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An advertisement for a thermopane window company touts Kr-filled windows and states that these windows provide ten times better insulation than conventional windows filled with Ar. Do you agree with this statement? What should the ratio of thermal conductivities be for \(\mathrm{Kr}\left(\sigma=0.52 \mathrm{nm}^{2}\right)\) versus \(\operatorname{Ar}\left(\sigma=0.36 \mathrm{nm}^{2}\right) ?\)

Short Answer

Expert verified
The claim that Kr-filled windows provide ten times better insulation than Ar-filled windows is not accurate. By comparing their thermal conductivities using the given collision cross-section values, we find that the ratio \(k_{\mathrm{Kr}}/k_{\mathrm{Ar}}\) is approximately 0.692. This indicates that Kr-filled windows only provide moderately better insulation compared to Ar-filled windows rather than ten times better.

Step by step solution

01

Recap thermal conductivity formula

To determine the ratio of thermal conductivities, recall that the thermal conductivity of gases is proportional to the inverse of their collision cross-section (\(\sigma\)). The formula for thermal conductivity is: \[\frac{k_{1}}{k_{2}} = \frac{\sigma_{2}}{\sigma_{1}}\] Here \(k_1\) and \(k_2\) are the thermal conductivities of the two gases, and \(\sigma_1\) and \(\sigma_2\) are their collision cross-sections.
02

Insert the given values

We are given the collision cross-sections for Kr and Ar: \(\sigma_{\mathrm{Kr}}=0.52 \, \mathrm{nm}^2\) and \(\sigma_{\mathrm{Ar}}=0.36 \, \mathrm{nm}^2\). Plug in these values into the thermal conductivity formula from Step 1. \[\frac{k_{\mathrm{Kr}}}{k_{\mathrm{Ar}}} = \frac{\sigma_{\mathrm{Ar}}}{\sigma_{\mathrm{Kr}}} = \frac{0.36 \, \mathrm{nm}^2}{0.52 \, \mathrm{nm}^2}\]
03

Compute the ratio

Now, we divide the collision cross-section of Ar by the collision cross-section of Kr to find the ratio of their thermal conductivities. \[\frac{k_{\mathrm{Kr}}}{k_{\mathrm{Ar}}} = \frac{0.36 \, \mathrm{nm}^2}{0.52 \, \mathrm{nm}^2} \approx 0.692\]
04

Compare the result to the claim

Given the result in Step 3, it is easy to see that \(0.692 \neq 10\). The given claim that Kr-filled windows provide ten times better insulation than conventional Ar-filled windows is not true based on the provided collision cross-section values. The actual ratio of thermal conductivities shows that Kr-filled windows are only moderately better in insulation compared to Ar-filled windows.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Collision Cross-Section
The collision cross-section is a crucial concept when discussing the thermal properties of gases. It refers to the area a molecule presents as a target for collisions with other molecules. This is typically expressed in square nanometers, and it influences how frequently gas molecules bump into one another. Understanding collision cross-sections is simplified by considering that a larger cross-section means more interaction between molecules, while a smaller cross-section results in less interaction. This property is vital in calculating thermal conductivity, as it directly affects how well or poorly heat is transferred through a gas. To put it simply, a smaller cross-section usually means the gas is more effective at insulating, as fewer molecular collisions happen to facilitate heat transfer. Thus, knowing the collision cross-section value helps in predicting the gas's thermal conductivity.
Krypton vs Argon Insulation
The insulation properties of a gas are linked to its thermal conductivity, which is influenced by the gas's collision cross-section. In analyzing Kr versus Ar for window insulation, we must consider these values: Krypton has a cross-section of 0.52 nm² while Argon stands at 0.36 nm². When comparing the two gases, Krypton has a larger collision cross-section, meaning it is less effective at insulating compared to Argon in terms of reducing heat transfer. This parameter essentially dictates how well a gas can slow down the movement of heat from one side of the window to the other. The belief that Kr-filled windows provide ten times better insulation than Ar-filled windows fails to consider the actual thermal conductivity calculation. The numerical result from the ratio of cross-sections gives a much smaller factor, indicating only a slight improvement with Krypton over Argon for insulation purposes.
Gas Thermal Conductivity Comparison
Thermal conductivity is a measure of a material’s ability to conduct heat. In gases like Krypton and Argon, thermal conductivity is inversely proportional to their collision cross-sections. This means gases with larger cross-sections, like Krypton, tend to be poorer conductors of heat, whereas gases with smaller cross-sections, like Argon, allow for quicker heat transfer.We calculate the thermal conductivity ratio using the formula \(\frac{k_{1}}{k_{2}} = \frac{\sigma_{2}}{\sigma_{1}}\). For Krypton and Argon:
  • \(\sigma_{\text{Kr}} = 0.52\,\text{nm}^{2}\)
  • \(\sigma_{\text{Ar}} = 0.36\,\text{nm}^{2}\)
Plug these into our formula: \[\frac{k_{\text{Kr}}}{k_{\text{Ar}}} = \frac{0.36\,\text{nm}^{2}}{0.52\,\text{nm}^{2}} \approx 0.692\]This reveals that Krypton's thermal conductivity is about 0.692 times that of Argon, debunking the claim of it being tenfold better. Thus, the selection between these gases for insulation involves careful balancing of cross-section versus desired level of thermal conductivity.

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Most popular questions from this chapter

The thermal conductivity of Kr is roughly half that of Ar under identical pressure and temperature conditions. Both gases are monatomic such that \(C_{V, m}=3 / 2 R\) a. Why would one expect the thermal conductivity of Kr to be less than that of Ar? b. Determine the ratio of collisional cross sections for Ar relative to Kr assuming identical pressure and temperature conditions. c. For \(\mathrm{Kr}\) at \(273 \mathrm{K}\) at \(1 \mathrm{atm}, \kappa=0.0087 \mathrm{J} \mathrm{K}^{-1} \mathrm{m}^{-1} \mathrm{s}^{-1}\) Determine the collisional cross section of Kr.

A current of 2.00 A is applied to a metal wire for 30. s. How many electrons pass through a given point in the wire during this time?

The Reynolds' number (Re) is defined as \(\mathrm{Re}=\rho\left\langle\mathrm{v}_{x}\right\rangle d / \eta,\) where \(\rho\) and \(\eta\) are the fluid density and viscosity, respectively; \(d\) is the diameter of the tube through which the fluid is flowing; and \(\left\langle\mathrm{v}_{x}\right\rangle\) is the average velocity. Laminar flow occurs when \(\operatorname{Re}<2000\), the limit in which the equations for gas viscosity were derived in this chapter. Turbulent flow occurs when \(\mathrm{Re}>2000 .\) For the following species, determine the maximum value of \(\left\langle\mathrm{v}_{x}\right\rangle\) for which laminar flow will occur: a. \(\mathrm{Ne}\) at \(293 \mathrm{K}(\eta=313 \mu \mathrm{P}, \rho=\) that of an ideal gas) through a 2.00 -mm-diameter pipe. b. Liquid water at \(293 \mathrm{K}\left(\eta=0.891 \mathrm{cP}, \rho=0.998 \mathrm{g} \mathrm{mL}^{-1}\right)\) through a 2.00 -mm-diameter pipe.

Two parallel metal plates separated by \(1 \mathrm{cm}\) are held at \(300 .\) and \(298 \mathrm{K}\), respectively. The space between the plates is filled with \(\mathrm{N}_{2}\left(\sigma=0.430 \mathrm{nm}^{2} \text { and } C_{V, m}=5 / 2 R\right)\) Determine the heat flux between the two plates in units of \(\mathrm{W} \mathrm{cm}^{-2}\)

Boundary centrifugation is performed at an angular velocity of 40,000 rpm to determine the sedimentation coefficient of cytochrome \(c\left(M=13,400 \mathrm{g} \mathrm{mol}^{-1}\right)\) in water at \(20^{\circ} \mathrm{C}\left(\rho=0.998 \mathrm{g} \mathrm{cm}^{-3}, \eta=1.002 \mathrm{cP}\right) .\) The following data are obtained on the position of the boundary layer as a function of time: $$\begin{array}{cc}\text { Time (h) } & x_{b}(\mathrm{cm}) \\\\\hline 0 & 4.00 \\\2.5 & 4.11 \\\5.2 & 4.23 \\\12.3 & 4.57 \\\19.1 & 4.91\end{array}$$ a. What is the sedimentation coefficient for cytochrome \(c\) under these conditions? b. The specific volume of cytochrome \(c\) is \(0.728 \mathrm{cm}^{3} \mathrm{g}^{-1}\) Estimate the size of cytochrome \(c\)

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