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The correct order of the arrangement of bond length is (1) \(\mathrm{F}_{2}>\mathrm{N}_{2}>\mathrm{Cl}_{2}>\mathrm{O}_{2}\) (2) \(\mathrm{Cl}_{2}>\mathrm{F}_{2}>\mathrm{O}_{2}>\mathrm{N}_{2}\) (3) \(\mathrm{O}_{2}>\mathrm{Cl}_{2}>\mathrm{N}_{2}>\mathrm{F}_{2}\) (3) \(\mathrm{F}_{2}>\mathrm{Cl}_{2}>\mathrm{N}_{2}>\mathrm{O}_{2}\)

Short Answer

Expert verified
Option 2 is correct. \(\mathrm{Cl_{2} > F_{2} > O_{2} > N_{2}}\).

Step by step solution

01

- Understand Bond Length

Bond length is the distance between the nuclei of two bonded atoms. Typically, the bond length is influenced by the size of the atoms and the bond order (single, double, triple bonds).
02

- Recognize the Elements and Bonds

Identify the molecules given in the options: \(\mathrm{F_{2}}, \mathrm{N_{2}}, \mathrm{Cl_{2}}, \mathrm{O_{2}}\). Fluorine (F) forms a diatomic molecule with a single bond, Nitrogen (N) forms a diatomic molecule with a triple bond, Chlorine (Cl) forms a diatomic molecule with a single bond, and Oxygen (O) forms a diatomic molecule with a double bond.
03

- Compare Atomic Sizes

Generally, larger atoms will have longer bond lengths. Cl (Chlorine, with atomic number 17) is larger than F (Fluorine, atomic number 9), but smaller than N and O.
04

- Bond Order Implications

Bond length also depends on the bond order. The greater the bond order, the shorter the bond length. Hence, the bond lengths should be ranked as follows based on bond order: \(\mathrm{N_{2}} (triple bond) < \mathrm{O_{2}} (double bond) < \mathrm{F_{2}} (single bond) = \mathrm{Cl_{2}} (single bond)\)
05

- Match with the Given Options

Review the provided options and match the correct ranking: For a correct arrangement, it should be that Chlorine has the highest bond length followed by Fluorine, Oxygen, and Nitrogen. Option 2 matches this: \(\mathrm{Cl_{2} > F_{2} > O_{2} > N_{2}}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bond Length
Bond length is the distance between the nuclei of two bonded atoms. Imagine holding hands with someone. The distance from your hand to the other person’s hand is like a bond length. This distance can vary depending on several factors:
First, the size of the atoms matters. Bigger atoms tend to have longer bond lengths because their nuclei are further apart.
Second, the type of bond (or bond order) between the atoms affects the bond length. Bond order refers to whether the bond is single, double, or triple. A single bond is like holding hands with one hand, a double bond like holding with both hands, and a triple bond like holding with more force. The stronger or higher the bond order, the shorter the bond length.
Therefore, to determine the bond length, you should consider both the size of the atoms and the bond order.
Diatomic Molecules
Diatomic molecules are molecules composed of only two atoms. The term 'diatomic' comes from 'di-', meaning two, and 'atomic', referring to atoms.
Some common diatomic molecules you might encounter are:
  • \(\text{H}_{2}\) - Hydrogen
  • \(\text{O}_{2}\) - Oxygen
  • \(\text{N}_{2}\) - Nitrogen
  • \(\text{F}_{2}\) - Fluorine
  • \(\text{Cl}_{2}\) - Chlorine
These gases naturally form pairs of atoms. This pairing offers stability to the molecules. In the given exercise, we specifically look at the bond lengths in \(\text{F}_{2}\), \(\text{N}_{2}\), \(\text{Cl}_{2}\), and \(\text{O}_{2}\). Each of these belongs to a group of diatomic molecules. By understanding their nature, we can more accurately predict how they bond and their bond lengths.
Bond Order
Bond order refers to the number of chemical bonds between a pair of atoms. It can be thought of as how tightly the atoms are held together. Bond order plays a significant role in determining bond length:
  • Single Bond (Bond Order 1): This is the longest type of bond, as it involves only one pair of electrons holding the two atoms together.
  • Double Bond (Bond Order 2): A bit shorter than a single bond, as two pairs of electrons pull the atoms closer together.
  • Triple Bond (Bond Order 3): The shortest of all, with three pairs of electrons creating very strong attraction and minimal distance between the nuclei.
For the given diatomic molecules: \(\text{F}_{2}\) and \(\text{Cl}_{2}\) have single bonds, \(\text{O}_{2}\) has a double bond, and \(\text{N}_{2}\) has a triple bond. As bond order increases from a single bond to a triple bond, the bond length decreases. Remember this hierarchy while comparing bond lengths in different molecules.

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Most popular questions from this chapter

Which of the following conditions is not correct for resonating structures? (1) The contributing structures must have the same number of unpaired electrons. (2) The contributing structures should have similar energies. (3) The contributing structures should be so written that unlike charges reside on atoms that are far apart. (4) The positive charge should be present on the electropositive clement and the negative charge on the electroncgative clement.

Hydrogen bonds are formed between moleculcs in which hydrogen is covalently bonded to an clcment whose atomic radius and electroncgativity respectively are (1) large and low (2) large and high (3) small and high (4) small and low

Which of the following statement is wrong? (1) Bond length decreases with increase in \(\mathrm{p}\) -character, (2) Bond energy of \(\mathrm{HF}\) is the highest among hydrogen halides. (3) Bond energy decreases with increase in the lone pair electrons on bonded atoms. (4) Bond energy of a covalent bond increases with increase in the difference of electronegativities of bonded atoms.

Which of the following statement is falsc? (1) The measurement of dipole moment of a gaseous diatomic molecule is a direct indication of bond polarity. (2) For a polyatomic molecule, its dipole moment is determined only from bond moments. (3) \(\mathrm{SO}_{2}\) is nonlinear and as a consequence it should have dipole moment, (4) Lone pair of electrons present on central atom can give rise to dipole moment.

Which of the following statement is false? (1) The boiling point of a compound is raised by intermolecular hydrogen bonding. (2) o-nitrophenol is more volatile than p-nitrophenol because of intramolecular hydrogen bonding. (3) Lower alcohols such as methanol and ethanol arc miscible in water due to hydrogen bonding. (4) Intramolecular hydrogen bond enhances the boiling point.

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