Chapter 1: Problem 85
a. What is the hybridization of each \(\mathrm{N}\) atom in nicotine?
Short Answer
Step by step solution
Analyze Nicotine Structure
Determine Hybridization of Nitrogen Atoms
Identify Geometry Around Nitrogen
Determine Orbital of Lone Pair
Draw a Constitutional Isomer
Draw a Resonance Structure
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hybridization
- In the pyrrolidine ring, the nitrogen atom forms three sigma bonds and has a lone pair. This arrangement is characteristic of \( sp^3 \) hybridization, where one s orbital and three p orbitals mix to form four \( sp^3 \) hybrid orbitals.
- In the pyridine ring, the nitrogen atom is bonded in such a way that it participates in one sigma bond and is also part of the aromatic system. This setup leads to \( sp^2 \) hybridization, involving the mixing of one s and two p orbitals to create three \( sp^2 \) hybrid orbitals, leaving one p orbital for the aromatic pi bonding.
Molecular Geometry
- For \( sp^3 \) hybridized nitrogen in pyrrolidine, the geometry is tetrahedral. This is because the nitrogen forms bonds and a lone pair around it, resembling a simplified pyramidial shape due to lone electron pair repulsion.
- On the other hand, \( sp^2 \) hybridized nitrogen in pyridine has a trigonal planar geometry. Here, the nitrogen forms bonds lying in a single plane, helping sustain the planar aromatic structure.
Lone Pair Orbitals
- In the \( sp^3 \) hybridized nitrogen atom in the pyrrolidine ring, the lone pair is found in one of the \( sp^3 \) hybrid orbitals. This leads to the characteristic tetrahedral shape affecting bond angles.
- For the \( sp^2 \) hybridized nitrogen in the pyridine ring, the lone pair resides in one of the \( sp^2 \) orbitals. This positioning helps the nitrogen's lone pair contribute to the \( \pi \) electron system in the aromatic ring, an essential aspect for its aromatic nature.
Constitutional Isomers
- One way to form a constitutional isomer of nicotine is by altering the position of nitrogen or other atoms within the molecule, such as moving the nitrogen atom in the pyrrolidine ring.
- These changes can lead to variations in properties such as boiling and melting points, solubility, and reactivity without changing the formula.
Resonance Structures
- In nicotine, drawing resonance structures involves shifting electrons, particularly in the aromatic pyridine ring, where electron movement helps stabilize the ring structure.
- This might involve moving double bonds and altering formal charges, aiding in a more accurate representation of the molecule's true electron structure.