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Including stereoisomers, draw the 11 aldehydes with molecular formula C\(_6\)H\(_{12}\)O, and give the IUPAC name (with any needed \(R,S\) designation) for each compound.

Short Answer

Expert verified
C鈧咹鈧佲倐O aldehydes: 1-hexanal, 2R/2S-methylpentanal, 3R/3S-methylpentanal, 4-methylpentanal, cyclohexanecarboxaldehyde, cyclopentanecarboxaldehyde with ethyl group.

Step by step solution

01

Identify Structural Formula

Determine the number of carbon atoms that should be part of the longest carbon chain containing the aldehyde group. Here, with the formula C鈧咹鈧佲倐O, the aldehyde group will be part of a hexane chain.
02

Draw Possible Linear Aldehydes

Start by drawing all possible linear aldehydes. The aldehyde group will always be at the terminal position of the carbon chain to form hexanal (1-hexanal) without any branching. This results in the structure: CH鈧-(CH鈧)鈧-CHO.
03

Consider Branched Structures with Aldehyde Group

Next, introduce branching within the five-carbon chain while still ending with an aldehyde group. This includes pentenal isomers such as 2-methylpentanal, 3-methylpentanal, and 4-methylpentanal.
04

Include Possible Stereoisomers

For isomers with asymmetric centers, consider R/S configurations. For instance, 2-methylpentanal has one chiral center, leading to two stereoisomers (2R-methylpentanal and 2S-methylpentanal). Similarly, 3-methylpentanal also has enantiomers.
05

Draw Cyclic Aldehydes

Consider cyclic structures that obey the formula. The aldehyde group must remain as a terminal function. Cyclohexane can be appended with an aldehyde group to form cyclohexanecarboxaldehyde or ring-opened to form linear aldehydes.
06

List and Name All Aldehydes

Gather all combinations from previous steps: 1-hexanal, 2-methylpentanal (R/S), 3-methylpentanal (R/S), 4-methylpentanal, cyclohexanecarboxaldehyde, cyclopentanecarboxaldehyde with an ethyl group.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stereoisomers
Stereoisomers are fascinating because even though they have the same molecular formula and sequence of bonded atoms (constitution), their three-dimensional orientations differ. For aldehydes with the formula C _6 H _12 O, stereoisomers become particularly interesting when asymmetric carbon atoms, also known as chiral centers, are involved.

Imagine the shape-shifting nature of these molecules. Even a small twist around a chiral center can lead to completely different properties. Two types of stereoisomers are common: enantiomers, which are non-superimposable mirror images, and diastereomers, which are not. This phenomenon is crucial for understanding why certain molecules, like 2-methylpentanal, can exist in multiple forms with different spatial arrangements, namely as (R) and (S) configurations.
  • Enantiomers: Different like right and left hands.
  • Diastereomers: Differ in more than one configuration and not mirror images.
Chiral centers add a delightful complexity to these compounds, affecting their reactions and behavior in biological systems. Recognizing and drawing these stereoisomers helps uncover the blueprint of molecular interactions.
IUPAC nomenclature
The IUPAC nomenclature system is like a universal language for chemists to name compounds systematically and unambiguously. When dealing with aldehydes like those of C _6 H _12 O, this naming convention provides insights into the molecule's skeleton and its specific branches or functional groups.

To name aldehydes, locate the longest chain of carbon atoms that contains the aldehyde group. Name it with the suffix '-al' to signify the aldehyde function. For example, a straight six-carbon chain with an aldehyde group is named hexanal. If there is branching, a prefix indicates the position and nature of the branch, such as methyl or ethyl groups. Position numbers ensure the accurate location of these functional groups.
  • Base name: Longest carbon chain including aldehyde.
  • Suffix '-al' for aldehyde.
  • Prefixes for branches and position numbers.
The systematic approach ensures clarity, even when tackling complex molecules like 2-methylpentanal. Each name provides a detailed map, making it easier to visualize and construct these aldehydes.
Chiral centers
Chiral centers act as pivotal points where structural variations lead to distinct molecular identities. Every chiral center is an asymmetric carbon atom bonded to four different groups. This small difference in structure can lead to enormous variations in how the molecules interact with the world around them, especially in biological systems.

Identifying chiral centers within aldehydes like those of C _6 H _12 O is crucial for understanding their stereochemistry. A molecule such as 3-methylpentanal contains chiral centers, and this leads to the existence of enantiomers with distinct properties called (R) and (S) configurations. Each configuration has a unique spatial arrangement that influences how it might interact with enzymes or receptors, behaving differently in biological processes.
  • Asymmetric carbon atom with four different groups.
  • Creates non-superimposable mirror images (enantiomers).
  • Specific configurations are labeled as (R) or (S).
Recognizing and labeling these centers in molecular structures aids in drawing precise isomers, which is vital in fields like pharmaceuticals, where the arrangement can influence the effectiveness of a drug.

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Most popular questions from this chapter

Devise a synthesis of each alkene using a Wittig reaction to form the double bond. You may use benzene and organic alcohols having four or fewer carbons as starting materials and any required reagents. a. CH\(_3\)CH\(_2\)CH\(_2\)CH=CHCH\(_3\) b. C\(_6\)H\(_5\)CH=CHCH\(_2\)CH\(_2\)CH\(_3\) c. (CH\(_3\))\(_2\) C=CHCH(CH\(_3\))\(_2\)

Draw the product formed when phenylacetaldehyde (C\(_6\)H\(_5\)CH\(_2\)CHO) is treated with each reagent. Phenylacetaldehyde is partly responsible for the fragrance of the flowers of the plumeria tree, which is native to the tropical and subtropical Americas. a. NaBH\(_4\), CH\(_3\)OH b. [1] LiAIH\(_4\) ; [2] H\(_2\)O c. [1] CH\(_3\)MgBr; [2] H\(_2\)O d. NaCN, HCI e. Ph\(_3\)P=CHCH\(_3\) f. (CH\(_3\))\(_2\)CHNH\(_2\) , mild acid g. (CH\(_3\)CH\(_2\))\(_2\)NH, mild acid h. CH\(_3\)CH\(_2\)OH (excess), H\(^+\) i. NH, mild acid j. HOCH\(_2\)CH\(_2\)OH, H\(^+\)

Reaction of 5,5-dimethoxy-2-pentanone with methylmagnesium iodide followed by treatment with aqueous acid forms cyclic hemiacetal \(\textbf{Y}\). Draw a stepwise mechanism that illustrates how \(\textbf{Y}\) is formed.

Draw the structure of all constitutional isomers that contain a ketone and have molecular formula C\(_5\)H\(_{10}\)O. Give the IUPAC name for each isomer and state how \(^{13}\)C NMR spectroscopy could be used to distinguish these isomers.

Sulfur ylides, like Wittig reagents, are useful intermediates in organic synthesis. Sulfur ylides are formed by the treatment of sulfonium salts with butyllithium. They react with carbonyl compounds to form epoxides. Draw the mechanism for formation of epoxide \(\textbf{X}\) from cyclohexanone using a sulfur ylide.

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