Chapter 1: Problem 63
What is the molarity of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) solution that has a density \(1.84 \mathrm{~g} / \mathrm{cc}\) at \(35^{\circ} \mathrm{C}\) and contains \(98 \% \mathrm{H}_{2} \mathrm{SO}_{4}\) by weight? (a) \(1.84 \mathrm{M}\) (b) \(81.4 \mathrm{M}\) (c) \(18.4 \mathrm{M}\) (d) \(184 \mathrm{M}\)
Short Answer
Step by step solution
Understanding the Given Data
Calculate Mass of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) in 1 L
Calculate Molarity Using Molar Mass
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Density
To understand a solution's density practically, imagine comparing the weight of a cup filled with feathers versus the same cup filled with rocks. The cup of rocks would weigh more because rocks are denser than feathers. Similarly, a solution's density can help us determine the solution's total mass, which is crucial for calculating concentrations and molarities in chemistry.
Percentage Concentration
Percentage by weight is a straightforward way to communicate how concentrated a solution is. It's crucial in industrial applications and laboratory settings where precise measurements of chemicals are needed for reactions or testing. Having a high percentage means the solute constitutes a significant portion of the solution, affecting the outcome of various chemical processes.
Molar Mass
For sulfuric acid \(\mathrm{H}_{2}\mathrm{SO}_{4}\), the molar mass is approximately 98.08 g/mol. Calculating this involves adding the atomic masses of two hydrogen atoms, one sulfur atom, and four oxygen atoms. Using the molar mass allows chemists to convert between grams of \(\mathrm{H}_{2}\mathrm{SO}_{4}\) and moles, which is crucial for determining the molarity of a solution, or how many moles are in a liter of solution.
Solution Chemistry
Understanding solution chemistry is vital for determining concentrations like molarity, which reflects how much of a solute is present in a given volume of solvent. This knowledge is essential for various applications, from making chemical reactions happen efficiently in a laboratory to producing solutions in industrial plants. Solution chemistry helps us tailor the concentration and proportion of ingredients to achieve desired outcomes and physical properties.