/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 Devise a synthesis of the ketone... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Devise a synthesis of the ketone 3-hexanone, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\), from \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Br}\) as the only organic starting material; that is. all the carbon atoms in 3-hexanone must come from \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{Br}\). You may use any other needed reagents.

Short Answer

Expert verified
Use ethyl bromide to form a Grignard reagent, react with ethyl formate, and oxidize the alcohol to yield 3-hexanone.

Step by step solution

01

Formation of Ethyl Magnesium Bromide

Begin by generating the Grignard reagent. React 2 equivalents of ethyl bromide, \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{Br}\), with magnesium in the presence of ether. This will create ethyl magnesium bromide \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{MgBr}\).
02

Reaction with Ethyl Formate

React the ethyl magnesium bromide with ethyl formate \(\mathrm{HCOOC}_{2}\mathrm{H}_{5}\) to form a secondary alcohol. This step involves a nucleophilic attack by the Grignard reagent on the carbonyl carbon, followed by protonation, yielding 3-pentanol \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}\left(\mathrm{OH}\right)\mathrm{CH}_{2}\mathrm{CH}_{3}\).
03

Oxidation to 3-Hexanone

Oxidize 3-pentanol using an oxidizing agent such as PCC (pyridinium chlorochromate) to convert the alcohol into a ketone, namely 3-hexanone \(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CO}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{CH}_{3}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Grignard Reagent
The Grignard reagent plays a crucial role in organic synthesis, serving as a powerful tool for creating carbon-carbon bonds. Named after the French chemist Victor Grignard, who discovered it, this reagent is typically formed by reacting an alkyl or aryl halide with magnesium metal in a dry ether solvent. The result is a compound such as ethyl magnesium bromide, which is an organomagnesium compound. In our synthesis of 3-hexanone, we started with ethyl bromide, to create a Grignard reagent:
  • React ethyl bromide (\(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{Br}\)) with magnesium, using dry ether as a solvent,to form ethyl magnesium bromide (\(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{MgBr}\)).
The formation of a Grignard reagent is sensitive to moisture and must be conducted under anhydrous conditions. This reactivity is due to its highly polar carbon-magnesium bond, making it an excellent nucleophile, capable of attacking a variety of electrophiles, which leads us to the next concept.
Nucleophilic Attack
In organic chemistry, nucleophilic attack is an essential mechanism where a nucleophile, which often has a pair of non-bonding electrons,attacks an electrophile to form a new covalent bond. For our synthesis of 3-hexanone, the Grignard reagent (ethyl magnesium bromide) acts as a nucleophile. Here’s what happens:
  • When ethyl magnesium bromide encounters ethyl formate (\(\mathrm{HCOOC}_{2}\mathrm{H}_{5}\)), it seeks out the carbon atom of the carbonyl group,as this carbon is electron-poor or electrophilic.
  • The Grignard reagent donates its electrons to this carbon,breaking the multiple bond, and forms a C-C bond with it.
  • The reaction initially results in a metal alkoxide,which is then protonated to create a secondary alcohol, 3-pentanol (\(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CH}(\mathrm{OH})\mathrm{CH}_{2}\mathrm{CH}_{3}\)).
Through this nucleophilic attack, we successfully construct more complex molecules and proceed onward in the synthesis process.
Oxidation of Alcohol
Oxidation, in a chemical context, refers to the process of increasing the oxidation state of a molecule, commonly involving a loss of electrons. In organic synthesis, oxidizing alcohols to form ketones is a common practice, utilizing various oxidizing agents. For the 3-hexanone synthesis, we apply this concept by:
  • Starting with 3-pentanol, which we obtained from the Grignard reaction as a secondary alcohol.
  • Choosing an appropriate oxidizing agent. In this case, PCC (pyridinium chlorochromate) is used as it is efficient at transforming secondary alcohols into ketones.
  • The reaction converts the hydroxyl group (\(\mathrm{OH}\)) on the 3-pentanol to a carbonyl group (\(\mathrm{C=O}\)), yielding the desired ketone, 3-hexanone (\(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{CO}\mathrm{CH}_{2}\mathrm{CH}_{2}\mathrm{CH}_{3}\)).
This oxidation step is significant because it marks the transition from an alcohol to a ketone, completing the synthesis pathway from simple starting materials to the finished product.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.