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Reaction of benzanilide \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NHCC}_{6} \mathrm{H}_{5}\right)\) with chlorine in acetic acid yields a mixture of two monochloro derivatives. Suggest reasonable structures for these two isomers.

Short Answer

Expert verified
The two isomers are para-chlorobenzanilide and ortho-chlorobenzanilide.

Step by step solution

01

Understand the Reactants and Conditions

We start by identifying the reactants: benzanilide, which has the formula \( ext{C}_6 ext{H}_5 ext{NHCOC}_6 ext{H}_5\), and chlorine in the presence of acetic acid. Chlorine can perform electrophilic aromatic substitution reactions.
02

Identify Active Sites for Chlorination

Since benzanilide consists of two benzene rings and an amide group (NHCO), we must assess where chlorine can substitute. The amide linkage connects these two benzene rings, which are sites for potential electrophilic substitution.
03

Consider Electron-Withdrawing and Donating Effects

Analyze the effect of the amide group on both rings: the group exhibits resonance and withdrawing effects on the attached ring, potentially deactivating the para and ortho positions. Meanwhile, the other ring behaves independently or symmetrically activated like a typical benzene without strong electron-withdrawing groups.
04

Predict the Chlorinated Isomers

Given the above influences, predict that monochlorination occurs at the ortho and para positions of both benzene rings. The amide nitrogen, while having a lone pair, generally doesn't reach these rings to activate them significantly, but the ortho and para positions bear enough partial positive charges for chlorination.
05

Determine the Two Isomers

The likely structures are: one where chlorine substitutes at the para position on one phenyl group, and one where chlorine substitutes at the para or ortho position on the other or same phenyl group. Therefore, the two isomers are para-chlorobenzanilide and ortho-chlorobenzanilide.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Monochlorination
In the process of monochlorination, only one chlorine atom is added into the organic compound structure. When talking specifically about benzanilide, the monochlorination involves the substitution of a hydrogen atom on the benzene ring with a chlorine atom. This is achieved through an electrophilic aromatic substitution reaction.

The conditions for this reaction involve chlorine acting as the electrophile and the aromatic structure of benzanilide providing the nucleophilic site. Under these circumstances, chlorine atoms don't just randomly attach. Instead, they prefer positions that are more electron-rich, typically the ortho or para positions relative to substituents already present on the benzene ring.
  • Chlorine acts as an electrophile, looking for electron-rich areas.
  • Benzanilide's benzene rings offer potential sites for substitution.
  • Monochlorination results in one chlorine atom substituted on the aromatic ring.
Benzanilide
Benzanilide is a compound characterized by its two benzene rings linked by an amide group. The structure can be represented as \(\mathrm{C}_6\mathrm{H}_5\mathrm{NHCOC}_6\mathrm{H}_5\). This molecule is notable for having an amide linkage, which plays a crucial role in determining how substitution reactions occur.

The amide group conveys special electronic effects over the benzene rings. It can withdraw or donate electrons due to resonance, thus altering the reactivity of those rings. Specifically, the amide group withdraws electron density, making it less reactive toward electrophiles in the ortho and para positions. However, the effect isn't strong enough to stop reactions altogether, which makes sites at the ortho and para what we should focus on when predicting reaction outcomes.
  • Composed of two benzene rings and an amide group.
  • Amide group affects electron distribution on benzene rings.
  • Positions like ortho and para are less reactive but are still frequent sites for reactions.
Isomer Identification
In the context of chemical reactions, particularly with benzanilide monochlorination, identifying isomers means recognizing where chlorine atoms attach on the benzene rings. For benzanilide, after chlorination, one gets a mixture of products. The task is to determine which derivatives, or isomers, are formed.

Through the process of electrophilic aromatic substitution, benzanilide can form two primary isomers:
  • Ortho-chlorobenzanilide
  • Para-chlorobenzanilide
These names reveal the position of the chlorine atoms relative to the amide group. When chlorine attaches to the ortho position—as close as possible—the compound becomes ortho-chlorobenzanilide. Conversely, para-chlorobenzanilide occurs when the substitution happens opposite the amide group. Recognizing these isomers involves understanding the spatial orientation of the benzene rings and how they interact with the introduced chlorines.

Identifying them is crucial because even small differences in atomic arrangement affect the entire molecule's chemical properties and reactivity profile. By understanding the positioning, one can predict how these compounds might behave in further reactions.

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Most popular questions from this chapter

Give reagents suitable for carrying out each of the following reactions, and write the major organic products. If an ortho, para mixture is expected, show both. If the meta isomer is the expected major product, write only that isomer. (a) Nitration of nitrobenzene (b) Bromination of toluene (c) Bromination of (trifluoromethyl) benzene (d) Sulfonation of anisole (e) Sulfonation of acetanilide \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{NHCCH}_{3}\right)\) (f) Chlorination of bromobenzene (g) Friedel-Crafts alkylation of anisole with benzyl chloride (h) Friedel-Crafts acylation of benzene with benzoyl chloride \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CCl}\right)\) (i) Nitration of the product from part (h) (i) Clemmensen reduction of the product from part (h) (k) Wolff-Kishner reduction of the product from part (h)

1.2.3.4.5-Pentafluoro-6-nitrobenzene reacts readily with sodium methoxide in methanol at room temperature to yield two major products, each having the molecular formula \(\mathrm{C}_{7} \mathrm{H}_{3} \mathrm{~F}_{4} \mathrm{NO}_{3}\). Suggest reasonable structures for these two compounds.

Sulfonation of naphthalene is reversible at elevated temperature. A different isomer of naphthalenesulfonic acid is the major product at \(160^{\circ} \mathrm{C}\) than is the case at \(0^{\circ} \mathrm{C}\). Which isomer is the product of kinetic control? Which one is formed under conditions of thermodynamic control? Can you think of a reason why one isomer is more stable than the other?

Use curved arrows to show the formation of the cyclohexadienyl cation in the Friedel-Crafts a kylation of benzene with the electrophile formed from ethyl chloride and \(\mathrm{AlCl}_{3}\).

Write equations showing how you could prepare each of the following from anisole and any necessary organic or inorganic reagents. If an ortho, para mixture is formed in any step of your synthesis, assume that you can separate the two isomers. (a) \(p\) -Methoxybenzenesulfonic acid (b) 2-Bromo-4-nitroanisole (c) 4 -Bromo-2-nitroanisole (d) \(p\) -Methoxystyrene

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