Chapter 18: Problem 58
The rotational temperature of molecular iodine is \(310 \mathrm{~K}\). Evaluate \(q_{\text {rot }}\) at \(T=298 \mathrm{~K}\) term by term, listing the cumulative value of \(q_{\text {rot }}\) for every term. At what number of terms does the change in \(q_{\text {rot }}\) become negligible? Repeat the evaluation for \(T=1000 \mathrm{~K}\).
Short Answer
Step by step solution
Understand the Rotational Partition Function
Evaluate the Terms at T = 298 K
Evaluate the Terms at T = 1000 K
Determine Negligible Contribution Point
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rotational Quantum Number
- Energy of a rotational level: \( E_J = \frac{J(J+1)\hbar^2}{2I} \)
- Here, \( \hbar \) is the reduced Planck's constant and \( I \) is the moment of inertia of the molecule.
Rotational Temperature
- \( \Theta_{\text{rot}} = \frac{\hbar^2}{2Ik} \)
Diatomic Molecules
- Common examples include hydrogen \((H_2)\), nitrogen \((N_2)\), and oxygen \((O_2)\).
- They have two degrees of freedom, which pertain to rotational motion.
Partition Function Evaluation
- \( q_{\text{rot}} = \sum_{J=0}^{\infty} (2J+1) e^{-\frac{J(J+1)\Theta_{\text{rot}}}{T}} \)