Chapter 14: Problem 55
Which of the following arrangement is the true with respect to acidic strength (1) \(\mathrm{CH}_{3} \mathrm{COOH}<\mathrm{HCOOH}<\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\) (2) \(\mathrm{FCH}_{2} \mathrm{COOH}<\mathrm{F}_{2} \mathrm{CHCOOH}<\mathrm{F}_{3} \mathrm{CCOOH}\) (3) \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{OH}<\mathrm{CH}_{3} \mathrm{COOH}<\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{OH}\) (4) None of these is correct
Short Answer
Step by step solution
Understanding acidic strength
Analyze Option (1)
Analyze Option (2)
Analyze Option (3)
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Acidic strength order
In general, a stronger acid will more readily lose a proton and stabilize its conjugate base better.
Here are key points to remember:
- The more stable the conjugate base, the stronger the acid.
- Electron-withdrawing groups attached to the molecule usually increase acidity.
- Electron-donating groups typically decrease acidity.
Always compare molecules by looking at their structures and the groups attached to them to establish the acidic strength order.
Electron-withdrawing groups
Let's see why:
- When a proton is lost, an electron-withdrawing group stabilizes the conjugate base by reducing the negative charge density.
- This increased stabilization makes the acid stronger since the conjugate base is more stabilized.
For example, consider the series \(\text{FCH}_2\text{COOH} < \text{F}_2\text{CHCOOH} < \text{F}_3\text{CCOOH}\). The fluorine atoms are electron-withdrawing, and as their number increases, so does the acidic strength. This is because the conjugate base is progressively better stabilized by the presence of more fluorine atoms.
Conjugate base stabilization
A stabilized conjugate base means a stronger acid. Here’s a closer look:
- Resonance: Delocalization of electrons through resonance can significantly stabilize the conjugate base.
- Inductive effect: Electron-withdrawing groups can stabilize the negative charge via the inductive effect, pulling electron density away from the conjugate base.
To grasp this, consider phenol (\(\text{C}_6\text{H}_5\text{OH}\)), acetic acid (\(\text{CH}_3\text{COOH}\)), and vinyl alcohol (\(\text{CH}_2 = \text{CH} - \text{OH}\)). In phenol, the conjugate base is stabilized by resonance between the aromatic ring and the oxygen. In vinyl alcohol, resonance also plays a role, making it more acidic than acetic acid. This concept explains why acidic strength order is essential for predicting reactions and behavior in organic chemistry.