Chapter 10: Problem 27
Photochemical chlorination of \(2,2,4\) -trimethylpentane gives four isomeric monochlorides. (a) Write structural formulas for these four isomers. (b) The two primary chlorides make up \(65 \%\) of the monochloride fraction. Assuming that all the primary hydrogens in \(2,2,4\) -trimethylpentane are equally reactive, estimate the percentage of each of the two primary chlorides in the product mixture.
Short Answer
Step by step solution
Identify the Structure of 2,2,4-Trimethylpentane
Identify the Types of Hydrogen Atoms
Identify Possible Monochloride Isomers
Write Structural Formulas for Monochloride Isomers
Calculate the Percentage of Each Primary Chloride
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
2,2,4-Trimethylpentane
Isooctane is notable in industries such as petroleum because of its high octane rating, which means it burns more efficiently in engines. The structural formula can be depicted as: CH\(_3\)-C(CH\(_3\))\(_2\)-CH\(_2\)-CH(CH\(_3\))-CH\(_3\). This specific arrangement of carbons and hydrogens contribute significantly to its unique reactivity, especially in photochemical reactions such as chlorination.
Monochloride Isomers
- Primary Monochlorides: Two isomers result from chlorine substituting a primary hydrogen on the terminal carbon atoms. These isomers have structural differences based on which specific hydrogen is replaced.
- Secondary Monochloride: Formed when chlorine substitutes a secondary hydrogen, providing another unique structural variation.
- Tertiary Monochloride: Not applicable here as there are no tertiary hydrogens present in 2,2,4-Trimethylpentane's structure.
Primary and Secondary Hydrogens
Primary hydrogens are bonded to a terminal carbon, found mostly in the methyl groups on the periphery. In this molecule, there are nine such primary hydrogens.
- The majority lie in the terminal methyl groups, with six in total from these groups alone.
- An additional three are attached to the quaternary carbon's methyl group.
Tertiary hydrogens are not present in this molecule, as no hydrogen is bonded to a tertiary carbon atom within the structure. This absence further simplifies the potential isomers during chlorination.
Chlorination Reaction Mechanism
- Initiation: The reaction starts when ultraviolet light breaks the Cl-Cl bond in a chlorine molecule, producing two highly reactive chlorine radicals.
- Propagation: These chlorine radicals are key players, attacking hydrogen atoms in 2,2,4-trimethylpentane to produce hydrogen chloride and a carbon radical. The carbon radical is then free to react with another chlorine molecule, forming a monochloride and another chlorine radical, continuing the chain reaction.
- Termination: Eventually, these steps culminate when radicals combine, stopping the chain reaction, and stabilizing the system by forming products like monochlorides.