Chapter 18: Problem 7
Calculate the percentages of neutral and protonated forms present in a solution of \(0.0010\) M pyrimidine at \(\mathrm{pH}=7.3\). The \(\mathrm{p} K_{\mathrm{a}}\) of pyrimidinium ion is \(1.3\).
Short Answer
Expert verified
Neutral: 99.9999%, Protonated: 0.0001%
Step by step solution
01
Understand the Problem
We need to find the percentages of the neutral (pyrimidine) and protonated (pyrimidinium ion) forms present in the solution at a given pH. The provided concentrations and pKa will help us determine the ratio of these forms.
02
Write the Henderson-Hasselbalch Equation
The Henderson-Hasselbalch equation relates pH, pKa, and the concentrations of the acid and its conjugate base. It is given by:\[pH = pK_{a} + \log \left(\frac{[A^-]}{[HA]}\right)\]where \([A^-]\) is the concentration of the base and \([HA]\) is the concentration of the acid.
03
Substitute Values and Solve for the Ratio
Substitute the given values into the equation:\[7.3 = 1.3 + \log \left(\frac{[A^-]}{[HA]}\right)\]Subtract 1.3 from both sides:\[6.0 = \log \left(\frac{[A^-]}{[HA]}\right)\]
04
Convert Logarithmic Equation to Exponential Form
Convert the logarithmic equation to its exponential form to find the ratio:\[10^{6.0} = \frac{[A^-]}{[HA]}\]This gives:\[1,000,000 = \frac{[A^-]}{[HA]}\]
05
Calculate Concentrations
We know that \([A^-] = 1,000,000 \cdot [HA]\) and the total concentration is 0.0010 M:\[[A^-] + [HA] = 0.0010\]Substitute \([A^-] = 1,000,000 \cdot [HA]\):\[1,000,000[HA] + [HA] = 0.0010\]\[1,000,001[HA] = 0.0010\]\[[HA] = \frac{0.0010}{1,000,001} \approx 1.0 \times 10^{-9}\]
06
Calculate [A^-]
Use the ratio to find \([A^-]\):\[[A^-] = 1,000,000 \times 1.0 \times 10^{-9} \approx 0.0010\]
07
Calculate Percentages
Calculate the percentage of each form:Neutral form (pyrimidine):\[\frac{[A^-]}{Total} \times 100 = \frac{0.0010}{0.0010} \times 100 = 99.9999\%\]Protonated form (pyrimidinium ion):\[\frac{[HA]}{Total} \times 100 = \frac{1.0 \times 10^{-9}}{0.0010} \times 100 \approx 0.0001\%\]
08
Final Answer
Therefore, the percentages are:
- Neutral form (pyrimidine): 99.9999%
- Protonated form (pyrimidinium ion): 0.0001%
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Henderson-Hasselbalch equation
The Henderson-Hasselbalch equation is a fundamental tool used in acid-base chemistry to relate the pH of a solution to its acid dissociation constant, usually denoted as pKa, and the concentrations of the acid and its conjugate base. This equation can be expressed as: \[ pH = pKa + \log \left( \frac{[A^-]}{[HA]} \right) \]Here,
- \([A^-]\) represents the concentration of the conjugate base,
- \([HA]\) is the concentration of the acid, and
- pKa is the negative logarithm of the Ka (acid dissociation constant).
Acid-Base Chemistry
Acid-base chemistry is a branch of chemistry that deals with reactions between acids and bases. These substances undergo a reaction known as neutralization, leading to the formation of water and a salt. At the heart of acid-base reactions are the concepts of acids, which are proton donors, and bases, which are proton acceptors, according to the Brønsted-Lowry theory.
In the context of chemical equilibrium, these reactions reach a state where the rate of the forward reaction equals the rate of the reverse, creating a balance of concentrations. This equilibrium concept is essential for calculating concentrations in solutions as seen with pyrimidine.
Acids have a characteristic pKa value, which is critical in determining its strength and its degree of ionization in solution.
- The lower the pKa, the stronger the acid, indicating a higher tendency to donate protons.
- For bases, a similar concept applies where a low pKb (the base dissociation constant) describes a stronger base.
pKa and pH Relationship
The relationship between pKa and pH is crucial in understanding the behavior of acids and bases in solution. The pKa value is a specific point where a weak acid and its conjugate base are present in equal concentrations in a buffer solution. It essentially acts as a measure of how readily an acid releases protons.
When the pH of a solution equals the pKa of the acid, the system is said to be at its most efficient buffering capacity. At this point:
- 50% of the acid is ionized, and 50% remains as the neutral form.
- This equilibrium makes the solution resistant to changes in pH upon the addition of small amounts of acids or bases.