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A substance reacts according to first-order kinetics. The rate constant for the reaction is \(1 \times 10^{-2} \mathrm{sec}^{1} .\) Its initial concentration is IM. Its initial rate is: (a) \(2 \times 10^{2} \mathrm{Ms}^{-1}\) (b) \(1 \times 10^{2} \mathrm{Ms}^{-1}\) (c) \(1 \times 10^{-2} \mathrm{Ms}^{-1}\) (d) \(2 \times 10^{-2} \mathrm{Ms}^{-1}\)

Short Answer

Expert verified
(c) \(1 \times 10^{-2} \mathrm{Ms^{-1}}\)

Step by step solution

01

Understanding First-Order Kinetics

In first-order kinetics reactions, the rate is directly proportional to the concentration of the reactant. The rate law expression is given by the formula \( rate = k[A] \) where \( rate \) is the reaction rate, \( k \) is the rate constant, and \( [A] \) is the concentration of the reactant.
02

Applying Rate Law

For the given problem, we know the rate constant \( k = 1 \times 10^{-2} \mathrm{sec^{-1}} \) and the initial concentration \( [A] = 1M \) (IM). Substituting these values into the rate law equation gives us \( rate = (1 \times 10^{-2} \mathrm{sec^{-1}})(1M) \) which simplifies to \( rate = 1 \times 10^{-2} \mathrm{Ms^{-1}} \).
03

Selecting the Correct Answer

Comparing the calculated rate with the given options, the correct answer is \( (c) 1 \times 10^{-2} \mathrm{Ms^{-1}} \) because it matches the rate we calculated.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Rate
When delving into the kinetics of chemical reactions, the concept of reaction rate is fundamental. It represents the speed at which reactants are consumed and products are formed over time. A more technical definition might explain reaction rate as the change in the concentration of reactants or products per unit of time. For example, if we begin with a high concentration of reactants, the reaction rate will initially be high; as the reaction proceeds and reactant concentrations decrease, the rate typically lessens as well.

Understanding this concept is crucial for many applications in chemistry, from industrial synthesis to biochemical reactions within our own bodies. It is expressed mathematically as the derivative of concentration with respect to time, emphasized as \( \dfrac{d[A]}{dt} \), where \( [A] \) is the concentration of a reactant.

In our exercise, we comprehend that as part of first-order kinetics, the reaction rate is directly proportional to the concentration of the reactant alone, which significantly simplifies the process of determining the rate.
Rate Constant
The rate constant, symbolized by \( k \), plays a pivotal role in the quantitative analysis of reaction speeds and mechanisms. It is a proportionality factor that connects the reaction rate to the concentrations of reactants as explained by the rate law. The makeup of \( k \) includes both the inherent characteristics of the reaction itself, like the activation energy and temperature dependency, along with external influences, encompassing solvent conditions or the presence of catalysts.

In our case of first-order kinetics, the rate constant has a specific significance, as it remains constant irrespective of the concentration of the reactant and only alters with temperature or when a catalyst is introduced.

To compute the initial rate, we use the exact value of the rate constant provided in the problem and multiply it by the reactant concentration—resulting in a straightforward calculation reflecting the central role of the rate constant in determining reaction speed.
Chemical Kinetics
Chemical kinetics is the branch of chemistry that deals with the rates of chemical reactions and the factors affecting those rates. It is a wide field that encompasses the understanding of precisely how reactions occur at the molecular level. Kinetics can explain the influence of different variables such as concentration, temperature, and catalysts on the reaction rate.

Within this field, reaction orders play a crucial aspect in defining how the rate reacts to changes in concentration. In first-order reactions, as is demonstrated in our exercise, the reaction rate depends linearly on the concentration of one reactant. Knowing this helps us not only to predict how a reaction will progress over time but also to control the reaction to suit our needs whether that’s in manufacturing, pharmaceuticals, or environmental applications.

By applying chemical kinetics, we can design experiments to measure reaction rates, analyze data to determine reaction order and rate constant, and finally, utilize that knowledge for practical uses such as the development of new materials and preservation methods, or the design of drugs and other therapies.

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Most popular questions from this chapter

A graph plotted between concentration of reactant, consumed at any time ( \(\mathrm{x}\) ) and time ' \(\mathrm{t}\) ' is found to be a straight line passing through the origin. The reaction is of: (a) First-order (b) Zero-order (c) Third-order (d) Second-order

Which of the following best explains the effects of a catalyst on the rate of a reversible reaction? (a) It decreases the rate of the reverse reaction (b) It increases the kinetic energy of the reacting mol ecules (c) It moves the equilibrium position to the right (d) It provides a new reaction path with a lower activation energy

The temperature dependence of rate constant (A) of a chemical reaction is written in terms of Arrhenius equation, \(=\mathrm{A} \cdot \mathrm{e}^{-\mathrm{E} / \mathrm{RT}}\), Activation energy \(\mathrm{E}_{3}\) of the reaction can be calculated by ploting: (a) \(\log \mathrm{k} \operatorname{vs} \mathrm{T}^{-1}\) (b) \(\log \mathrm{k} \mathrm{vs} \frac{1}{\log \mathrm{T}}\) (c) \(k \operatorname{vs} \mathrm{T}\) (d) \(\mathrm{k} \mathrm{vs} \frac{1}{\log \mathrm{T}}\)

In a first-order reaction \(\mathrm{A} \longrightarrow \mathrm{P}\), the ratio of \(\mathrm{a} /(\mathrm{a}-\mathrm{x})\) was found to be 8 after 60 minutes. If the concentration is \(0.1 \mathrm{M}\) then the rate of reaction in moles of A reacted per minutes is: (a) \(2.226 \times 10^{-3}\) mol litre \(^{-1} \min ^{-1}\) (b) \(3.466 \times 10^{-3}\) mol litre \(^{-1} \min ^{-1}\) (c) \(4.455 \times 10^{-3}\) mol litre \(^{-1} \min ^{-1}\) (d) \(5.532 \times 10^{-3}\) mol litre \(^{-1} \mathrm{~min}^{-1}\)

In a second-order reaction, if first-order is observed for both the reactants \(\mathrm{A}\) and \(\mathrm{B}\), then which one of the following reactant mixtures will provide the highest initial rate? (a) \(0.1\) mol of \(A\) and \(0.1\) mol of in \(0.2\) litre solvent (b) \(1.0 \mathrm{~mol}\) of \(\mathrm{A}\) and \(1.0 \mathrm{~mol}\) of in one litre solvent (c) \(0.2\) mol of \(A\) and \(0.2\) mol of in \(0.1\) litre solvent (d) \(0.1\) mol of \(\mathrm{A}\) and \(0.1\) mol of in \(0.1\) litre solvent

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