Chapter 13: Problem 48
Given that \(\Delta_{i} G\left[\mathrm{HSO}_{4}^{-}(\mathrm{aq})\right]=-755.91 \mathrm{~kJ} \cdot \mathrm{mol} /\) and that \(\Delta_{f} G^{\prime}\left[\mathrm{SO}_{4}^{2-}(\mathrm{aq})\right]=\) \(-744.53 \mathrm{~kJ} \cdot \mathrm{mol}^{-1}\), calculate the value of the second acid- dissociation constant of sulfuric acid al \(298.15 \mathrm{~K}\).
Short Answer
Step by step solution
Write the Reaction Equation
Determine Reaction Free Energy Change
Calculate the Value of \(\Delta_r G\)
Calculate the Acid-Dissociation Constant \(K_a\)
Solve for \(K_a\)
Calculate the Exponential
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gibbs Free Energy
- If \( \Delta G < 0 \), the process occurs spontaneously.
- If \( \Delta G > 0 \), the process is non-spontaneous.
- If \( \Delta G = 0 \), the system is in equilibrium.
Sulfuric Acid
- The first dissociation: \( \text{H}_2\text{SO}_4 \rightarrow \text{HSO}_4^- + \text{H}^+ \)
- The second dissociation: \( \text{HSO}_4^- \rightarrow \text{SO}_4^{2-} + \text{H}^+ \)
Thermodynamics Calculations
To calculate \( \Delta_r G \) for the dissociation, we use:\[ \Delta_r G = \Delta_{f} G[\mathrm{products}] - \Delta_{f} G[\mathrm{reactants}] \]For the reaction \( \mathrm{HSO}_4^- \rightarrow \mathrm{SO}_4^{2-} + \mathrm{H}^+ \), the calculation becomes inserting the given values:\[ \Delta_r G = (-744.53 + 0) - (-755.91) = 11.38, \text{ kJ/mol} \]Using the relationship \( \Delta_r G = -RT\ln K_a \), where \( R \) is the gas constant \( 8.314 \text{ J/mol} \cdot \text{K} \), we solve for \( K_a \):\[ \ln K_a = -\frac{11.38}{2.47988} \]This reveals \( K_a = e^{-4.59} \equiv 0.0101 \).
These calculations not only provide the dissociation constant but also offer insights into the thermodynamic feasibility of the reaction, contributing to a broader understanding of chemical equilibria and reaction spontaneity.