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Predict the major monoalkylation products you would expect to obtain from reaction of the following substances with chloromethane and \(\mathrm{AlCl}_{3}:\) (a) \(p\) -Chloroaniline (b) \(m\) -Bromophenol (c) 2,4-Dichlorophenol (d) 2,4 -Dichloronitrobenzene (e) \(p\) -Methylbenzenesulfonic acid (f) 2,5 -Dibromotoluene

Short Answer

Expert verified
The major products are: (a) o-methyl-p-chloroaniline, (b) o-methyl-m-bromophenol, (c) 3-methyl-2,4-dichlorophenol, (d) 3-methyl-2,4-dichloronitrobenzene, (e) o-methyl-p-methylbenzenesulfonic acid, and (f) 4-methyl-2,5-dibromotoluene.

Step by step solution

01

Understanding the Reaction

The reaction involves chloromethane and AlCl鈧, which is a Friedel-Crafts alkylation. This reaction allows for the introduction of an alkyl group onto an aromatic ring. The key to predicting the product is knowing the directing effects of substituents present on the aromatic ring. Activating groups (such as -OH, -狈贬鈧, -颁贬鈧) generally direct new substituents to the ortho or para positions, while deactivating groups (such as -狈翱鈧, -Cl, -COOH) typically direct them to meta positions.
02

Analyzing Compound (a): p-Chloroaniline

p-Chloroaniline has a -狈贬鈧 group which is a strong ortho/para-directing, activating group, and a -Cl group which is a weak ortho/para-directing, deactivating group. In this scenario, the -狈贬鈧 group predominates effect. Therefore, methylation is likely to occur at the ortho position relative to the -狈贬鈧 group, since the para position is blocked by -Cl.
03

Analyzing Compound (b): m-Bromophenol

m-Bromophenol has an -OH group which is ortho/para-directing and activating, while the -Br is ortho/para-directing but deactivating. Given that the -Br is already on the meta position, the -OH group will direct the incoming methyl group to the ortho position with respect to itself, leading to ortho-methyl placement.
04

Analyzing Compound (c): 2,4-Dichlorophenol

With both -Cl groups being ortho/para-directing deactivators and one -OH which is an ortho/para-directing activator, the -OH group predominates. The most reactive site for methylation will be the ortho position to the -OH which is not already blocked by -Cl, thus the product is likely to have methyl at the 3-position.
05

Analyzing Compound (d): 2,4-Dichloronitrobenzene

2,4-Dichloronitrobenzene has two ortho/para-directing deactivators (-Cl) and a meta-directing deactivating group (-狈翱鈧). The strongest effect is from the -狈翱鈧 group which pushes substitution to the position only meta to it and para to one -Cl, which is the 3-position on the ring.
06

Analyzing Compound (e): p-Methylbenzenesulfonic Acid

p-Methylbenzenesulfonic acid contains a p-tolyl group (-颁贬鈧) which is ortho/para-directing and activating, and a -厂翱鈧仅 group which is meta-directing and strongly deactivating. The -颁贬鈧's activating nature dominates, and the methyl will be placed at the ortho position relative to the -颁贬鈧 group since the para position is occupied by the -厂翱鈧仅.
07

Analyzing Compound (f): 2,5-Dibromotoluene

Here, the methyl group is ortho/para-directing and activating, and each bromine is ortho/para-directing but deactivating. The methyl group pushes substitution primarily at its adjacent positions. Therefore, the most likely site for methylation is the ortho position relative to the methyl, leading to methyl placement at 4-position.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Directing Effects
The concept of "directing effects" is critical when predicting the result of electrophilic aromatic substitution reactions like Friedel-Crafts alkylation. Substituents attached to an aromatic ring can influence the position where new substituents will be added. This is known as their directing effect.
Substituents fall into two main categories based on how they influence substituent positioning:
  • Ortho/Para Directors: These groups direct new groups to the ortho (adjacent) and para (opposite) positions relative to themselves. They operate via electron donation through resonance or hyperconjugation and are often activating groups. For example: -OH, -狈贬鈧, and -颁贬鈧.
  • Meta Directors: These groups direct incoming substituents to the meta position, or two positions away on the ring. They typically withdraw electrons, stabilizing the meta-substituted intermediates. Examples include -狈翱鈧, -CN, and -COOH.
Knowing the directing effect of existing substituents helps chemists predict the major product in such reactions.
Activating and Deactivating Groups
In the realm of aromatic chemistry, understanding the difference between activating and deactivating groups is crucial. These groups influence how easily an aromatic compound undergoes substitution reactions.

Activating Groups

Activating groups increase the reactivity of the aromatic ring. They make it more amenable to electrophilic substitution by donating electrons, often through resonance. This makes the ring more nucleophilic, attracting electrophiles. Common activating groups include:
  • -OH
  • -狈贬鈧
  • -颁贬鈧
These groups lead to faster reactions and major products at the ortho and para positions.

Deactivating Groups

In contrast, deactivating groups reduce the reactivity of the ring toward electrophilic substitution. They withdraw electron density from the ring, making it less nucleophilic. As a result, such rings are less reactive. Deactivating groups typically favor meta substitution. Examples include:
  • -狈翱鈧
  • -厂翱鈧仅
  • -COOH
They slow down reactions but play a crucial role in dictating the position of substitution.
Aromatic Substitution
Aromatic substitution refers to a process where an atom on an aromatic ring, typically hydrogen, is replaced by another atom or group of atoms.
  • Electrophilic Aromatic Substitution (EAS): In this type, an electrophile replaces a hydrogen on the aromatic ring. It usually involves a catalyst to help generate a strong electrophile. This includes nitration, sulfonation, halogenation, and Friedel-Crafts alkylation/acylation.
  • Nucleophilic Aromatic Substitution (NAS): Less common, occurring mostly in significantly deactivated aromatic rings. In NAS, a nucleophile replaces a leaving group like a halogen.
In Friedel-Crafts reactions, the aromatic ring acts as a nucleophile, reacting with an electrophile to introduce an alkyl or acyl group, significantly changing the organic molecule's properties. Aromatic substitution is foundational in the synthesis of thousands of compounds.
Chloromethane and AlCl鈧 Reaction
The Friedel-Crafts alkylation using chloromethane ( CH鈧僀l) and aluminum chloride (AlCl鈧) is a classic example of aromatic substitution. AlCl鈧 acts as a catalyst, facilitating the formation of a powerful electrophile from chloromethane.

The Reaction Mechanism

1. **Formation of Electrophile:** The non-bonding electron pair on chlorine in chloromethane is attracted to AlCl鈧, creating a complex. This interaction generates a carbocation (CH鈧冣伜), which is a highly reactive electrophile. 2. **Electrophilic Attack:** The aromatic benzene ring, acting as a nucleophile, attacks this carbocation, forming a sigma complex. 3. **Rearrangement:** The aromaticity of the ring is temporarily lost. To regain aromaticity, a proton is lost, often with the help of the AlCl鈧勨伝 anion, frequently regenerating AlCl鈧 in the process.
Using chloromethane and AlCl鈧 for Friedel-Crafts alkylation allows chemists to introduce a methyl group to an aromatic ring effectively, highlighting the powerful nature of electrophilic aromatic substitutions.

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