/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Nitration of 1,4 -dimethylbenzen... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Nitration of 1,4 -dimethylbenzene ( \(p\) -xylene) gives a single product having the molecular formula \(\mathrm{C}_{8} \mathrm{H}_{9} \mathrm{NO}_{2}\) in high yield. What is this product?

Short Answer

Expert verified
The product is 2-nitro-1,4-dimethylbenzene.

Step by step solution

01

Identify the Starting Material

The nitration reaction starts with 1,4-dimethylbenzene, commonly known as \( p \)-xylene. The structure of \( p \)-xylene includes a benzene ring with two methyl groups attached to positions 1 and 4.
02

Understand the Nitration Reaction

Nitration typically involves the substitution of a hydrogen atom on an aromatic ring with a nitro group \( \text{-NO}_2 \). This process usually involves the use of a mixture of concentrated nitric acid and sulfuric acid.
03

Determine the Product of Nitration on \( p \)-xylene

The nitration reaction on \( p \)-xylene would predominantly occur at the position which is para or ortho to the methyl groups. Since both methyl groups are already \( para \) to each other, the most favorable position for nitration is \( ortho \) to one of the methyl groups due to the electron-donating nature of the methyl groups enhancing reactivity.
04

Confirm the Molecular Formula of the Product

The molecular formula \( \mathrm{C}_{8} \mathrm{H}_{9} \mathrm{NO}_{2} \) fits with the introduction of a single nitro group to the aromatic structure of \( p \)-xylene. The remaining structure is a benzene ring with two methyl groups and one nitro group.
05

Structure of the Nitrated Product

Thus, the resulting product is 2-nitro-1,4-dimethylbenzene. The nitro group is at position 2, which is ortho to one of the methyl groups.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Aromatic Substitution
In the context of chemistry, an aromatic substitution reaction involves replacing an atom, typically a hydrogen, on an aromatic ring with another atom or group.

Aromatic compounds are often stable due to their resonance structures, which makes substitution rather than addition or elimination, a common reaction type for them.
  • One of the key characteristics of aromatic rings is the delocalized pi electron cloud that contributes to the ring’s stability.
  • Substituents attached to the aromatic ring can influence the positions at which new substitutions occur, as they can either donate electrons to the ring or withdraw electrons from the ring.
  • Activating groups like alkyl groups increase the reactivity of the compound by donating electron density into the ring, which makes it easier for attacks by electrophiles.
An aromatic substitution reaction includes electrophilic substitution where a strong electrophile replaces a hydrogen atom in the aromatic ring.
Replacing a hydrogen atom on the benzene ring of p-xylene with another group like a nitro group is an excellent example of electrophilic aromatic substitution. This is the guiding principle behind nitration reactions.
Electrophilic Nitration
The nitration reaction is a type of electrophilic aromatic substitution reaction where a nitro group (\(\text{–NO}_2\)) replaces a hydrogen atom on the aromatic ring.

This reaction is crucial in the manufacturing of various aromatic compounds.
  • The nitration process utilizes a mixture of concentrated nitric acid, \(\text{HNO}_3\), and concentrated sulfuric acid, \(\text{H}_2\text{SO}_4\), to generate the nitronium ion \(\text{NO}_2^+\), which is a powerful electrophile.
  • The \(\text{NO}_2^+\) ion attacks the electron-rich aromatic ring in a substitution reaction, replacing one of the hydrogen atoms with a nitro group.
  • This set of reactions generally occurs at low temperatures to prevent further unwanted reactions or the decomposition of the nitro compound formed.
In p-xylene, the methyl groups act as ortho/para directors which enhance the rate of reaction by stabilizing the intermediate carbocation. This makes the ortho position most reactive for substitution.
P-Xylene
P-Xylene is an aromatic hydrocarbon or arene that plays an essential role in organic chemistry reactions such as nitration.

It is a derivative of benzene, with the chemical formula \(\text{C}_8\text{H}_{10}\), and includes two methyl groups attached to the benzene ring at equal intervals, specifically at the para positions which are opposite each other.
  • The structure of p-xylene is advantageous for substitution reactions as the two methyl groups are electron-releasing, increasing the ring's electron density and facilitating electrophilic attack.
  • This ortho/para directing effect of the methyl groups strongly influences the outcome of electrophilic aromatic substitution reactions, such as in the production of nitro aromatics.
  • In the nitration of p-xylene, due to steric and electronic factors, the most favored site is ortho to one of the methyl groups, resulting in high yields of 2-nitro-1,4-dimethylbenzene.
Overall, the unique chemical structure of p-xylene makes it an interesting subject in studying substitution mechanisms and their outcomes in aromatic chemistry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Friedel-Crafts acylation of the individual isomers of xylene with acetyl chloride and aluminum chloride yields a single product, different for each xylene isomer, in high yield in each case. Write the structures of the products of acetylation of \(0-, m-\), and \(p\) -xylene.

Use curved arrows to show the formation of the cyclohexadienyl cation in the Friedel-Crafts a kylation of benzene with the electrophile formed from ethyl chloride and \(\mathrm{AlCl}_{3}\).

On being heated with sulfur trioxide in sulfuric acid, \(1,2,4,5\) -tetramethy benzene was converted to a product of molecular formula \(\mathrm{C}_{10} \mathrm{H}_{14} \mathrm{O}_{3} \mathrm{~S}\) in \(94 \%\) yield. Suggest a reasonable structure for this product.

Write the structure of the expected product from the reaction of 1-chloro-2,4-dinitrobenzene with each of the following reagents: (a) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{ONa}\) (b) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{SNa}\) (c) \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) Sample Solution (a) Sodium ethoxide is a source of the nucleophile \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{O}^{-}\), which d splaces chloride from 1-chloro-2,4-dinitrobenzene.

The compounds benzyl chloride \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{2} \mathrm{Cl}\right)\), (dichloromethyl)benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH} \mathrm{Cl}_{2}\right)\), and (trichloromethyl)benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CCl}_{3}\right)\) all undergc nitration more slowly than benzene. The proportion of m-nitro-substituted product is \(4 \%\) in one, \(34 \%\) in another, and \(64 \%\) in another. Classify the substituents \(-\mathrm{CH}_{2} \mathrm{Cl},-\mathrm{CHCl}_{2}\), and \(-\mathrm{CCl}_{3}\) according to each one's effect on rate and regioselectivity in electrophilic aromatic substitution.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.