Chapter 6: Problem 11
Which reaction is likely to be more exergonic, one with \(K_{\mathrm{eq}}=1000\) or one with \(K_{\mathrm{eq}}=0.001 ?\)
Short Answer
Expert verified
The reaction with \(K_{\mathrm{eq}} = 1000\) is more exergonic.
Step by step solution
01
Understanding Exergonic Reactions
Exergonic reactions are characterized by the release of energy. The term "exergonic" indicates that the reaction proceeds with a net release of free energy.
02
The Relationship Between Keq and Free Energy
The relationship between the equilibrium constant (
K_{ ext{eq}}
) and the Gibbs free energy change (
ext{ΔG}^ ext{°}
) for a reaction is given by the equation:
ext{ΔG}^ ext{°} = -RT imes ext{ln}(K_{ ext{eq}})
. Here,
R
is the universal gas constant, and
T
is the temperature in Kelvin.
03
Analyzing Reaction with Keq = 1000
Using the equation,
ext{ΔG}^ ext{°}_{1} = -RT imes ext{ln}(1000)
. The natural logarithm of 1000 is positive, so
ext{ΔG}^ ext{°}_{1}
will be negative, indicating an exergonic reaction.
04
Analyzing Reaction with Keq = 0.001
For this reaction, use the equation
ext{ΔG}^ ext{°}_{2} = -RT imes ext{ln}(0.001)
. The natural logarithm of 0.001 is negative, leading to a positive
ext{ΔG}^ ext{°}_{2}
, which indicates an endergonic reaction.
05
Comparing ΔG° Values
A negative
ext{ΔG}^ ext{°}
indicates an exergonic (spontaneous) process. Since reaction 1 yields a negative
ext{ΔG}^ ext{°}
and reaction 2 gives a positive value, Reaction 1 (with
K_{ ext{eq}} = 1000
) is more exergonic than Reaction 2 (with
K_{ ext{eq}} = 0.001
).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equilibrium Constant
The equilibrium constant, often denoted as \(K_{\mathrm{eq}}\), is a crucial concept in understanding chemical reactions. It helps predict the extent to which a reaction will proceed. The value of \(K_{\mathrm{eq}}\) reflects the ratio of the concentrations of products to reactants at equilibrium. A high \(K_{\mathrm{eq}}\) (greater than 1) means products are favored, while a low value (less than 1) suggests reactants are favored.
In the context of exergonic reactions, a large \(K_{\mathrm{eq}}\) indicates a greater tendency for the reaction to occur spontaneously and release energy. In the exercise, \(K_{\mathrm{eq}} = 1000\) is much higher than \(K_{\mathrm{eq}} = 0.001\), so it suggests more products are formed, thus releasing more energy (exergonic).
In the context of exergonic reactions, a large \(K_{\mathrm{eq}}\) indicates a greater tendency for the reaction to occur spontaneously and release energy. In the exercise, \(K_{\mathrm{eq}} = 1000\) is much higher than \(K_{\mathrm{eq}} = 0.001\), so it suggests more products are formed, thus releasing more energy (exergonic).
- Large \(K_{\mathrm{eq}}\): Reaction favors products, more exergonic
- Small \(K_{\mathrm{eq}}\): Reaction favors reactants, less exergonic
Gibbs Free Energy
Gibbs free energy, symbolized as \(\Delta G\), is a measure of the maximum reversible work obtainable from a system at constant temperature and pressure. The change in Gibbs free energy, \(\Delta G^\circ\), determines whether a reaction occurs spontaneously. The key relationship to understand here is:
\[ \Delta G^\circ = -RT \times \ln(K_{\mathrm{eq}}) \]
Where \(R\) is the universal gas constant and \(T\) is the temperature in Kelvin.
This equation shows that when \(K_{\mathrm{eq}}\) is greater than 1, \(\Delta G^\circ\) becomes negative, indicating that the reaction releases free energy (exergonic). Conversely, when \(K_{\mathrm{eq}}\) is less than 1, \(\Delta G^\circ\) is positive, suggesting that the reaction absorbs energy (endergonic). Thus, the reaction with \(K_{\mathrm{eq}} = 1000\) is exergonic, while \(K_{\mathrm{eq}} = 0.001\) is endergonic.
\[ \Delta G^\circ = -RT \times \ln(K_{\mathrm{eq}}) \]
Where \(R\) is the universal gas constant and \(T\) is the temperature in Kelvin.
This equation shows that when \(K_{\mathrm{eq}}\) is greater than 1, \(\Delta G^\circ\) becomes negative, indicating that the reaction releases free energy (exergonic). Conversely, when \(K_{\mathrm{eq}}\) is less than 1, \(\Delta G^\circ\) is positive, suggesting that the reaction absorbs energy (endergonic). Thus, the reaction with \(K_{\mathrm{eq}} = 1000\) is exergonic, while \(K_{\mathrm{eq}} = 0.001\) is endergonic.
- Negative \(\Delta G^\circ\): Exergonic, releases energy
- Positive \(\Delta G^\circ\): Endergonic, absorbs energy
Spontaneous Processes
Spontaneous processes are crucial to understanding chemical reactions. A reaction is said to be spontaneous if it occurs naturally without needing to be driven by an external energy source. Whether a reaction is spontaneous is determined by the sign of \(\Delta G^\circ\).
If \(\Delta G^\circ\) is negative, the process can occur spontaneously, often with a release of energy, making it exergonic. These reactions typically favor the formation of products, as demonstrated in the exercise where the reaction with \(K_{\mathrm{eq}} = 1000\) is more likely to be spontaneous.
When \(\Delta G^\circ\) is positive, the reaction is non-spontaneous. It requires an input of energy to proceed, and such reactions are endergonic, favoring reactants over products.
If \(\Delta G^\circ\) is negative, the process can occur spontaneously, often with a release of energy, making it exergonic. These reactions typically favor the formation of products, as demonstrated in the exercise where the reaction with \(K_{\mathrm{eq}} = 1000\) is more likely to be spontaneous.
When \(\Delta G^\circ\) is positive, the reaction is non-spontaneous. It requires an input of energy to proceed, and such reactions are endergonic, favoring reactants over products.
- Spontaneous: \(\Delta G^\circ\) is negative, products are formed
- Non-spontaneous: \(\Delta G^\circ\) is positive, needs energy input