Chapter 20: Problem 72
Explain why the \(\beta\) carbon of an \(\alpha, \beta\) -unsaturated carbonyl compound absorbs farther downfield in the \({ }^{13} \mathrm{C}\) NMR spectrum than the \(\alpha\) carbon, even though the \(\alpha\) carbon is closer to the electron-withdrawing carbonyl group. For example, the \(\beta\) carbon of mesityl oxide absorbs at \(150.5 \mathrm{ppm}\), while the \(\alpha\) carbon absorbs at \(122.5 \mathrm{ppm}\).
Short Answer
Step by step solution
Understand Downfield Shifts in NMR
Analyze Electron Withdrawing Effects
Consider the π System of the α, β-unsaturated Carbonyl
Compare Deshielding Effects
Conclusion on Downfield Absorption
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chemical Shift in NMR Spectroscopy
Electron Withdrawal in Carbonyl Groups
- The oxygen atom in the carbonyl group is highly electronegative, pulling electron density away from the carbon.
- This creates a more positive charge on the carbon, which further extends to adjacent atoms in the molecule.
Understanding Deshielding
- Selective electron withdrawal by nearby electronegative groups, such as carbonyls.
- Participation in system that allows electron delocalization, such as π-conjugation.
Conjugation and Its Effects
- In \( \alpha, \beta \) -unsaturated carbonyl compounds, conjugation involves the \( \alpha \,\) and \( \beta \) carbons as well as the carbonyl group.
- The \( \beta \) carbon becomes more deshielded due to increased electron sharing.
- This involvement in conjugation affects the chemical shift, pushing the \( \beta \) carbon's signal farther downfield when compared to the \( \alpha \) carbon.
Role of the Carbonyl Group
- The carbon double-bonded to the electronegative oxygen creates a polar bond.
- This causes electron withdrawal through the bond, influencing chemical shifts in \( ^{13} \mathrm{C} \) NMR.