Chapter 4: Problem 50
Which one of the following is the correct set with reference to molecular formula, hybridization of central atom and shape of the molecule? (a) \(\mathrm{CO}_{2}, \mathrm{sp}^{2}\), bent (b) \(\mathrm{H}_{2} \mathrm{O}, \mathrm{sp}^{2}\), bent (c) \(\mathrm{BeCl}_{2}\), sp, linear (d) \(\mathrm{H}_{2} \mathrm{O}, \mathrm{sp}^{3}\), linear
Short Answer
Step by step solution
Analyze Option (a)
Analyze Option (b)
Analyze Option (c)
Analyze Option (d)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Hybridization
For instance, in the case of \(\small{\mathrm{CO}_2}\), the central atom, carbon, forms two double bonds with oxygen. Despite each double bond containing one sigma and one pi-bond, only the sigma bonds count towards hybridization. With no lone pairs on carbon, the hybridization is \(\mathrm{sp}\), indicating a linear shape due to the 180° bond angle.
In contrast, water (\(\small{\mathrm{H}_2\mathrm{O}}\)) has an oxygen central atom with two sigma bonds and two lone pairs. This arrangement results in \(\mathrm{sp}^3\) hybridization despite having only two bonded atoms. This type of hybrid orbitals makes the molecular shape bent, deviating slightly from 109.5° to about 104.5° due to lone pair-bond pair repulsion.
Hybridization is crucial in determining both the geometry and properties of molecules, thus providing insightful predictions about molecular behavior.
Molecular Shape
For example, \(\small{\mathrm{CO}_2}\) has a linear shape because of its \(\mathrm{sp}\) hybridization and symmetrical distribution of bonding pairs around carbon. Each oxygen atom forms a double bond with carbon, leading to a 180° angle between the atoms.
- Linear Geometries: Seen when there are two regions of electron density, often leading to a 180° bond angle.
Alternatively, the water molecule, \(\small{\mathrm{H}_2\mathrm{O}}\), exhibits a bent shape because of the \(\mathrm{sp}^3\) hybridization and the presence of two lone pairs on the oxygen. The repulsion caused by the lone pairs compresses the bond angle to approximately 104.5°.
- Bent Structures: Occur when there are lone pairs exerting repulsive forces, decreasing bond angles.
Sigma Bonds
In the molecule \(\small{\mathrm{CO}_2}\), carbon forms two sigma bonds, one with each oxygen. Despite each being part of a double bond, only the sigma component is considered in hybridization, leading to the \(\mathrm{sp}\) hybrid arrangement;
while in \(\small{\mathrm{H}_2\mathrm{O}}\), the oxygen atom is involved in two sigma bonds with the hydrogen atoms. Alongside \sp^3 hybrid orbitals,
the sigma bonds ensure the bent shape of the molecule.
- Characteristics of Sigma Bonds:
- Formed by direct orbital overlap.
- Allows free rotation of bonded atoms.
- Strong and stable, usually forming the base for more complex interactions like pi-bonds.