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Hydrogen cyanide \((\mathrm{HCN})\) has a \(\mathrm{pK}_{\mathrm{a}}\) of \(9.1\). What is its \(K_{\mathrm{a}} ?\)

Short Answer

Expert verified
The \\(K_{\mathrm{a}}\\) of HCN is approximately \\ 7.94 \times 10^{-10}\\.

Step by step solution

01

Understanding the relationship between pKa and Ka

The relationship between \(\mathrm{pK}_{\mathrm{a}}\) and \(K_{\mathrm{a}}\) is given by the formula: \[\mathrm{pK}_{\mathrm{a}} = -\log_{10}(K_{\mathrm{a}})\]\ This equation can be rearranged to find \(K_{\mathrm{a}}\) by taking the inverse of the logarithm.
02

Rearranging the formula to solve for Ka

To find \(K_{\mathrm{a}}\), we need to rearrange the formula: \[K_{\mathrm{a}} = 10^{-\mathrm{pK}_{\mathrm{a}}}\] This allows us to substitute the given value of \(\mathrm{pK}_{\mathrm{a}}\) and calculate \(K_{\mathrm{a}}\).
03

Substituting the value of pKa

Substitute \(\mathrm{pK}_{\mathrm{a}} = 9.1\) into the rearranged formula: \[K_{\mathrm{a}} = 10^{-9.1}\] This step gives us the value of \(K_{\mathrm{a}}\) using the power of 10.
04

Calculating Ka

Calculate \(K_{\mathrm{a}}\) by evaluating the expression: \[K_{\mathrm{a}} = 10^{-9.1} \approx 7.94 \times 10^{-10}\] This represents the acid dissociation constant for hydrogen cyanide.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

pKa and Ka relationship
In chemistry, understanding the relationship between \( \mathrm{pK}_a \) and \( K_a \) is crucial for assessing the strength of an acid. \( \mathrm{pK}_a \) and \( K_a \) are both measures of acid strength, but they are expressed differently.
\( \mathrm{pK}_a \) stands for the "logarithmic acid dissociation constant". It's calculated as the negative base-10 logarithm of \( K_a \), the acid dissociation constant. The equation is: \[\mathrm{pK}_a = -\log_{10}(K_a)\] This means the lower the \( \mathrm{pK}_a \) value, the stronger the acid, as more of the acid dissociates in solution. Conversely, a higher \( \mathrm{pK}_a \) suggests a weaker acid.
When you know the \( \mathrm{pK}_a \), you can find \( K_a \) using the equation: \[K_a = 10^{-\mathrm{pK}_a}\] This inverse relationship holds the key to switching between the two metrics, helping chemists compare acids directly.
logarithmic calculations in chemistry
Logarithms are a powerful mathematical tool used widely in chemistry to simplify multiplicative relationships. The use of logarithms allows large or small numbers to be expressed more concisely and makes data processing easier. When dealing with acids, chemists often use logarithms to calculate acid strength.
The logarithmic scale is especially handy in dealing with \( K_a \), since these constants can have very large or very small values. Using the \( \mathrm{pK}_a \) empowers chemists to express such extremes in a manageable way because:
  • It condenses lengthy calculations into simpler arithmetic operations.
  • It translates multiplicative relationships into addition and subtraction.
  • It provides a toolkit for handling different orders of magnitude.
When you calculate \( K_a \) from \( \mathrm{pK}_a \) using logarithmic equations, you reverse the process: Start with \( \mathrm{pK}_a = 9.1 \) and convert with: \[K_a = 10^{-9.1}\] This converts the logarithmic value back to a standard mathematical expression.
hydrogen cyanide
Hydrogen cyanide, often represented as \( HCN \), is a weak acid known for its low dissociation in water. It's a volatile and colorless compound, usually noted by its slight odor of almonds.
The \( \mathrm{pK}_a \) value of \( HCN \) is approximately 9.1, indicating it's not a particularly strong acid. In an aqueous solution, it does not dissociate into ions as readily as stronger acids do.
  • The \( K_a \) value of hydrogen cyanide, about \( 7.94 \times 10^{-10} \) (calculated from \( 10^{-9.1}\)), underscores this weakness in dissociation.
  • This means that in a balanced aqueous environment, most \( HCN \) molecules stay intact.
  • Understanding these properties is essential, as HCN is not only relevant in theoretical chemistry but also in real-world applications, ranging from its use in industrial processes to its notorious history in human toxicology.
Hydrogen cyanide serves as a meaningful example of how \( \mathrm{pK}_a \) and \( K_a \) can be used to measure and describe acid strength.

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Most popular questions from this chapter

In each of the following pairs, determine whether the two represent resonance contributors of a single species or depict different substances. If two structures are not resonance contributors, explain why. (a) \(: \ddot{\mathrm{N}}-\mathrm{N} \equiv \mathrm{N}: \quad\) and \(\quad: \mathrm{N}=\mathrm{N}=\mathrm{N}\) (c) \(: \ddot{\mathrm{N}}-\mathrm{N} \equiv \mathrm{N}: \quad\) and \(\quad: \ddot{\mathrm{N}}-\ddot{\mathrm{N}}-\ddot{\mathrm{N}}\) : (b) \(: \ddot{\mathrm{N}}-\mathrm{N} \equiv \mathrm{N}: \quad\) and \(\quad: \ddot{\mathrm{N}}-\mathrm{N}=\ddot{\mathrm{N}}\) :

What is the electron configuration of \(\mathrm{C}^{+} ?\) Of \(\mathrm{C}^{-} ?\) Does either one of these ions have a noble gas (closed-shell) electron configuration?

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