Chapter 12: Problem 13
What product would you expect from \(\mathrm{S}_{\mathrm{N}}\) 2 reaction of 1 -bromobutane with each of the following? (a) NaI (b) KOH (c) \(\mathrm{H}-\mathrm{C} \equiv \mathrm{C}-\mathrm{Li}\) (d) \(\mathrm{NH}_{3}\)
Short Answer
Expert verified
The products are 1-iodobutane, 1-butanol, 1-butynylbutane, and butylamine respectively.
Step by step solution
01
Identify the reaction type
The problem asks for the product of an \( \text{S}_\text{N}2 \) reaction involving 1-bromobutane. An \( \text{S}_\text{N}2 \) reaction is a bimolecular nucleophilic substitution, where a nucleophile attacks an electrophilic carbon, displacing a leaving group (here, bromide).
02
Analyze the reaction with NaI
In the presence of \( \text{NaI} \), iodide ion \( \text{I}^- \) acts as the nucleophile. It attacks the electrophilic carbon bound to bromine, replacing bromine and forming 1-iodobutane, \( \text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{I} \).
03
Analyze the reaction with KOH
For \( \text{KOH} \), hydroxide ion \( \text{OH}^- \) is the nucleophile. It attacks the electrophilic carbon, displacing bromine to form butanol, specifically 1-butanol, \( \text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{OH} \).
04
Analyze the reaction with H-C≡C-Li
In this case, the acetylide ion \( \text{HC} \equiv \text{C}^- \) serves as the nucleophile. It attacks the carbon attached to bromine, resulting in the formation of 1-butynylbutane, \( \text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{C}\equiv\text{CH} \).
05
Analyze the reaction with NH3
Ammonia \( \text{NH}_3 \) in its deprotonated form, \( \text{NH}_2^- \) (though ammonia itself is a neutral nucleophile), can act as a nucleophile attacking the electrophilic carbon, leading to the displacement of bromine and formation of butylamine \( \text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_2\text{NH}_2 \).
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nucleophilic Substitution
Nucleophilic substitution is a core reaction type in organic chemistry where a nucleophile targets an electrophilic carbon, displacing an existing group known as the leaving group.
- The nucleophile is electron-rich and seeks to donate electrons.
- The electrophilic carbon is part of the molecule that attracts the nucleophile due to electron deficiency.
- The leaving group is typically a halide, such as bromide in the case of 1-bromobutane, and leaves the reacting molecule upon substitution.
Organic Chemistry
Organic chemistry involves the study of carbon-containing compounds, which are central to life and industrial processes. Reactions, like \( \text{S}_\text{N}2 \), are foundational in understanding how these compounds transform.
- This field examines how atoms are arranged and how molecules interact.
- Reactions are driven by the properties of molecules such as polarity and electron configuration.
- Many synthetic processes in pharmaceuticals and materials science rely on organic reactions.
Reaction Mechanisms
A reaction mechanism describes the step-by-step process by which reactants transform into products. For \( \text{S}_\text{N}2 \) reactions, the mechanism displays specific characteristics:
- Bimolecular: The reaction involves interactions between two molecules, the nucleophile and the substrate.
- Concerted Process: Substitution occurs in a single step without intermediates.
- Backside Attack: The nucleophile approaches the carbon opposite the leaving group, leading to an inversion of molecular geometry.
Halides
Halides are a class of compounds where a halogen atom is bonded to a carbon skeleton. In nucleophilic substitutions, they often act as leaving groups:
- Common halides include chloride, bromide, and iodide.
- Bromine in 1-bromobutane is a typical leaving group in \( \text{S}_\text{N}2 \) reactions due to its decent balance of leaving group ability and reactivity.
- The strength of the halide leaving group can affect both the rate and the outcome of the reaction.
1-Bromobutane Reactions
1-Bromobutane is a simple alkyl halide used to illustrate nucleophilic substitutions. Different nucleophiles produce varied products as they react with this compound:
- With NaI, iodide replaces bromide, forming 1-iodobutane.
- With KOH, hydroxide results in the formation of 1-butanol.
- The acetylide ion from \( \text{H-C} \equiv \text{C-Li} \) forms 1-butynylbutane.
- Ammonia forms butylamine when displacing bromine.