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Calculate the rotational partition function for CINO at \(500 .\) K where \(B_{A}=2.84 \mathrm{cm}^{-1}, B_{B}=0.187 \mathrm{cm}^{-1}\) and \(B_{C}=0.175 \mathrm{cm}^{-1}\)

Short Answer

Expert verified
The rotational partition function for CINO at 500 K, given the rotational constants \(B_{A}=2.84 \mathrm{cm}^{-1}, B_{B}=0.187 \mathrm{cm}^{-1}\) and \(B_{C}=0.175 \mathrm{cm}^{-1}\), is approximately 39589.6.

Step by step solution

01

Identify the constants and given values

We are given the following values: - Temperature T = 500 K - Rotational constants B_A = 2.84 cm鈦宦, B_B = 0.187 cm鈦宦, B_C = 0.175 cm鈦宦 We will also use the following constants: - Planck's constant h = 6.626 脳 10鈦宦斥伌 Js - Speed of light c = 2.998 脳 10鹿鈦 cm/s - Boltzmann constant k_B = 1.381 脳 10鈦宦猜 J/K For CINO, the symmetry number 蟽 is equal to 1 because it is a nonlinear molecule.
02

Convert the rotational constants to SI units

The rotational constants are given in wavenumber units (cm鈦宦), so we need to convert them to SI units (J) using the following formula: \[B = hc\tilde{B}\] where B is the rotational constant in J, and \(\tilde{B}\) is the rotational constant in wavenumber units (cm鈦宦). Using the given values of the rotational constants and the constants h and c, we get: - B_A = (6.626 脳 10鈦宦斥伌 Js) 脳 (2.998 脳 10鹿鈦 cm/s) 脳 (2.84 cm鈦宦) = 5.36 脳 10鈦宦猜 J - B_B = (6.626 脳 10鈦宦斥伌 Js) 脳 (2.998 脳 10鹿鈦 cm/s) 脳 (0.187 cm鈦宦) = 3.52 脳 10鈦宦猜 J - B_C = (6.626 脳 10鈦宦斥伌 Js) 脳 (2.998 脳 10鹿鈦 cm/s) 脳 (0.175 cm鈦宦) = 3.30 脳 10鈦宦猜 J
03

Calculate the rotational partition function for CINO

Using the expression for the rotational partition function for a nonlinear molecule: \(q_{rot} = \frac{\pi^{1/2}}{1} \left(\frac{hc}{k_{B}T}\right)^{-3/2} (\frac{1}{B_{A}}\frac{1}{B_{B}}\frac{1}{B_{C}})^{1/2}\) we substitute the given and calculated values: \(q_{rot} = \frac{\pi^{1/2}}{1} \left(\frac{6.626 \times 10^{-34} \text{Js} \cdot 2.998 \times 10^{10} \text{cm/s}}{1.381 \times 10^{-23} \text{J/K} \cdot 500 \text{K}}\right)^{-3/2} (\frac{1}{5.36 \times 10^{-22} \text{J}}\frac{1}{3.52 \times 10^{-23} \text{J}}\frac{1}{3.30 \times 10^{-23} \text{J}})^{1/2}\) After evaluating the expression: \(q_{rot} \approx 39589.6\) #Phase2Solution# The rotational partition function for CINO at 500 K is approximately 39589.6.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Constants
Rotational constants are crucial in determining the rotational energy levels of molecules. These constants, denoted as \(B_A\), \(B_B\), and \(B_C\), characterize the rotational inertia of the molecule along different principal axes. They are measured in units of wavenumbers (cm鈦宦) and give insight into the geometry and internal structure of the molecule.
To convert these constants into the energy units of joules (J), you can use the formula \( B = hc\tilde{B} \), where \(h\) is Planck's constant and \(c\) is the speed of light. In our example, we converted the given rotational constants into joules to facilitate further thermodynamic calculations. Understanding rotational constants allows us to predict how a molecule will behave when exposed to thermal energy.
Nonlinear Molecules
Nonlinear molecules, such as the chloroiodomethane (CINO) molecule in our example, have a more complex rotational behavior compared to linear molecules. They possess three unique axes of rotation, leading to three distinct rotational constants \(B_A\), \(B_B\), and \(B_C\).
One unique property of nonlinear molecules is their symmetry number \(\sigma\). This number accounts for identical configurations through rotational symmetry. In CINO's case, the symmetry number is \(1\) because it has no axis aligning with symmetrically equivalent arrangements. Understanding the concept of nonlinear molecules is vital for accurately calculating the rotational partition function, as it differs from that of purely linear structures.
Boltzmann Constant
The Boltzmann constant \(k_B\) bridges small-scale physical energy scales with macroscopic temperature measurement. It is a fundamental constant in statistical mechanics, with a value of approximately \(1.381 \times 10^{-23} \, \text{J/K}\).
In the calculation of partition functions, including the rotational partition function, the Boltzmann constant is used in evaluating thermal energy availability per molecule at a specific temperature. It serves as a key parameter to express the relationship between the microscopic and macroscopic aspects of thermodynamic systems. In the solution, \(k_B\) helps convert quantum mechanical concepts into measurable temperature effects.
Partition Function
The partition function is a central concept in thermodynamics and statistical mechanics, representing a statistical sum over all possible energy states a system can occupy. In the context of rotations for molecules like CINO, the rotational partition function \(q_{rot}\) helps determine the distribution of energy states at a given temperature.
The formula for the rotational partition function for a nonlinear molecule integrates the rotational constants and temperature to provide the probability distribution among rotational states. For CINO at 500 K, \(q_{rot}\) equals approximately 39589.6, indicating a broad distribution over rotational energy states due to sufficient thermal energy. Partition functions ultimately allow us to predict molecular behavior in broader thermodynamic contexts, showing how molecules store and exchange energy.

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Most popular questions from this chapter

Evaluate the translational partition function for \(\mathrm{H}_{2}\) confined to a volume of \(100 . \mathrm{cm}^{3}\) at \(298 \mathrm{K}\). Perform the same calculation for \(\mathrm{N}_{2}\) under identical conditions. (Hint: Do you need to reevaluate the full expression for \(q_{T} ?\) )

Calculate the rotational partition function for the interhalogen compound \(\mathrm{F}^{35} \mathrm{Cl}\left(B=0.516 \mathrm{cm}^{-1}\right)\) at \(298 \mathrm{K}\).

NO is a well-known example of a molecular system in which excited electronic energy levels are readily accessible at room temperature. Both the ground and excited electronic states are doubly degenerate and are separated by \(121.1 \mathrm{cm}^{-1}\) a. Evaluate the electronic partition function for this molecule at \(298 \mathrm{K}\) b. Determine the temperature at which \(q_{E}=3\)

Evaluate the electronic partition function for atomic Fe at \(298 \mathrm{K}\) given the following energy levels. $$\begin{array}{ccc} \text { Level }(\boldsymbol{n}) & \text { Energy }\left(\mathrm{cm}^{-1}\right) & \text {Degeneracy } \\ \hline 0 & 0 & 9 \\ 1 & 415.9 & 7 \\ 2 & 704.0 & 5 \\ 3 & 888.1 & 3 \\ 4 & 978.1 & 1 \end{array}$$

The effect of symmetry on the rotational partition function for \(\mathrm{H}_{2}\) was evaluated by recognizing that each hydrogen is a spin \(1 / 2\) particle and is, therefore, a fermion. However, this development is not limited to fermions, but is also applicable to bosons. Consider \(\mathrm{CO}_{2}\) in which rotation by \(180^{\circ}\) results in the interchange of two spin 0 particles. a. Because the overall wave function describing the interchange of two bosons must be symmetric with respect to exchange, to what \(J\) levels is the summation limited in evaluating \(q_{R}\) for \(\mathrm{CO}_{2} ?\) b. The rotational constant for \(\mathrm{CO}_{2}\) is \(0.390 \mathrm{cm}^{-1}\). Calculate \(q_{R}\) at \(298 \mathrm{K} .\) Do you have to evaluate \(q_{R}\) by summation of the allowed rotational energy levels? Why or why not?

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