Chapter 22: Problem 14
Draw the products formed when benzoyl chloride \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COCl}\right)\) is treated with each nucleophile: (a) \(\mathrm{H}_{2} \mathrm{O}\), pyridine; (b) \(\mathrm{CH}_{3} \mathrm{COO}^{-}\); (c) \(\mathrm{NH}_{3}\) (excess); (d) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{NH}\) (excess).
Short Answer
Step by step solution
Reaction with Water and Pyridine
Reaction with Acetate Ion
Reaction with Ammonia (Excess)
Reaction with Dimethylamine (Excess)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Benzoyl Chloride Reactions
- When it reacts with water in the presence of pyridine, it forms benzoic acid.
- With an acetate ion, it forms benzoyl acetate.
- Reaction with ammonia leads to the formation of benzamide.
- It reacts with amines like dimethylamine to form N,N-dimethylbenzamide.