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Give the equations and mechanisms for the reactions of sodium methyl acetylide with: (a) 1-bromobutane (b) 2-bromobutane.

Short Answer

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The reactions of sodium methyl acetylide with: a) 1-bromobutane: Equation: \( CH鈧僀鈮Na + CH鈧僀H鈧侰H鈧侰H鈧侭r 鈫 CH鈧僀鈮CH鈧侰H鈧侰H鈧侰H鈧 + NaBr \) Mechanism (SN2): \( CH鈧僀鈮鈦 + CH鈧僀H鈧侰H鈧侰H鈧侭r 鈫 CH鈧僀鈮CH鈧侰H鈧侰H鈧侰H鈧 + Br鈦 \) Product: 5-methyl-1-pentyne b) 2-bromobutane: Equation: \( CH鈧僀鈮Na + CH鈧僀HBrCH鈧侰H鈧 鈫 CH鈧僀鈮CH(CH鈧)CH鈧侰H鈧 + NaBr \) Mechanism (SN2): \( CH鈧僀鈮鈦 + CH鈧僀HBrCH鈧侰H鈧 鈫 CH鈧僀鈮CH(CH鈧)CH鈧侰H鈧 + Br鈦 \) Product: 4-methyl-3-hexyne

Step by step solution

01

Identify the nucleophile and electrophile

In this reaction, sodium methyl acetylide (CH3C鈮Na) is the nucleophile while 1-bromobutane (CH3CH2CH2CH2Br) is the electrophile.
02

Write the reaction equation

The reaction equation for the nucleophilic substitution of 1-bromobutane with sodium methyl acetylide is: CH鈧僀鈮Na + CH鈧僀H鈧侰H鈧侰H鈧侭r 鈫 CH鈧僀鈮CH鈧侰H鈧侰H鈧侰H鈧 + NaBr
03

Describe the mechanism for the reaction

The mechanism for the reaction is an SN2 mechanism, which involves a single concerted step. The nucleophile (sodium methyl acetylide) attacks the electrophile (1-bromobutane) at the carbon atom bonded to the bromine atom. The bromine atom is then expelled as a leaving group. The mechanism can be represented as: 1) CH鈧僀鈮鈦 + CH鈧僀H鈧侰H鈧侰H鈧侭r 鈫 CH鈧僀鈮CH鈧侰H鈧侰H鈧侰H鈧 + Br鈦 or with the sodium ions: 1) CH鈧僀鈮Na + CH鈧僀H鈧侰H鈧侰H鈧侭r 鈫 CH鈧僀鈮CH鈧侰H鈧侰H鈧侰H鈧 + NaBr The product formed is 5-methyl-1-pentyne. #b) Sodium methyl acetylide with 2-bromobutane#
04

Identify the nucleophile and electrophile

In this reaction, sodium methyl acetylide (CH3C鈮Na) is the nucleophile while 2-bromobutane (CH鈧僀HBrCH鈧侰H鈧) is the electrophile.
05

Write the reaction equation

The reaction equation for the nucleophilic substitution of 2-bromobutane with sodium methyl acetylide is: CH鈧僀鈮Na + CH鈧僀HBrCH鈧侰H鈧 鈫 CH鈧僀鈮CH(CH鈧)CH鈧侰H鈧 + NaBr
06

Describe the mechanism for the reaction

The mechanism for the reaction is also an SN2 mechanism, involving a single concerted step. The nucleophile (sodium methyl acetylide) attacks the electrophile (2-bromobutane) at the carbon atom bonded to the bromine atom. The bromine atom is expelled as a leaving group. The mechanism can be represented as: 1) CH鈧僀鈮鈦 + CH鈧僀HBrCH鈧侰H鈧 鈫 CH鈧僀鈮CH(CH鈧)CH鈧侰H鈧 + Br鈦 or with the sodium ions: 1) CH鈧僀鈮Na + CH鈧僀HBrCH鈧侰H鈧 鈫 CH鈧僀鈮CH(CH鈧)CH鈧侰H鈧 + NaBr The product formed is 4-methyl-3-hexyne.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nucleophilic Substitution
Nucleophilic substitution reactions are a critical concept in organic chemistry. They involve the replacement of an atom or group in a molecule with a nucleophile. A nucleophile is a species that donates an electron pair to an electrophile. In the context of SN2 reactions, where "S" stands for "substitution," "N" stands for "nucleophilic," and "2" denotes that the reaction is bimolecular, both the nucleophile and the substrate are involved in the rate-determining step. SN2 reactions are favored by strong nucleophiles and proceed in a single step, with a transition state where the bonds are partially broken and formed simultaneously. This leads to an inversion of stereochemistry, often referred to as a "back-side attack" by the nucleophile.
Sodium Methyl Acetylide
Sodium methyl acetylide is a strong nucleophile, made up of sodium (Na) and methyl acetylide (CH鈧僀鈮鈦). It consists of a negatively charged acetylide ion, which is highly reactive due to the presence of the triple bond between the carbon atoms. This high energy state makes sodium methyl acetylide an effective nucleophile in SN2 reactions. The sodium cation (Na鈦) stabilizes the acetylide anion, making it more conducive for nucleophilic attacks. It is commonly used in organic reactions to transform alkyl halides into alkynes, adding a new dimension to synthetic organic chemistry.
1-Bromobutane
1-Bromobutane serves as a classic substrate in nucleophilic substitution reactions, particularly those undergoing the SN2 mechanism. It is a primary alkyl halide, which means that the bromine atom is attached to a primary carbon, or a carbon bound to just one other carbon. This position makes 1-bromobutane more accessible for nucleophilic attack, as there is less steric hindrance compared to secondary or tertiary carbon centers. The bromine atom acts as a leaving group, which, once expelled, enables the formation of a new carbon-carbon bond between the nucleophile and the substrate.
2-Bromobutane
2-Bromobutane is a secondary alkyl halide, meaning the bromine is bound to a carbon atom that is attached to two other carbon atoms. This structural change introduces more steric hindrance compared to 1-bromobutane, affecting the potential reaction pathways. In an SN2 reaction with sodium methyl acetylide, the nucleophile has a more challenging pathway due to the increased crowding around the electrophilic center. Despite this, the reaction still proceeds as an SN2 mechanism, facilitated by the strong nucleophilic character of sodium methyl acetylide. The reaction outcomes in the formation of new carbon-carbon bonds, leading to the production of more complex organic molecules.

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