Chapter 6: Problem 116
Describe dehydration of alcohols to obtain an alkene.
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Chapter 6: Problem 116
Describe dehydration of alcohols to obtain an alkene.
These are the key concepts you need to understand to accurately answer the question.
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Consider the feasibility of a free-radical chain mechanism for hydrogenation of ethylene in the vapor state at \(25^{\circ}\) by the following propagation steps: $$ \begin{aligned} &\mathrm{CH}_{3}-\mathrm{CH}_{2}+\mathrm{H}_{2} \rightarrow \mathrm{CH}_{3}-\mathrm{CH}_{3}+\mathrm{H} \\ &\mathrm{CH}_{2}=\mathrm{CH}_{2}+\mathrm{H} \cdot \rightarrow \mathrm{CH}_{3} \mathrm{CH}_{2} \end{aligned} $$
Synthesize pentane from 2,3 -dibromopentane using any inorganic reagents.
When ethylene is alkylated by isobutane in the presence of acid, there is obtained not neohexane, \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{CCH}_{2} \mathrm{CH}_{3}\), but chiefly 2,3 -dimethylbutane. Account in detail for the formation of this product.
How are alkenes prepared?
In the dark at room temperature, a solution of chlorine in tetrachloroethylene can be kept for long periods with no sign of reaction. When irradiated with ultraviolet light, however, the clorine is rapidly consumed, with the formation of hexachloroethane; many molecules of product are formed for each photon of light absorbed, and the reaction; is slowed down markedly when oxygen is bubbled through the solution. (a) How do you account for the absence of reaction in the dark? (b) Outline all steps in the most likely mechanism for the photochemical reaction. Show how it accounts for the facts, including the effect of oxygen.
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