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Problem \(18.10\) asked you to write details of the mechanism describing formation of benzaldehyde diethyl acetal from benzaldehyde and ethanol. Write a stepwise mechanism for the acid hydrolysis of this acetal.

Short Answer

Expert verified
The acetal undergoes acid-catalyzed hydrolysis, releasing two ethanol molecules and forming benzaldehyde.

Step by step solution

01

Protonation of the Acetal

The acid hydrolysis of benzaldehyde diethyl acetal begins with the protonation of the acetal oxygen. Sulfuric acid (H鈧係O鈧) or another acid donates a proton (H鈦) to the oxygen atom of the diethyl acetal, resulting in the formation of a positively charged oxonium ion. This protonation increases the electrophilicity of the carbon connected to the acetal oxygen, making it more susceptible to nucleophilic attack.
02

Formation of the First Ethanol

Following protonation, the carbon-oxygen bond of one of the ethoxyl groups (O-CH鈧侰H鈧) breaks, leading to the formation of an ethanol molecule (CH鈧僀H鈧侽H) and a stabilized carbocation intermediate in which the central carbon now has a positive charge.
03

Proton Transfer to Carbocation

A molecule of water in the reaction acts as a nucleophile and attacks the positively charged carbocation, forming a hemiketal intermediate. This intermediate is then protonated again, typically at the hydroxyl group, forming a positively charged tetrahedral oxonium ion.
04

Release of Second Ethanol

Once again, the positively charged intermediate undergoes cleavage of another carbon-oxygen bond. This results in the release of the second ethanol molecule and the reformation of the oxonium ion.
05

Deprotonation to Form Benzaldehyde

Finally, the positively charged oxygen in the oxonium ion undergoes deprotonation, often facilitated by a base present in the solution, such as the conjugate base of the initial acid or another molecule of water. This results in the formation of the neutral benzaldehyde molecule as the end product of the hydrolysis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Protonation
Protonation is a critical initial step in many acid-catalyzed reactions, including the hydrolysis of acetals. In this context, the acetal oxygen atom, which is part of benzaldehyde diethyl acetal, accepts a proton from an acid, such as sulfuric acid (H鈧係O鈧). This process converts the neutral oxygen into a positively charged oxonium ion. The positive charge on the oxygen atom enhances the acetal's reactivity, particularly increasing the carbon's susceptibility next to the oxygen to undergo subsequent reactions. Protonation essentially primes the molecule for further transformations by increasing electrophilicity, making the carbon more attractive to nucleophiles.
Carbocation Formation
The formation of a carbocation is an essential step in the acetal hydrolysis mechanism. Following the protonation of the acetal oxygen, the C-O bond in an ethoxyl group breaks. This bond cleavage leads to the creation of ethanol and a carbocation intermediate at the central carbon atom. This carbon now lacks one pair of bonding electrons, resulting in a positively charged center known as a carbocation. The stability of the carbocation is crucial, as it allows for intermediates to form and reactions to proceed. Stabilizing factors can include resonance structures or hyperconjugation, depending on the molecular environment. In this case, the aromatic benzene ring can provide some stabilization through resonance effects.
Nucleophilic Attack
Once the carbocation is formed during the acetal hydrolysis, it becomes highly susceptible to nucleophilic attack. Because carbocations are electron-deficient, they readily accept electron pairs from nucleophiles. In this reaction, a water molecule acts as the nucleophile and donates a lone pair of electrons to the positively charged carbocation. This interaction forms a temporary structure known as a hemiketal. The molecule now includes a new carbon-oxygen bond but still carries a positive charge due to earlier protonation, reflecting the need for further transformations to reach a stable product.
Tetrahedral Intermediate
The next stage in acetal hydrolysis involves the formation of a tetrahedral intermediate. After the nucleophilic attack by the water molecule, the oxonium ion formed still retains a positive charge on the oxygen. To increase stability, another proton transfer occurs, often to one of the oxygen atoms, enhancing the ionic structure. This creates a tetrahedral configuration around the carbon atom initially bearing the carbocation. Having four substituents, this intermediate's geometry is bent and labile, ready for subsequent transformations. The tetrahedral intermediate is pivotal, as it precedes the cleavage of another C-O bond, culminating in the eventual formation of benzaldehyde.

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Most popular questions from this chapter

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