Chapter 21: Problem 57
Treatment of 5 -aminopentanoic acid with DCC (dicyclohexylcarbodiimide) yields a lactam. Show the structure of the product and the mechanism of the reaction.
Short Answer
Expert verified
The product is a 5-membered lactam, pyrrolidinone, formed via nucleophilic attack and cyclization.
Step by step solution
01
Identify the reactants
In this reaction, we have 5-Aminopentanoic acid and DCC (dicyclohexylcarbodiimide) as the reactants. 5-Aminopentanoic acid contains both an amino group (-NH2) and a carboxylic acid group (-COOH). DCC is a coupling agent that facilitates the formation of amide bonds.
02
Understand the reaction goal - Lactam formation
The objective is to form a lactam, which is a cyclic amide. The amine group of 5-aminopentanoic acid will react with its own carboxylic acid group to form a ring, releasing water and creating a cyclic structure.
03
Mechanism Initiation - Activation of carboxyl group
DCC activates the carboxylic acid group of 5-aminopentanoic acid by forming an O-acylisourea intermediate. This activation makes the carbonyl carbon more electrophilic and susceptible to attack by nucleophiles.
04
Nucleophilic attack by the amino group
The amino group (-NH2) attacks the activated carboxyl carbon. This nucleophilic attack leads to the formation of a tetrahedral intermediate, facilitating the cyclization process.
05
Cyclization and lactam formation
The intermediate undergoes intramolecular attack where the amino group forms a ring by closing onto the carbonyl carbon from which DCC is releasing, forming a 5-membered lactam cycle.
06
Removal of dicyclohexylurea
Dicyclohexylurea (DCU) is a by-product of the reaction, which precipitates out. The reaction completion is confirmed by this by-product precipitation.
07
Confirm the product structure
The final structure of the product is a cyclic molecule with a 5-membered ring containing an amide linkage, specifically a 5-membered lactam, called pyrrolidinone.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Amide Bond Formation
In the world of organic chemistry, forming an amide bond is a crucial step toward creating larger and more complex molecules. An amide bond is formed when an amino group
(-NHâ‚‚) reacts with a carboxylic acid group (-COOH). This reaction typically results in the formation of an amide linkage (-CONH-), releasing water as a by-product.
To facilitate this reaction, especially when high energy is needed to make it happen, a coupling agent like DCC (dicyclohexylcarbodiimide) is used.
To facilitate this reaction, especially when high energy is needed to make it happen, a coupling agent like DCC (dicyclohexylcarbodiimide) is used.
- DCC acts as a facilitator, converting the carboxylic acid into an activated form that is more reactive.
- This allows the amino group to easily form a bond with the carbonyl carbon of the carboxylic group.
Nucleophilic Attack
The idea of a nucleophilic attack is fundamental to understanding how atoms and molecules interact in reactions. At its core, nucleophilic attack is when a nucleophile, an electron-rich species, targets an electrophile, an electron-poor species, aiming to form a chemical bond.
In our reaction of interest, the amino group of 5-aminopentanoic acid plays the role of the nucleophile. It attacks the electrophilic center, which is the activated carbonyl carbon of the carboxylic acid group.
This attack leads to a tetrahedral intermediate, making the carbonyl carbon more amenable to incorporating the amino group.
In our reaction of interest, the amino group of 5-aminopentanoic acid plays the role of the nucleophile. It attacks the electrophilic center, which is the activated carbonyl carbon of the carboxylic acid group.
This attack leads to a tetrahedral intermediate, making the carbonyl carbon more amenable to incorporating the amino group.
- The nucleophilic attack alters the electron distribution within the molecule, preparing it for further transformation.
- This is a critical step where the structure starts to morph, establishing the backbone of our target molecule—the lactam.
Carboxylic Acid Activation
Carboxylic acid activation is a pivotal process that significantly enhances the reactivity of the carboxylic acid group. Normally, carboxylic acids aren't particularly reactive due to the resonance-stabilized nature of their carboxylate group.
However, activating them with DCC transforms them into an O-acylisourea intermediate. This activation drastically increases the electrophilic character of the carboxyl carbon.
This process is key in enabling a successful nucleophilic attack from the amino group, which is normally challenging due to the innate stability of carboxylic acids.
However, activating them with DCC transforms them into an O-acylisourea intermediate. This activation drastically increases the electrophilic character of the carboxyl carbon.
This process is key in enabling a successful nucleophilic attack from the amino group, which is normally challenging due to the innate stability of carboxylic acids.
- Activation reduces the energy barrier that must be overcome for the reaction to occur, making the process more efficient.
- The intermediate O-acylisourea is more electrophilic and reactive, attributing to its transformation to an amide bond.
Cyclization Reaction
Cyclization is a fascinating reaction that transforms linear molecules into cyclic structures. This is exactly what happens when 5-aminopentanoic acid forms a lactam via intramolecular nucleophilic attack.
Cyclization requires a nucleophile to attack an electrophile within the same molecule; in this case, it is the amino group attacking the activated carboxyl carbon.
After the formation of a tetrahedral intermediate, the structure rearranges, allowing the molecule to form a ring.
Cyclization requires a nucleophile to attack an electrophile within the same molecule; in this case, it is the amino group attacking the activated carboxyl carbon.
After the formation of a tetrahedral intermediate, the structure rearranges, allowing the molecule to form a ring.
- This reaction is significant because it reduces structural overlap and often increases the stability of the molecule.
- For the 5-aminopentanoic acid, cyclization results in a 5-membered ring known as pyrrolidinone.