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Question: Ethyllithium is often used as a base in organic reactions,

(a)Predict the products of the following acid-base reaction,

(b) What is the conjugate acid of? Would you expectto be a strong base or a weak base?

Short Answer

Expert verified

(a)

(b)

Step by step solution

01

Bronsted – Lowry concept of acid and base

According to Bronsted-Lowry, an acid can be defined as any substance (molecule or ion) that has the tendency to donate a proton(H+) to any substance whereas a base can be defined as any substance (molecule or ion) that has the tendency to accept a proton(H+) from any other substance.

02

Conjugate acid-base pair

The residual part of acid after losing a proton (H+) will have a tendency to accept a proton(H+) . Therefore, it will behave as a base. These pairs of substances which differ from one another by a proton (H+) are known as conjugate acid-base pairs. Consider a general example of an acid:

03

Prediction of the products and explanation            

(a) Bronsted-Lowry acid is a proton (H+)donor while Bronsted-Lowry base is a proton (H+)acceptor.

(b) The conjugate acid of CH3CH2Li is CH3-CH3 (or C2H6). Ethane (C2H6 )is a very weak acid because its pKa is around 50. Since it is a very weak acid therefore its conjugate base is a very strong base. Hence, CH3CH2Li can be expected to be a strong base.

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Most popular questions from this chapter

N-Methylpyrrolidine has a boiling point of81οC, and piperidine has a boiling point of106οC.

  1. Explain the large difference (25οC) in boiling point for these two isomers.
  2. Tetrahydropyran has a boiling point of 88οC, and cyclopentanol has a boiling point of 141οC. These two isomers have a boiling point difference of 53οC.Explain why the two oxygen-containing isomers have a much larger boiling point difference than two amine isomers.
  3. N,N-Dimethylformamide has a boiling point of 150οC, and N-methylacetamide has a boiling point of 206οC, for a difference of 56οC.Explain why these two nitrogen-containing isomers have a much larger boiling point difference than the two amine isomers. Also explain why these two amides have higher boiling points than any of the other four compounds shown (two amines, an ether, and an alcohol).

Give a definition and an example for each class of organic compounds.

(a) alkane

(b) alkene

(c) alkyne

(d) alcohol

(e) ether

(f) ketone

(g) aldehyde

(h) aromatic hydrocarbon

(i) carboxylic acid

(j) ester

(k) amine

(l) amide

(m) nitrile

Two isomers of 1,2 Dichloroethene are known. One has dipole moment of 2.4 D; the other has zero dipole moment. Draw the two isomers, and explain why one has zero dipole moment

CHCl=CHCl (1,2 Dichloroethene)

Classify the following hydrocarbons, and draw a lewis structure for each one. A compound may fit into more than one of the following classifications:

Alkane, alkene, alkyne, cycloalkane, cycloalkene, cycloalkyne, aromatic hydrocarbon.

  1. (CH3CH2)2CHCH(CH3)2
  2. CH3CHCHCH2CH3
  3. CH3CCCH2CH2CH3

e.

f.

g.

h.

i.

Circle the member of each pair that is more soluble in water.

(a) CH3CH2OCH2CH3 or CH3CH2CH2CH2CH3

(b) CH3CH2OCH2CH3 or CH3CH2CH2OH

(c) CH3CH2NHCH3 or CH3CH2CH2CH3

(d) CH3CH2OH or CH3CH2CH2CH2OH

(e) or

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