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1-Methylcyclopentene gives a single compound \(\left(\mathrm{C}_{6} \mathrm{H}_{10} \mathrm{O}_{2}\right)\) on ozonolysis. What is it?

Short Answer

Expert verified
The compound is hexan-2,5-dione.

Step by step solution

01

Understand Ozonolysis

Ozonolysis is a reaction where ozone breaks down alkenes into carbonyl compounds, typically ketones or aldehydes. In this process, the carbon-carbon double bond is cleaved.
02

Analyze 1-Methylcyclopentene Structure

1-Methylcyclopentene is a cyclic alkene with a methyl group attached to the cyclopentene ring. This means it has one carbon-carbon double bond within the five-membered ring.
03

Draw the Structure of 1-Methylcyclopentene

Draw the cyclopentene ring and add a methyl group at the carbon adjacent to the double bond. The structure is a five-membered ring with a double bond and a methyl (CH鈧) substituent.
04

Predict the Ozonolysis Products

When the double bond in 1-Methylcyclopentene undergoes ozonolysis, it splits into two carbonyl groups. Given the formula C鈧咹鈧佲個O鈧, the molecule will form a six-carbon chain with two oxygen atoms indicating two carbonyl groups (likely aldehyde or ketone).
05

Identify the Single Compound Resulting from Ozonolysis

Considering the linear arrangement of carbons post-ozonolysis, the product is expected to be hexan-2,5-dione. The double bond of 1-Methylcyclopentene opens, forming a compound with two ketone groups on the second and fifth carbon atoms of a hexane chain.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

1-Methylcyclopentene
1-Methylcyclopentene is an organic compound classified as a cyclic alkene with a methyl group. It has a chemical formula of \( C_6H_{10} \). Being a cycloalkene, it features a five-membered carbon ring with a double bond between two of the carbon atoms. This characteristic double bond makes it reactive and versatile in various chemical reactions.
In this structure, the methyl group (\( CH_3 \)) is attached to one of the ring carbons, adjacent to the double-bonded atoms. Here's a simple breakdown:
  • The ring consists of five carbon atoms.
  • One double bond is present within the ring.
  • A methyl group is attached to the ring, branching out from the primary structure.
These features contribute to 1-Methylcyclopentene's reactivity, especially in reactions such as ozonolysis, where the double bond plays a crucial role.
Carbonyl Compounds
Carbonyl compounds are a significant class of organic molecules characterized by the presence of a carbon-oxygen double bond, \( C=O \). These compounds are widely found in nature and synthetic materials. Upon undergoing reactions like ozonolysis, compounds such as 1-Methylcyclopentene can transform into these carbonyl products.
Ozonolysis, in particular, cleaves the double bonds of alkenes and converts unsaturated substrates into carbonyls, which can be either aldehydes or ketones.
  • Aldehydes: The carbonyl group is bonded to at least one hydrogen atom.
  • Ketones: The carbonyl group is bonded to two carbon atoms.
These transformations are important for determining molecular frameworks and understanding chemical pathways. In the case of 1-Methylcyclopentene, the ozonolysis leads to a compound with two carbonyl groups, specifically forming a diketone, which is crucial for identifying the final product.
Organic Chemistry Reactions
Organic chemistry reactions are central to forming and breaking bonds within organic molecules. One of the key reactions in organic chemistry is ozonolysis, a process used to oxidatively cleave the carbon-carbon double bonds in alkenes and alkynes. This reaction is particularly useful for determining the structure of suspected unsaturated compounds by breaking them down into simpler, defined fragments.
During ozonolysis:
  • Ozone (\( O_3 \)) attacks the double bond of an alkene, forming an ozonide intermediate.
  • This intermediate is typically unstable and is further processed into carbonyl products in either oxidative or reductive environments.
With 1-Methylcyclopentene, ozonolysis cleaves its double bond, leading to straightforward identification and determination of the produced carbonyl compound as hexan-2,5-dione. This method showcases the utility of ozonolysis in organic synthesis, structural elucidation, and mechanistic studies of organic molecules.

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Most popular questions from this chapter

Oxymercuration-demercuration of allyl alcohol gives 1,2 -propanediol. Under the same conditions, however, 4 -penten-1-ol yields a compound having the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{O}\). What is the most reasonable structure for the product of this reaction?

When \((R)-3\) -buten-2-ol is treated with a peroxy acid, two stereoisomeric epoxides are formed in a \(60: 40\) ratio. The minor stereoisomer has the structure shown. (a) What is the structure of the major isomer? (b) What is the relationship between the two epoxides? Are they enantiomers or diastereomers? (c) What four stereoisomeric products are formed when racemic 3-buten-2-ol is epoxidized under the same conditions? How much of each stereoisomer is formed?

Write the structure of the major organic product obtained by hydroboration- oxidation of each of the following alkenes: (a) 2-Methylpropene (d) Cyclopentene (b) cis-2-Butene (e) 3-Ethyl-2-pentene

On being heated with a solution of sodium ethoxide in ethanol, compound \(\mathrm{A}\left(\mathrm{C}_{7} \mathrm{H}_{15} \mathrm{Br}\right)\) yielded a mixture of two alkenes \(\mathrm{B}\) and \(\mathrm{C}\), each having the molecular formula \(\mathrm{C}_{7} \mathrm{H}_{14}\). Catalytic hydrogenation of the major isomer \(\mathrm{B}\) or the minor isomer \(\mathrm{C}\) gave only 3 -ethylpentane Suggest structures for compounds \(A, B\), and \(C\) consistent with these observations.

Compound \(\mathrm{A}\left(\mathrm{C}_{7} \mathrm{H}_{15} \mathrm{Br}\right)\) is not a primary alkyl bromide. It yields a single alkene (compound \(\mathrm{B}\) ) on being heated with sodium ethoxide in ethanol. Hydrogenation of compound B yields 2,4-dimethylpentane. Identify compounds A and B

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