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Draw the organic products formed when 2 -bromo-3-pentanone \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCHBrCH}_{3}\right)\) is treated with each reagent: (a) \(\mathrm{Li}_{2} \mathrm{CO}_{3}\), LiBr, DMF; (b) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{NH}_{2} ;\) (c) \(\mathrm{CH}_{3} \mathrm{SH}\).

Short Answer

Expert verified
(a) 3-penten-2-one, (b) the corresponding amide, (c) a thioether.

Step by step solution

01

Understanding the initial compound

The compound given is 2-bromo-3-pentanone, with the structure \(\text{CH}_3\text{CH}_2\text{COCHBrCH}_3\). This molecule contains a bromine atom on the third carbon and a carbonyl group (C=O) on the second carbon.
02

Reaction with Li2CO3, LiBr, DMF

In this reaction, the bromide ion is a good leaving group. The basic conditions provided by Li2CO3 in DMF facilitate an elimination reaction, leading to the formation of an alpha, beta-unsaturated ketone. Thus, the product formed is an enone, which is 3-penten-2-one: \(\text{CH}_3\text{CH}_2\text{COCH}=\text{CH}_\text{2}\.\)
03

Reaction with CH3CH2NH2

The primary amine \(\text{CH}_3\text{CH}_2\text{NH}_2\) acts as a nucleophile, attacking the electrophilic carbonyl carbon of the ketone. This results in a nucleophilic acyl substitution leading to the formation of an amide. The product is \(\text{CH}_3\text{CH}_2\text{C}(\text{O})(\text{NHCH}_2\text{CH}_3)\text{CH}_2\text{CH}_3\).
04

Reaction with CH3SH

\(\text{CH}_3\text{SH}\), or methanethiol, functions as a nucleophile to displace the bromide ion. This forms a thioether, and the product is \(\text{CH}_3\text{CH}_2\text{COCH}(\text{SCH}_3)\text{CH}_3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elimination Reactions
Elimination reactions are a crucial type of organic reaction where two atoms or groups are removed from a molecule, resulting in the formation of a double bond. In our exercise, when 2-bromo-3-pentanone is treated with a combination of - Li\(_2\)CO\(_3\)- LiBr - DMF the reaction conditions are set for an elimination reaction. The bromine atom acts as a leaving group. The base, Li\(_2\)CO\(_3\), facilitates the removal of the β hydrogen atom. The result is the formation of a double bond between the alpha (α) and beta (β) carbon atoms, creating an unsaturated ketone known as an enone. This change transforms 2-bromo-3-pentanone into 3-penten-2-one, a compound characterized by its carbon-carbon double bond adjacent to a ketone group.
Nucleophilic Substitution
Nucleophilic substitution is another fundamental reaction mechanism where a nucleophile replaces a leaving group in a molecule. In the reaction involving 2-bromo-3-pentanone and primary amine, - ethylamine ( CH\(_3\)CH\(_2\)NH\(_2\) ), the amine acts as a nucleophile. It attacks the electrophilic carbonyl carbon in the ketone. The bromine atom in 2-bromo-3-pentanone serves as an excellent leaving group. This allows the formation of a bond between the amine and the carbon, transforming the carbonyl group into an amide linkage. The resultant product is an amide, specifically an N-substituted amide, where the ethylamine is attached to the carbonyl carbon, forming - CH\(_3\)CH\(_2\)C(O)(NHCH\(_2\)CH\(_3\))CH\(_2\)CH\(_3\) . This example illustrates how nucleophilic substitution can create a variety of organic compounds.
Enone Formation
Enones are organic compounds that contain a double bond conjugated with a carbonyl group. In the reaction described, the starting compound is 2-bromo-3-pentanone. This compound undergoes an elimination reaction to form 3-penten-2-one, an enone. The process involves removing a hydrogen and a bromine to form a double bond between the α and β carbons. This transformation is significant because enones are versatile intermediates in organic chemistry. They participate in a range of chemical reactions, including conjugate additions and cycloadditions. Enone formation is a valuable tool in synthetic organic chemistry for building complex molecular structures.
Thioether Formation
Thioethers, also known as sulfides, are compounds where a sulfur atom is bonded to two alkyl or aryl groups. They are similar to ethers but feature sulfur instead of oxygen. In the reaction with methanethiol (- CH\(_3\)SH ), 2-bromo-3-pentanone undergoes a nucleophilic substitution reaction. The sulfur in methanethiol acts as a nucleophile, attacking the carbon atom attached to the bromine, and the bromide ion departs as a leaving group. This results in the formation of a thioether. The product,- CH\(_3\)CH\(_2\)COCH(SCH\(_3\))CH\(_3\) , is called methyl thioether. Thioether groups are found in numerous biological molecules and are important in pharmaceuticals, providing unique chemical properties that are useful in a variety of applications.

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