}(g)\) raised to the second power.

To put it simply, if the concentration of \(\mathrm{NO}_{2}(g)\) is doubled, the reaction rate increases by a factor of four. This quadratic relationship is key to understanding the dynamics of the reacting system and influences how one might control or optimize the reaction in various industrial or environmental settings.
Intermediates in Chemical Reactions
Intermediates are species that appear in the mechanism of a chemical reaction but not in the overall balanced equation because they are neither reactants nor final products. They are produced in one step and consumed in another. The formation of intermediates is an important aspect because they often reveal significant details about the pathway a reaction follows.

For our given reaction, \(\mathrm{NO}_{3}(g)\) is identified as an intermediate. It is crucial in linking the reactants to the eventual products. Understanding how an intermediate is created and later utilized or destroyed gives valuable insight into the mechanism and potential side reactions that could be targeted for inhibition or enhancement in chemical processes.
Elementary Reaction Steps
Elementary reaction steps are individual reactions that happen within a complex chemical reaction mechanism. Each elementary step typically involves a small number of molecules, often only one, two, or three, and directly corresponds to a single molecular event, such as bond formation or breaking.

The proposed reaction mechanism for the combination of \(\mathrm{NO}_{2}(g)\) and \(\mathrm{CO}(g)\) hypothesizes two elementary steps. The first is the formation of \(\mathrm{NO}_{3}(g)\) and \(\mathrm{NO}(g)\) from the reaction of two \(\mathrm{NO}_{2}(g)\) molecules, and the second is the reaction of the intermediate \(\mathrm{NO}_{3}(g)\) with \(\mathrm{CO}(g)\) to produce \(\mathrm{NO}(g)\) and \(\mathrm{CO}_{2}(g)\). These steps collectively explain the observed second-order dependence on \(\mathrm{NO}_{2}(g)\) and highlight the decisive role played by the formation of the intermediate in dictating the overall reaction rate.

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Most popular questions from this chapter

A proposed mechanism for the formation of \(\mathrm{N}_{2} \mathrm{O}_{5}(g)\) from \(\mathrm{NO}_{2}(g)\) and \(\mathrm{O}_{3}(g)\) is \\[ \begin{array}{c} \mathrm{NO}_{2}(g)+\mathrm{O}_{3}(g) \stackrel{k_{1}}{\longrightarrow} \mathrm{NO}_{3}(g)+\mathrm{O}_{2}(g) \\ \mathrm{NO}_{2}(g)+\mathrm{NO}_{3}(g)+\mathrm{M}(g) \stackrel{k_{2}}{\longrightarrow} \mathrm{N}_{2} \mathrm{O}_{5}(g)+\mathrm{M}(g) \end{array} \\] Determine the rate law expression for the production of \(\mathrm{N}_{2} \mathrm{O}_{5}(g)\) given this mechanism.

Another type of autocatalytic reaction is referred to as cubic autocatalytic corresponding to the following elementary process: \\[ A+2 B \rightarrow 3 B \\] Write the rate law expression for this elementary process. What would you expect the corresponding differential rate expression in terms of \(\xi(\) the coefficient of reaction advancement) to be?

One complication when using FRET is that fluctuations in the local environment can affect the \(\mathrm{S}_{0}-\mathrm{S}_{1}\) energy gap for the donor or acceptor. Explain how this fluctuation would impact a FRET experiment.

The hydrogen-bromine reaction corresponds to the production of \(\operatorname{HBr}(g)\) from \(\mathrm{H}_{2}(g)\) and \(\mathrm{Br}_{2}(g)\) as follows: \(\mathrm{H}_{2}(g)+\operatorname{Br}_{2}(g) \rightleftharpoons 2 \mathrm{HBr}(g) .\) This reaction is famous for its complex rate law, determined by Bodenstein and Lind in 1906: \\[ \frac{d[\mathrm{HBr}]}{d t}=\frac{k\left[\mathrm{H}_{2}\right]\left[\mathrm{Br}_{2}\right]^{1 / 2}}{1+\frac{m[\mathrm{HBr}]}{\left[\mathrm{Br}_{2}\right]}} \\] where \(k\) and \(m\) are constants. It took 13 years for a likely mechanism of this reaction to be proposed, and this feat was accomplished simultaneously by Christiansen, Herzfeld, and Polyani. The mechanism is as follows: \\[ \begin{array}{l} \operatorname{Br}_{2}(g) \stackrel{k_{1}}{\sum_{k_{-1}}} 2 \operatorname{Br} \cdot(g) \\ \text { Br' }(g)+\mathrm{H}_{2}(g) \stackrel{k_{2}}{\longrightarrow} \operatorname{HBr}(g)+\mathrm{H} \cdot(g) \\ \text { H\cdot }(g)+\operatorname{Br}_{2}(g) \stackrel{k_{3}}{\longrightarrow} \operatorname{HBr}(g)+\operatorname{Br} \cdot(g) \\ \operatorname{HBr}(g)+\mathrm{H} \cdot(g) \stackrel{k_{4}}{\longrightarrow} \mathrm{H}_{2}(g)+\operatorname{Br} \cdot(g) \end{array} \\] Construct the rate law expression for the hydrogen-bromine reaction by performing the following steps: a. Write down the differential rate expression for \([\mathrm{HBr}]\) b. Write down the differential rate expressions for \([\mathrm{Br} \cdot]\) and [H']. c. Because \(\mathrm{Br} \cdot(g)\) and \(\mathrm{H} \cdot(g)\) are reaction intermediates, apply the steady-state approximation to the result of part (b). d. Add the two equations from part (c) to determine [Br'] in terms of \(\left[\mathrm{Br}_{2}\right]\) e. Substitute the expression for \([\mathrm{Br} \cdot]\) back into the equation for \([\mathrm{H} \cdot]\) derived in part \((\mathrm{c})\) and solve for \([\mathrm{H} \cdot]\) f. Substitute the expressions for \([\mathrm{Br} \cdot]\) and \([\mathrm{H} \cdot]\) determined in part (e) into the differential rate expression for \([\mathrm{HBr}]\) to derive the rate law expression for the reaction.

Using the preequilibrium approximation, derive the predicted rate law expression for the following mechanism: $$\begin{array}{l} \mathrm{A}_{2} \stackrel{k_{1}}{=} 2 \mathrm{A} \\ \mathrm{A}+\mathrm{B} \stackrel{k_{2}}{\longrightarrow} \mathrm{P} \end{array}$$

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