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Which of the following possible structures for \(X\) can be excluded on the basis of its IR spectrum: (a) \(\mathrm{CH}_{3} \mathrm{COOCH}_{2} \mathrm{CH}_{3}\); (b) \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CHO} ;\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOCH}_{3}\); (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COOH} ?\)

Short Answer

Expert verified
If the IR spectrum lacks a broad O-H stretch, structure (b) and (d) can be excluded.

Step by step solution

01

Understand the IR Spectrum

The IR spectrum allows us to identify functional groups present in a compound by detecting their characteristic vibration frequencies. Esters have C=O stretches near 1735-1750 cm鈦宦, alcohols show broad O-H stretches around 3200-3550 cm鈦宦, and carboxylic acids exhibit O-H stretches around 2500-3300 cm鈦宦 and C=O stretches near 1700-1725 cm鈦宦.
02

Analyze Structure (a)

Structure (a), \(\text{CH}_3\text{COOCH}_2\text{CH}_3\), is an ester. It should have a strong absorbance due to the C=O stretch around 1735-1750 cm鈦宦, but no broad O-H stretch.
03

Analyze Structure (b)

Structure (b), \(\text{HOCH}_2\text{CH}_2\text{CH}_2\text{CHO}\), is an alcohol with an aldehyde. We expect a broad O-H stretch from 3200-3550 cm鈦宦 and an aldehyde C=O stretch around 1720-1740 cm鈦宦.
04

Analyze Structure (c)

Structure (c), \(\text{CH}_3\text{CH}_2\text{COOCH}_3\), is another ester. It should have the C=O ester stretch around 1735-1750 cm鈦宦, with no O-H stretch.
05

Analyze Structure (d)

Structure (d), \(\text{CH}_3\text{CH}_2\text{CH}_2\text{COOH}\), is a carboxylic acid. It should show a broad O-H stretch from 2500-3300 cm鈦宦 and a C=O carboxylic acid stretch near 1700-1725 cm鈦宦.
06

Determine which structure can be excluded

Based on the absence of a broad O-H stretch in the IR spectrum, which would exclude any compound with a hydroxyl group (alcohol or carboxylic acid), compounds (b) and (d) can be identified by these functional groups. Since (d) and (b) both should have O-H stretch, if it is absent, these structures can be excluded. If C=O is present but no O-H, structure (c) still fits. The presence of both C=O without any O-H means structure (a) can be excluded if the spectrum indicates presence of both.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Functional Groups
Understanding functional groups is key in the study of Infrared (IR) Spectroscopy. Functional groups are specific groupings of atoms within molecules that are responsible for the characteristic chemical reactions of those molecules. In IR spectroscopy, different functional groups absorb infrared light at different wavelengths, allowing us to identify them based on their unique vibrational frequencies.
For example, in the exercise, esters, alcohols, aldehydes, and carboxylic acids each have unique IR absorption characteristics.
  • Esters exhibit a strong carbonyl (C=O) stretch near 1735-1750 cm鈦宦.
  • Alcohols present a broad hydroxyl (O-H) stretch around 3200-3550 cm鈦宦.
  • Carboxylic acids have both a broad O-H stretch (2500-3300 cm鈦宦) and a C=O stretch near 1700-1725 cm鈦宦.
  • Aldehydes show a carbonyl C=O stretch around 1720-1740 cm鈦宦.
Identifying functional groups helps in determining what compounds might be present in an unknown mixture or verifying the structure of a synthesized compound. Functional group analysis through IR can therefore be a powerful tool in chemical research and industry.
Chemical Structure Analysis
IR spectroscopy is an essential tool in chemical structure analysis. It allows scientists to deduce the molecular blueprint of a compound by examining the absorbed wavelengths of infrared light, which correspond with vibrations of chemical bonds.
This technique was used in the provided exercise to scrutinize four potential molecular structures. By analyzing the IR spectrum:
  • You can identify the presence of certain bonds. For instance, esters like structures (a) and (c) have a distinctive C=O stretching frequency approximately between 1735-1750 cm鈦宦, while lacking an O-H stretch.
  • Structures with alcohol groups, such as structure (b), show an O-H stretch, typically broad due to hydrogen bonding, around 3200-3550 cm鈦宦.
  • Carboxylic acids, as represented by structure (d), exhibit a dual presence of the O-H and C=O stretches.
Identifying these features allows chemists to eliminate structures that do not match the spectral data, thereby zeroing in on those that do. This makes IR spectroscopy an invaluable method for confirming the chemical structure of organic molecules and ensuring the integrity of synthesized compounds.
Vibrational Frequencies
Vibrational frequencies in Infrared (IR) Spectroscopy correspond to the specific energies at which different chemical bonds vibrate. These vibrations can be bending, stretching, or a combination of both, depending on the bond type and atoms involved.
In the IR spectrum:
  • Stretching vibrations, such as those of the C=O and O-H bonds, are typically seen as sharp bands. For example, the C=O stretch found in esters and carboxylic acids will appear prominently between 1700-1750 cm鈦宦.
  • The O-H stretching vibration manifests as a broader band due to the involvement of hydrogen, particularly in alcohols and acids, which is crucial for distinguishing these functional groups.
This principle was applied in the problem's step-by-step solution. By noting the absence of an O-H vibrational frequency, two of the four chemical possibilities could be eliminated, showcasing how crucial understanding these vibrational frequencies is in determining the correct structure of a molecule.
This knowledge aids significantly in both academic and practical applications of chemical analysis, such as identifying unknown substances or confirming the composition of synthesized materials.

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Most popular questions from this chapter

Can the exact mass obtained in a high-resolution mass spectrum distinguish between two isomers such as \(\mathrm{CH}_{2}=\mathrm{CHCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\) and \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{CHCH}_{2} \mathrm{CH}_{3} ?\)

Propose possible structures consistent with each set of data. Assume each compound has an \(s p^{3}\) hybridized \(\mathrm{C}-\mathrm{H}\) absorption in its IR spectrum, and that other major IR absorptions above \(1500 \mathrm{~cm}^{-1}\) are listed. a. A compound having a molecular ion at 72 and an absorption in its IR spectrum at \(1725 \mathrm{~cm}^{-1}\) b. A compound having a molecular ion at 55 and an absorption in its IR spectrum at \(-2250 \mathrm{~cm}^{-1}\) c. A compound having a molecular ion of 74 and an absorption in its IR spectrum at \(3600-3200 \mathrm{~cm}^{-1}\)

Reaction of pentanoyl chloride \(\left(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{COCl}\right)\) with lithium dimethyl cuprate \(\left[\mathrm{LiCu}\left(\mathrm{CH}_{3}\right)_{2}\right]\) forms a compound \(\mathrm{J}\) that has a molecular ion in its mass spectrum at 100 , as well as fragments at \(m / z=85,57\), and 43 (base). The IR spectrum of \(\mathrm{J}\) has strong peaks at 2962 and \(1718 \mathrm{~cm}^{-1}\). Propose a structure for \(\mathbf{J}\).

Propose two possible structures for a hydrocarbon having an exact mass of \(96.0939\) that forms ethylcyclopentane upon hydrogenation with \(\mathrm{H}_{2}\) and Pd-C.

Benzonitrile \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CN}\right)\) is reduced to two different products depending on the reducing agent used. Treatment with lithium aluminum hydride followed by water forms \(\mathbf{K}\), which has a molecular ion in its mass spectrum at 107 and the following IR absorptions: \(3373,3290,3062,2920\), and \(1600 \mathrm{~cm}^{-1}\). Treatment with a milder reducing agent forms \(\mathrm{L}\), which has a molecular ion in its mass spectrum at 106 and the following IR absorptions: \(3086,2850,2820,2736,1703\), and \(1600 \mathrm{~cm}^{-1} . \mathrm{L}\) shows fragments in its mass spectrum at \(m / z=105\) and 77 . Propose structures for \(K\) and \(L\) and explain how you arrived at your conclusions.

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