/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 45 The iodination of ethylene at \(... [FREE SOLUTION] | 91Ó°ÊÓ

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The iodination of ethylene at \(25^{\circ} \mathrm{C}\) is characterized by the thermodynamic values shown. \(\begin{aligned} \mathrm{H}_{2} \mathrm{C}=\mathrm{CH}_{2}(g) &+\mathrm{I}_{2}(g) \rightleftharpoons \mathrm{ICH}_{2} \mathrm{CH}_{2} \mathrm{I}(g) \\ \Delta H^{\circ}=-48 \mathrm{~kJ} / \mathrm{mol}(11.5 \mathrm{kcal} / \mathrm{mol}) ; \Delta S^{\circ}=-0.13 \mathrm{~kJ} / \mathrm{K} \cdot \mathrm{mol}(0.31 \mathrm{kcal} / \mathrm{K} \cdot \mathrm{mol}) \end{aligned}\) (a) Calculate \(\Delta G^{\circ}\) and \(K\) at \(25^{\circ} \mathrm{C}\). (b) Is the reaction exergonic or endergonic at \(25^{\circ} \mathrm{C}\) ? (c) What happens to \(K\) as the temperature is raised?

Short Answer

Expert verified
(a) \( \Delta G^{\circ} = -9.24 \) kJ/mol; \( K \approx 41.3 \). (b) The reaction is exergonic. (c) \( K \) decreases with increasing temperature.

Step by step solution

01

Calculate \( \Delta G^{\circ} \) using \( \Delta H^{\circ} \) and \( \Delta S^{\circ} \)

The Gibbs free energy change, \( \Delta G^{\circ} \), can be calculated using the formula: \( \Delta G^{\circ} = \Delta H^{\circ} - T \Delta S^{\circ} \). First, we convert \( T \) from degrees Celsius to Kelvin: \( T = 25 + 273.15 = 298.15 \) K. Then, substitute \( \Delta H^{\circ} = -48 \) kJ/mol and \( \Delta S^{\circ} = -0.13 \) kJ/K·mol into the formula: \( \Delta G^{\circ} = -48 - (298.15)(-0.13) = -48 + 38.7595 = -9.2405 \) kJ/mol.
02

Calculate \( K \) using \( \Delta G^{\circ} \)

The equilibrium constant \( K \) can be calculated from \( \Delta G^{\circ} \) using the relationship: \( \Delta G^{\circ} = -RT \ln K \), where \( R = 8.314 \) J/mol·K. Rearrange to solve for \( \ln K \): \( \ln K = -\Delta G^{\circ} / (RT) \). Convert \( \Delta G^{\circ} = -9.2405 \) kJ/mol to J/mol: \( -9240.5 \) J/mol. Then, \( \ln K = 9240.5 / (8.314 \times 298.15) \approx 3.721 \). Finally, \( K = e^{3.721} \approx 41.3 \).
03

Determine if the reaction is exergonic or endergonic at \( 25^{\circ} \mathrm{C} \)

A reaction is considered exergonic if \( \Delta G^{\circ} < 0 \) and endergonic if \( \Delta G^{\circ} > 0 \). In our calculation, \( \Delta G^{\circ} = -9.2405 \) kJ/mol, which is negative. This means the reaction is exergonic.
04

Analyze the effect of increased temperature on \( K \)

For a reaction with a negative \( \Delta H^{\circ} \) (exothermic), increasing the temperature generally decreases \( K \) because the reaction is more spontaneous at lower temperatures. Using Le Chatelier's principle, an increase in temperature will shift equilibrium to favor the reactants, thus decreasing \( K \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy
Gibbs free energy (\( \Delta G^{\circ} \)) is a pivotal concept in thermodynamics that helps determine the spontaneity of a chemical reaction. The equation to calculate \( \Delta G^{\circ} \) is:
  • \( \Delta G^{\circ} = \Delta H^{\circ} - T \Delta S^{\circ} \)
where \( \Delta H^{\circ} \) is the change in enthalpy, \( T \) is the temperature in Kelvin, and \( \Delta S^{\circ} \) is the change in entropy.
If \( \Delta G^{\circ} \) is negative, the reaction tends to be spontaneous under standard conditions, meaning it can proceed without external energy input.
Conversely, a positive \( \Delta G^{\circ} \) indicates that the reaction is non-spontaneous and requires energy to proceed. In the context of the iodination of ethylene, the calculated \( \Delta G^{\circ} \) was \(-9.2405 \text{kJ/mol}\), showing that the reaction is exergonic and thus favorable at \(25^{\circ} \text{C}\). Understanding \( \Delta G^{\circ} \) helps predict how different conditions affect the energy landscape of the reaction.
Equilibrium Constant
The equilibrium constant (\( K \)) is another critical aspect of chemical reactions. It offers insight into the ratio of products to reactants at equilibrium. The value of \( K \) for a reaction can be determined using the Gibbs free energy change with the relation:
  • \( \Delta G^{\circ} = -RT \ln K \)
where \( R \) is the universal gas constant, and \( T \) is the temperature in Kelvin.
After rearranging the formula to solve for \( K \), we find that \( K = e^{-\Delta G^{\circ}/(RT)} \). A relatively large \( K \), such as \(41.3\) in the exercise, suggests that at equilibrium, the products of the iodination of ethylene are favored.
Thus, the reactants get converted primarily to products, highlighting the spontaneous nature of the reaction at the given temperature. The equilibrium constant aids in predicting how the reaction composition changes with varying initial concentrations and external conditions.
Le Chatelier's Principle
Le Chatelier's Principle is a fundamental principle in chemistry that describes how a system at equilibrium reacts to external changes.
According to this principle, if a change in temperature, pressure, or concentration occurs, the equilibrium will shift in a direction that counteracts the change.
In the context of the iodination of ethylene, this principle is particularly relevant. Since the reaction is exothermic (\( \Delta H^{\circ} < 0 \)), increasing the temperature will shift the equilibrium to favor the reactants.
This is because the added heat "pushes" the system to absorb it by producing more reactants, thus decreasing the equilibrium constant \( K \). Le Chatelier's Principle helps predict how changing conditions such as temperature will affect the balance between products and reactants, allowing chemists to manipulate reaction conditions for desired outcomes.
Enthalpy and Entropy Changes
Enthalpy (\( \Delta H^{\circ} \)) and entropy (\( \Delta S^{\circ} \)) are two key parameters in thermodynamics that denote changes in heat content and disorder, respectively.
Enthalpy change signifies the heat absorbed or released in a reaction. A negative \( \Delta H^{\circ} \), like \(-48 \text{kJ/mol}\) in the iodination of ethylene, indicates an exothermic process, where heat is emitted.
Entropy change, on the other hand, measures the dispersal of energy within a system.
A negative value of \( \Delta S^{\circ} \) shows a decrease in system disorder, meaning the reaction results in a more ordered state.
Both these values contribute to determining the Gibbs free energy of the reaction and are pivotal in predicting reaction spontaneity and equilibrium properties. By combining these values, chemists deeply understand the thermodynamic favorability and feasibility of chemical processes.

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