Chapter 8: Problem 60
Determine ionic strengths for the following solutions. Assume that they are \(100 \%\) ionized. (a) \(0.0055\) molal \(\mathrm{HCl}\), (b) \(0.075\) molal \(\mathrm{NaHCO}_{3}\), (c) \(0.0250\) molal \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2 r}\) (d) \(0.0250 \mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\)
Short Answer
Step by step solution
Understand Ionic Strength Formula
Calculate Ionic Strength for HCl (0.0055 molal)
Calculate Ionic Strength for NaHCO3 (0.075 molal)
Calculate Ionic Strength for Fe(NO3)2 (0.0250 molal)
Calculate Ionic Strength for Fe(NO3)3 (0.0250 molal)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
HCl dissociation
- **Ion Charges**: Both \(H^+\) and \(Cl^-\) have a charge of 1. So, in calculating the ionic strength of an HCl solution, we consider the contribution of each ion with their respective charges squared.- **Ionic Strength Formula**: Use the formula \( I = \frac{1}{2} \sum c_i z_i^2 \) where \(c_i\) and \(z_i\) are the concentration and charge of ion \(i\), respectively.
To find the ionic strength of a 0.0055 molal HCl solution, plug in the values to get \( I = \frac{1}{2} \times (0.0055 \times 1^2 + 0.0055 \times 1^2) = 0.0055 \). This reflects the concentration of ions and their charges in the solution.
NaHCO3 dissociation
- **Ion Characteristics**: The \(Na^+\) ion has a positive charge of 1, and the \(HCO_3^-\) ion has a negative charge of 1. Both are monovalent ions.- **Dissociation Process**: This dissociation results in equal amounts of each ion, as the process involves breaking down the NaHCO3 entirely.
To calculate the ionic strength of a 0.075 molal NaHCO3 solution, use \( I = \frac{1}{2} \times (0.075 \times 1^2 + 0.075 \times 1^2) = 0.075 \). Each ion contributes equally, reflecting the full dissociation and ion distribution in solution.
Fe(NO3)2 dissociation
- **Ion Charges**: The \(Fe^{2+}\) ion carries a charge of +2, while each \(NO_3^-\) ion has a charge of -1.- **Contribution to Ionic Strength**: The charge of the ions affects the ionic strength significantly. Each \(Fe^{2+}\) ion has a squared charge contribution of 4 due to its +2 charge, magnifying its impact on the ionic strength.
For a 0.0250 molal solution of \(Fe(NO_3)_2\), calculate as follows: \( I = \frac{1}{2} [(0.025 \times 2^2) + 2(0.025 \times 1^2)] = 0.075 \). The formula shows how both the concentration and the charge of ions determine the overall ionic strength.
Fe(NO3)3 dissociation
- **Ion Charges**: The \(Fe^{3+}\) ion holds a triple positive charge (+3), while each nitrate ion holds a single negative charge (-1).- **Influence on Ionic Strength**: The high charge of \(Fe^{3+}\) greatly influences ionic strength because the contribution depends on charge squared (\(3^2 = 9\)). Nitrate's charges add up due to their count and impact the total ionic strength.
For a 0.0250 molal \(Fe(NO_3)_3\) solution, calculate: \( I = \frac{1}{2} [ 0.025 \times 3^2 + 3 \times 0.025 \times 1^2 ] = 0.15 \). This calculation clearly shows the significance of iron's higher charge in determining the ionic strength of the solution.