Chapter 8: Problem 29
The compressibility factor for ethane at \(600 \mathrm{~K}\) can be fit to the expression $$ \begin{aligned} Z=1.0000 &-0.000612(P / \mathrm{bar})+2.661 \times 10^{-6}(P / \mathrm{bar})^{2} \\ &-1.390 \times 10^{-4}(P / \mathrm{bar})^{3}-1.077 \times 10^{-13}(P / \mathrm{bar})^{4} \end{aligned} $$ for \(0 \leq P /\) bar \(\leq 600\). Use this expression to determine the fugacily cocfficient of ethane as a function of pressure at \(600 \mathrm{~K}\).
Short Answer
Step by step solution
Understand the Problem
Write the Fugacity Coefficient Equation
Substitute Z into the Integral
Simplify the Integral
Integrate the Function
Evaluate at Upper Limit
Find Fugacity Coefficient Expression
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Fugacity Coefficient
The fugacity coefficient, denoted by \( \phi \), is defined mathematically as:
- \( \ln \phi = \int_{0}^{P} \left( \frac{Z - 1}{P} \right) dP \)
This concept simplifies predicting a gas's behavior under different conditions, making it easier to handle real-world situations involving gases.
Ideal Gas Behavior
- Real gases deviate from ideal behavior at high pressures and low temperatures due to intermolecular forces and the finite size of molecules.
- The compressibility factor \( Z \) helps quantify these deviations from ideal gas behavior.
Polynomial Integration
Substituting this polynomial into the integral for \( \ln \phi \), it becomes essential to integrate each term individually:
- For a polynomial term \( ax^n \), the antiderivative is \( \frac{a}{n+1}x^{n+1} \).
Thermodynamics
- First Law of Thermodynamics: This is the law of energy conservation. It forms the basis for understanding energy transfer in systems.
- Second Law of Thermodynamics: Deals with entropy and the direction of energy transfers.