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Write the conjugate acids for the following Br枚nsted bases: \(\mathrm{NH}_{2}^{-}, \mathrm{NH}_{3}\) and \(\mathrm{HCOO}\).

Short Answer

Expert verified
The conjugate acids are NH鈧, NH鈧勨伜, and HCOOH, respectively.

Step by step solution

01

Understanding Conjugate Acids

To find the conjugate acid of a base, we need to understand that a conjugate acid is formed when a base gains a proton (H鈦). This generally involves adding an H鈦 to the molecular formula of the base.
02

Conjugate Acid of \(\mathrm{NH}_{2}^{-}\)

The base \(\mathrm{NH}_{2}^{-}\) gains a proton (H鈦) to form its conjugate acid. When one hydrogen ion is added to \(\mathrm{NH}_{2}^{-}\), it becomes \(\mathrm{NH}_{3}\). Thus, the conjugate acid of \(\mathrm{NH}_{2}^{-}\) is \(\mathrm{NH}_{3}\).
03

Conjugate Acid of \(\mathrm{NH}_{3}\)

The base \(\mathrm{NH}_{3}\) gains a proton (H鈦) to form its conjugate acid. By adding one hydrogen ion to \(\mathrm{NH}_{3}\), it becomes \(\mathrm{NH}_{4}^{+}\). Therefore, the conjugate acid of \(\mathrm{NH}_{3}\) is \(\mathrm{NH}_{4}^{+}\).
04

Conjugate Acid of \(\mathrm{HCOO}^{-}\)

The base \(\mathrm{HCOO}^{-}\) also gains a proton (H鈦) to form its conjugate acid. By adding one hydrogen ion to \(\mathrm{HCOO}^{-}\), it becomes \(\mathrm{HCOOH}\). So, the conjugate acid of \(\mathrm{HCOO}^{-}\) is \(\mathrm{HCOOH}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Br枚nsted Bases
Br枚nsted bases are substances that can accept a proton, which is represented as \(\mathrm{H}^{+}\). The term 'proton' is used because the hydrogen atom often loses its electron, leaving just the proton behind. This concept was introduced by Johannes Nicolaus Br枚nsted, who played a significant role in defining acids and bases in a new way that broadened our understanding of chemical reactions.

In everyday chemistry, identifying a Br枚nsted base involves looking for atoms or molecules that have the ability to gain a proton. This includes not only the more obvious hydroxide ions but also other species like amines and carboxylate ions. When a base accepts a proton, it turns into its conjugate acid. For example:
  • \(\mathrm{NH}_{2}^{-}\) accepts a proton to become \(\mathrm{NH}_{3}\).
  • \(\mathrm{NH}_{3}\) becomes \(\mathrm{NH}_{4}^{+}\) after gaining a proton.
  • \(\mathrm{HCOO}^{-}\) when protonated turns into \(\mathrm{HCOOH}\).
This ability to accept protons is pivotal in many chemical reactions that involve acid-base chemistry.
Proton Transfer
Proton transfer is a fundamental process in chemistry where a proton is transferred from one molecule (acid) to another (base). This transaction is at the heart of many chemical reactions, especially those that involve acids and bases.

During proton transfer, the base accepts the proton, which transforms it into a conjugate acid. The original acid, having lost its proton, becomes a conjugate base. This back-and-forth process is essential for reaching equilibrium in acid-base reactions.

The concept is simple: a proton, \(\mathrm{H}^{+}\), moves between species, highlighting the dynamic nature of chemical reactions. Understanding which molecule can donate or accept a proton helps us predict the outcomes of these reactions.
Chemical Reactions
Chemical reactions are processes that convert one or more substances into new substances. In the context of acid-base chemistry, these reactions often involve protons being transferred between chemicals. This can lead to dramatic changes, even in the chemicals' physical states or color.

The acid-base reactions involve key players like acids, which release protons, and bases, like Br枚nsted bases, that accept them. For instance, in a reaction where \(\mathrm{NH}_{3}\) gains a proton to become \(\mathrm{NH}_{4}^{+}\), we see the base-to-conjugate-acid transformation.

Observing these transformations helps clarify the underlying changes happening during chemical reactions. Hence, recognizing the roles of different materials can aid in navigating complex chemistry problems.
Acid-Base Chemistry
Acid-base chemistry focuses on the relationship and reactions between acids and bases. It's a branch of chemistry that's crucial for understanding countless natural and industrial processes.

In this field, acids are defined as proton donors, and bases are proton acceptors. When a base gains a proton, it forms its conjugate acid, and this transformation is foundational to the balancing act in chemical reactions. The reverse is also true where the acid loses a proton and becomes its conjugate base.

Acid-base reactions are a practical way to appreciate the exchange of protons. By learning about how substances like \(\mathrm{NH}_{2}^{-}\), \(\mathrm{NH}_{3}\), and \(\mathrm{HCOO}^{-}\) behave, you gain insights into broader chemical principles that affect everything from biochemical pathways to environmental processes.

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Most popular questions from this chapter

Calculate the degree of ionization of \(0.05 \mathrm{M}\) acetic acid if its \(\mathrm{pK}\) value is \(4.74\). How is the degree of dissociation affected when its solution also contains (a) \(0.01 \mathrm{M}\) (b) \(0.1 \mathrm{M}\) in \(\mathrm{HCl} ?\)

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