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The amino acid threonine, \((2 S, 3 R)-2\) -amino-3-hydroxybutanoic acid, has two chirality centers. (a) Draw threonine, using normal, wedged, and dashed lines to show dimensionality. (b) Draw a diastereomer of threonine, and label its chirality centers as \(R\) or \(S\).

Short Answer

Expert verified
Draw threonine and change one chiral center to create a diastereomer.

Step by step solution

01

Understanding Threonine's Structure

Threonine is an amino acid with two chiral centers. The chemical name "\((2 S, 3 R)-2\)-amino-3-hydroxybutanoic acid" indicates its specific configuration.
02

Drawing Threonine

To draw threonine, identify the correct configuration: \( (2S) \) at carbon 2 and \( (3R) \) at carbon 3. Use wedged and dashed lines to represent the 3D arrangement. Attach the appropriate groups: amino \((NH_2)\), hydroxy \((OH)\), hydrogen \((H)\), and carboxylic acid \((COOH)\) to their respective carbons.
03

Drawing a Diastereomer

Select a different configuration for one of the chiral centers. Change the configuration of one chiral center while keeping the other constant. For example, set \( (2S, 3S) \) or \( (2R, 3R) \). Draw the structure reflecting this change, using wedged and dashed lines.
04

Labeling Chirality Centers

Identify and label the new configuration for the drawn diastereomer. Use the CIP (Cahn-Ingold-Prelog) priority rules to determine the \( R \) or \( S \) configuration for each chiral center you modified. Ensure each chiral center is labeled appropriately in your drawing.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chirality Centers
A chirality center, often called an asymmetric carbon, is a carbon atom that has four different groups attached to it. This unique arrangement allows the molecule to exist in two different configurations that are mirror images of each other, known as enantiomers. In amino acids like threonine, chirality centers influence the molecule's properties and interactions.

Threonine has two chirality centers, which are the second and third carbon atoms in its structure. The placement of different groups like NHâ‚‚ (amino), OH (hydroxy), COOH (carboxylic acid), and H (hydrogen) creates these centers. Identifying and labeling these is crucial for understanding amino acid stereochemistry and its impact on biological processes.
  • The second carbon is attached to groups like NHâ‚‚, COOH, H, and the rest of the carbon chain.
  • The third carbon is attached to the OH group, H, and the remaining chain of atoms.
By evaluating these arrangements, we can determine the exact 3D configuration of the molecule, which is important in fields like medicinal chemistry and biochemistry.
Cahn-Ingold-Prelog Priority Rules
The Cahn-Ingold-Prelog (CIP) priority rules are a set of guidelines used to assign configurations to chirality centers. They help in determining whether each center is configured as R (rectus) or S (sinister). This system is vital for chemists when identifying and naming chemical structures.

To use the CIP priority rules, we first assign priorities to the four groups attached to the chirality center. The priority is based on the atomic number of the atoms directly attached to the chiral center. Higher atomic numbers get higher priority. If two atoms have the same atomic number, we proceed to the next atoms in their chains until a difference is found.
  • Arrange the molecule so that the lowest priority group (often hydrogen) is at the back.
  • If the sequence of remaining groups (in decreasing priority) follows a clockwise direction, the configuration is R.
  • If it goes counterclockwise, the configuration is S.
This systematic approach ensures accuracy in depicting stereochemistry, which has critical implications in the development and understanding of pharmaceuticals and biochemical pathways.
Diastereomers
Diastereomers are a type of stereoisomer that are not mirror images of each other, unlike enantiomers. They occur when a molecule has two or more chirality centers and at least one of them differs in configuration from another molecule. In amino acids such as threonine, diastereomers can distinctly affect the molecule's chemical properties and behavior.

For example, if threonine is found in the (2S, 3R) configuration, one could create a diastereomer by changing one of these centers while keeping the other constant, like (2S, 3S). This alteration results in molecules with different physical and chemical properties that are still related but not mirror images.
  • Diastereomers have different melting points, boiling points, and solubilities.
  • They may show varied biological activities, a crucial consideration in drug design.
Understanding diastereomers is essential in chemistry and pharmacology, as these variations can lead to significant differences in how compounds function or are used in biological systems.

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Most popular questions from this chapter

Leuprolide is a synthetic nonapeptide used to treat both endometriosis in women and prostate cancer in men. (a) Both C-terminal and N-terminal amino acids in leuprolide have been structurally modified. Identify the modifications. (b) One of the nine amino acids in leuprolide has o stereochemistry rather than the usual \(\mathrm{L}\). Which one? (c) Write the structure of leuprolide using both one- and three-letter abbreviations. (d) What charge would you expect leuprolide to have at neutral \(\mathrm{pH}\) ?

Draw the structure of ( \(S\) )-proline.

Proteins can be cleaved specifically at the amide bond on the carboxyl side of methionine residues by reaction with cyanogen bromide, \(\mathrm{BrC} \equiv \mathrm{N}:\) The reaction occurs in several steps: (a) The first step is a nucleophilic substitution reaction of the sulfur on the methionine side chain with BrCN to give a cyanosulfonium ion, \(\mathrm{R}_{2} \mathrm{SCN}^{+}\). Show the structure of the product, and propose a mechanism for the reaction. (b) The second step is an internal \(\mathrm{S}_{\mathrm{N}} 2\) reaction, with the carbonyl oxygen of the methionine residue displacing the positively charged sulfur leaving group and forming a five-membered ring product. Show the structure of the product and the mechanism of its formation. (c) The third step is a hydrolysis reaction to split the peptide chain. The carboxyl group of the former methionine residue is now part of a lactone (cyclic ester) ring. Show the structure of the lactone product and the mechanism of its formation. (d) The final step is a hydrolysis of the lactone to give the product shown. Write the mechanism of the reaction.

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