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Question: The heat of combustion of cis-1,2-dimethylcyclopropane is larger than that of trans isomer. Which isomer is most stable? Use drawings to explain this difference in stability.

Short Answer

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Answer

Between cis-1,2-dimethylcyclopropane and trans-1,2-dimethylcyclopropane, trans-1,2-dimethylcyclopropane is more stable.

Step by step solution

01

Cis and trans isomers

Both cis- and trans-isomers are geometrical isomers but differ in their spatial arrangement. In cis-isomer same functional group (or element or group of atoms) is on the same side while in the trans-isomers same functional group (or element or group of atoms) is on the opposite side of each other.

02

Explanation of the more stable isomer

Here,trans-1,2-dimethylcyclopropane is more stable because in cis-isomer two methyl groups are either above or below the cyclopropane ring causing steric hindrance which makes cis isomer less stable (shown in figure). On the other hand, in the case of trans-isomer, both methyl groups are opposite to each other causing less steric hindrance resulting in higher stability of trans-isomer (shown in figure).

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Most popular questions from this chapter

(a) Draw and name the five cycloalkane structures of formulaC5H10. Can any of these structures give rise to geometric (cis-trans) isomerism? If so, show the cis and trans stereoisomers.

(b) Draw and name the eight cycloalkane structures of formulaC6H12that do not show geometric isomerism.

(c) Draw and name the four cycloalkanes of formulaC6H12that do have cis-trans isomerism.

Use a Newman projection about the indicated bond to draw the most stable conformer for each compound.

(a)3-³¾±ð³Ù³ó²â±ô±è±ð²Ô³Ù²¹²Ô±ð â¶Ä‰a²ú´Ç³Ü³Ù â¶Ä‰t³ó±ð C2−°ä3 â¶Ä‰b´Ç²Ô»å

(b)3,3-»å¾±³¾±ð³Ù³ó²â±ô³ó±ð³æ²¹²Ô±ð â¶Ä‰a²ú´Ç³Ü³Ù â¶Ä‰t³ó±ð C3−°ä4 â¶Ä‰b´Ç²Ô»å

Draw the most stable conformation of

(a) ethylcyclohexane

(b) 3-isopropyl-1,1-dimethylcyclohexane

(c) cis - 1-tert- butyl - 4 - isopropylcyclohexane

Construct a graph, similar to Figure 3-11, of the torsional energy of 3-methylpentanealong theC2−C3.PlaceC2in front, represented by three bonds coming together in a Y shape, andC3in back, represented by a circle with three bonds pointing out from it. Define the dihedral angle as the angle between the methyl group on the front carbon and ethyl group on the back carbon. Begin your graph at 00thedihedral angle and begin to turn the front carbon. Show the Newman projection and the approximate energy at each600of rotation. Indicate which conformations are the most stable (lowest energy) and the least stable (highest energy).

Question: The most stable form of 1,2,3,4,5,6-Cyclohexanehexolcontains a six-membered ring in the chair conformation with all the substituents equatorial. Draw this most stable conformation of cyclohexanehexol

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