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An initial step in the biosynthesis of glucose \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}\) is the carboxylation of pyruvic acid \(\mathrm{CH}_{3} \mathrm{COCOOH}\) to form oxaloacetic acid HOOCCOCH \(_{2} \mathrm{COOH}\) \\[ \mathrm{CH}_{3} \mathrm{COCOOH}(s)+\mathrm{CO}_{2}(g) \rightarrow \mathrm{HOOCCOCH}_{2} \mathrm{COOH}(s) \\] If you knew nothing else about the intervening reactions involved in glucose biosynthesis other than no further carboxylations occur, what volume of \(\mathrm{CO}_{2}\), is required to produce \(1.10 \mathrm{g}\) of glucose? Assume \(P=1\) atm and \(T=298 \mathrm{K}\).

Short Answer

Expert verified
To produce 1.10 g of glucose, first convert the mass of glucose to moles (1.10 g / 180.18 g/mol). It takes two moles of CO2 to produce one mole of glucose. Calculate the moles of CO2 required, and using the ideal gas law (PV = nRT), find the volume of CO2 at 1 atm and 298 K.

Step by step solution

01

Convert the mass of glucose to moles

We begin by converting the given mass of glucose (1.10 g) into moles using its molar mass. The molar mass of glucose is \(C_6H_{12}O_6 = 6(12.01)+12(1.01)+6(16.00)\) g/mol. Moles of glucose = \(\frac{1.10 \: \text{g}}{180.18 \: \text{g/mol}}\) Calculate the number of moles for glucose.
02

Determine the stoichiometry of carbon dioxide in relation to glucose

From the balanced equation of the given reaction, we know that one mole of pyruvic acid reacts with one mole of CO2 to form one mole of oxaloacetic acid. However, if no further carboxylations occur in the biosynthesis of glucose, we can assume that all of the carbon atoms in glucose came from pyruvic acid. Thus, we can determine the stoichiometry. Glucose has 6 carbon atoms, and one pyruvic acid molecule has 3 carbon atoms. Therefore, two moles of pyruvic acid and two moles of CO2 will combine to form one mole of glucose.
03

Calculate the moles of carbon dioxide required

Now that we understand the stoichiometry, we can calculate the moles of carbon dioxide needed to produce the given amount of glucose. Moles of CO2 = \(2 \times\) moles of glucose Calculate the number of moles for carbon dioxide.
04

Use the ideal gas law to find the volume of carbon dioxide

Finally, we will use the ideal gas law, PV = nRT, to find the volume of CO2: P = Pressure = 1 atm n = Moles of CO2 (calculated in step 3) R = Ideal gas constant = 0.0821 L atm/mol K T = Temperature = 298 K Rearrange the ideal gas law to solve for V: V = \(\frac{nRT}{P}\) Plug in the values and calculate the volume of CO2 required to produce 1.10 g of glucose.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carboxylation
Carboxylation is a chemical reaction where a carboxyl group (-COOH) is added to a compound. This process is crucial in the biosynthesis of glucose. In the context of our problem, carboxylation involves converting pyruvic acid into oxaloacetic acid by introducing a carbon dioxide molecule.

This reaction is significant because it adds extra carbon atoms to the molecule, which are later needed to build glucose. In biosynthetic pathways such as gluconeogenesis, carboxylation is often a key step that helps regulate the flow of carbon, ensuring molecules are synthesized in the amount needed by the cell. Carboxylation relies on the presence of enzymes to facilitate this reaction under mild conditions, showing the sophistication of cellular chemistry.
Ideal Gas Law
The ideal gas law is an equation of state for a hypothetical gas, illustrating the relationship among pressure (P), volume (V), temperature (T), and moles of gas (n). The formula is expressed as: \[ PV = nRT \]where R is the ideal gas constant.

This law is instrumental in our glucose biosynthesis problem because it allows us to determine the volume of carbon dioxide gas needed when we have the values for the other variables. By rearranging the formula to solve for volume \( V \), we can find how much space the CO2 will occupy. The ideal gas law assumes that the gas molecules do not interact beyond collision, which simplifies many calculations in chemistry.
Stoichiometry
Stoichiometry involves the calculation of reactants and products in a chemical reaction. It is based on the principle that in a chemical reaction, matter is conserved. This means the amounts of each chemical element are kept equal on both sides of the equation.

In the context of glucose biosynthesis, stoichiometry helps us understand how many molecules of carbon dioxide are needed for a specific amount of glucose. Since each molecule of glucose has six carbon atoms, and each pyruvic acid provides three of them, stoichiometry shows us that two molecules of pyruvic acid and therefore two molecules of carbon dioxide are required to synthesize one molecule of glucose. By learning stoichiometry, one can predict the quantities of materials consumed and produced in a given reaction.
Pyruvic Acid
Pyruvic acid is an organic acid and a key intermediate in several metabolic pathways. Its chemical formula is \( CH_3COCOOH \). Pyruvic acid can convert to various substances within the cell, playing a fundamental role in metabolic processes like glycolysis and gluconeogenesis.

In glycolysis, glucose is broken down to form pyruvic acid, which can then enter the citric acid cycle or be converted to lactate in anaerobic conditions. In gluconeogenesis, it serves as a starting material for the carboxylation reaction forming oxaloacetic acid. Its ability to rapidly change functions based on cellular needs makes pyruvic acid vital for metabolism.
Oxaloacetic Acid
Oxaloacetic acid is a four-carbon compound with the formula \( HOOCCOCH_2COOH \). It plays a central role in the citric acid cycle, providing energy through cellular respiration. In the gluconeogenesis pathway, it is produced by the carboxylation of pyruvic acid, making it essential in the formation of glucose.

Oxaloacetic acid facilitates the biosynthesis of glucose by providing a carbon skeleton that can be transformed into glucose molecules. This compound not only aids in energy production but also in the storage of energy in the form of glucose. Thus, understanding its role can help clarify the intricacies of cellular metabolism and energy management.

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Most popular questions from this chapter

Calculate the pressure exerted by Ar for a molar volume of \(1.31 \mathrm{L} \mathrm{mol}^{-1}\) at \(426 \mathrm{K}\) using the van der Waals equation of state, The van der Waals parameters \(a\) and \(b\) for Ar are 1.355 bar \(\mathrm{dm}^{6} \mathrm{mol}^{-2}\) and \(0.0320 \mathrm{dm}^{3} \mathrm{mol}^{-1},\) respectively. Is the attractive or repulsive portion of the potential dominant under these conditions?

A sample of propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) is placed in a closed ves sel together with an amount of \(\mathrm{O}_{2}\) that is 2.15 times the amount needed to completely oxidize the propane to \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) at constant temperature. Calculate the mole fraction of each component in the resulting mixture after oxidation, assuming that the \(\mathrm{H}_{2} \mathrm{O}\) is present as a gas.

One liter of fully oxygenated blood can carry 0.18 liters of \(\mathrm{O}_{2}\) measured at \(T=298 \mathrm{K}\) and \(P=1.00 \mathrm{atm}\) Calculate the number of moles of \(\mathrm{O}_{2}\) carried per liter of blood. Hemoglobin, the oxygen transport protein in blood has four oxygen binding sites. How many hemoglobin molecules are required to transport the \(\mathrm{O}_{2}\) in \(1.0 \mathrm{L}\) of fully oxygenated blood?

A balloon filled with 11.50 L of Ar at \(18.7^{\circ} \mathrm{C}\) and 1 atm rises to a height in the atmosphere where the pressure is 207 Torr and the temperature is \(-32.4^{\circ} \mathrm{C}\). What is the final volume of the balloon? Assume that the pressure inside and outside the balloon have the same value.

Consider a \(31.0 \mathrm{L}\) sample of moist air at \(60 .^{\circ} \mathrm{C}\) and one atm in which the partial pressure of water vapor is 0.131 atm. Assume that dry air has the composition 78.0 mole percent \(\mathrm{N}_{2}, 21.0\) mole percent \(\mathrm{O}_{2},\) and 1.00 mole percent Ar. a. What are the mole percentages of each of the gases in the sample? b. The percent relative humidity is defined as \(\% \mathrm{RH}=\) \(P_{H_{2}} o / P_{H_{2} O}^{*}\) where \(P_{H_{2}, O}\) is the partial pressure of water in the sample and \(P_{H, O}^{*}=0.197\) atm is the equilibrium vapor pressure of water at \(60 .^{\circ} \mathrm{C}\). The gas is compressed at \(60 .^{\circ} \mathrm{C}\) until the relative humidity is \(100 . \% .\) What volume does the mixture contain now? c. What fraction of the water will be condensed if the total pressure of the mixture is isothermally increased to 81.0 atm?

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