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Which of the following gases has the maximum value of \(^{4} \mathrm{a}\) " in Van der Waals equation? (1) \(\mathrm{H}_{2}\) (2) \(\mathrm{He}\) (3) \(\mathrm{O}_{2}\) (4) \(\mathrm{NH}_{3}\)

Short Answer

Expert verified
NH\textsubscript{3} has the maximum value of \(a\).

Step by step solution

01

Understand the Van der Waals Equation

The Van der Waals equation is given by \[ \bigg( P + \frac{a}{V_m^2} \bigg)(V_m - b) = RT \]where \(a\) represents the measure of the attraction between molecules, and \(b\) is the volume excluded by a mole of the gas particles.
02

Identify the Variables related to Strength of Attraction

Among the constants, a higher value of the Van der Waals constant \(a\) indicates stronger intermolecular forces of attraction.
03

Compare the given gases

Now, let's compare the intermolecular attraction (\(a\) values) for the gases listed: \(\mathrm{H_{2}}: a = 0.244 \, L^2 bar/mol^2\) \(\mathrm{He}: a = 0.0341 \, L^2 bar/mol^2\) \(\mathrm{O_{2}}: a = 1.360 \, L^2 bar/mol^2\) \(\mathrm{NH_{3}}: a = 4.170 \, L^2 bar/mol^2\)
04

Determine the Maximum Value

Among the given gases, \( \mathrm{NH_{3}} \) has the highest value of the Van der Waals constant \(a = 4.170 \, L^2 bar/mol^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Van der Waals Equation and Intermolecular Forces
The Van der Waals equation is a modified version of the Ideal Gas Law to account for intermolecular forces and the finite size of gas molecules. It is given by:equationdisplaying:\(\big( P + \frac{a}{V_m^2} \big)(V_m - b) = RT\)In this equation, \(P\) is the pressure, \(V_m\) is the molar volume, \(R\) is the universal gas constant, and \(T\) is temperature. The constants \(a\) and \(b\) correct for intermolecular attractions and the volume occupied by gas molecules, respectively. The constant \(a\), in particular, signifies the strength of intermolecular attractions. A higher \(a\) value indicates stronger attraction between molecules. For example, among \(H_2\), \(He\), \(O_2\), and \(NH_3\), \(NH_3\) exhibits the strongest intermolecular forces because it has the highest \(a\) value.
Ideal Gas Law and Its Limitations
The Ideal Gas Law is expressed as:\(PV = nRT\)where \(P\) is pressure, \(V\) is volume, \(n\) is the number of moles, \(R\) is the gas constant, and \(T\) is temperature. This equation assumes that gas molecules have no volume and do not interact with each other through intermolecular forces. Although simple, it falls short when dealing with real gases, especially under high pressure or low temperature. That’s where the Van der Waals equation comes in, precisely introducing parameters \(a\) and \(b\) to correct for these interactions and the non-zero size of molecules, thus providing more accurate predictions.
Understanding Gas Constants
In gas laws, various constants are used for precise measurements and predictions. The universal gas constant \(R\) is a key part of these laws. It is a physical constant expressed as \(8.314\ J/(mol·K)\) and ties together multiple gas law equations, like the Ideal Gas Law and the Van der Waals Equation.Additionally, in the Van der Waals equation, two unique constants \(a\) and \(b\) are tailored for each gas:
  • \(a\): Measures intermolecular attraction. Higher values indicate stronger forces, as seen in gases like \(NH_3\).
  • \(b\): Accounts for the volume occupied by the gas particles themselves.
Understanding these constants helps in predicting the behavior of real gases under various conditions. Comparing these constants across different gases reveals their unique properties, such as why \(NH_3\) has more intermolecular forces compared to \(H_2\) or \(He\).

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Most popular questions from this chapter

RMS velocity of a gas at STP cannot be calculated by the following expressions (1) \(\sqrt{\frac{3 P V}{M}}\) (2) \(\sqrt{\frac{3 R T}{M}}\) (3) \(\sqrt{\frac{3 P}{d}}\) (4) \(\sqrt{\frac{3 R T}{d}}\)

With the increase in temperature of a gas the fraction of molecules having velocities within a given range around the most probable velocity would (1) increase (2) decrease (3) remain unchanged (4) initially increase and then decrease

The rates of diffusion of \(\mathrm{SO}_{2}, \mathrm{CO}_{2}, \mathrm{PCl}_{3}\) and \(\mathrm{SO}_{3}\) are in the following (1) \(\mathrm{PCl}_{3}>\mathrm{SO}_{3}>\mathrm{SO}_{2}>\mathrm{CO}_{2}\) (2) \(\mathrm{CO}_{2}>\mathrm{SO}_{2}>\mathrm{PCl}_{3}>\mathrm{SO}_{3}\) (3) \(\mathrm{SO}_{2}>\mathrm{SO}_{3}>\mathrm{PCl}_{3}>\mathrm{CO}_{2}\) (4) \(\mathrm{CO}_{2}>\mathrm{SO}_{2}>\mathrm{SO}_{3}>\mathrm{PCl}_{3}\)

A vessel has two equal compartments \(\mathrm{A}\) and \(\mathrm{B}\) containing \(\mathrm{H}_{2}\) and \(\mathrm{O}_{2}\), respectively, each at 1 atm pressure. If the wall separating the compartment is removed, the pressure (1) Will remain unchanged in \(\mathrm{A}\) and \(\mathrm{B}\) (2) Will increase in \(\mathrm{A}\) and decrease in \(\mathrm{B}\) (3) Will decrease in \(\mathrm{A}\) and increase in \(\mathrm{B}\) (4) Will increase in both \(\mathrm{A}\) and \(\mathrm{B}\)

Gases deviate from ideal behaviour at high pressure. Which of the following is correct for nonideality? (1) At high pressure, the collision between the gas molecules become enormous (2) At high pressure, the gas molecules move only in one direction (3) At high pressure, the volume of a gas becomes insignificant (4) At high pressure, the intermolecular interactions become insignificant

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