Chapter 9: Problem 3
Determine the vapor pressure of a solution containing \(190 \mathrm{~g} \mathrm{MgCl}_2\) in \(540 \mathrm{~g}\) water at room temperature: (Note: The vapor pressure of pure water at \(25^{\circ} \mathrm{C}\) is \(3.2 \mathrm{kPa}\).)
Short Answer
Expert verified
3.00 kPa
Step by step solution
01
Calculate Moles of Solute
Determine the moles of \(\text{MgCl}_2\) by using its molar mass. The molar mass of \(\text{MgCl}_2\) is \(\text{24.305 g/mol (Mg)} + 2 \times \text{35.453 g/mol (Cl)} = 95.211 \text{ g/mol}\). Thus, the moles of \(\text{MgCl}_2\) are \(\frac{190 \text{ g}}{95.211 \text{ g/mol}} \approx 1.996 \text{ mol}\).
02
Calculate Moles of Solvent
Determine the moles of water \( \text{H}_2\text{O} \) using its molar mass, which is \(\text{18.015 g/mol} \). Thus, the moles of \( \text{H}_2\text{O} \) are \(\frac{540 \text{ g}}{18.015 \text{ g/mol}} = 29.97 \text{ mol} \).
03
Calculate Total Moles in Solution
Add the moles of \( \text{MgCl}_2 \) and water to find the total moles in the solution. Total moles are \( 1.996 \text{ mol} + 29.97 \text{ mol} = 31.966 \text{ mol} \).
04
Determine Mole Fraction of Solvent
Calculate the mole fraction of the solvent (water). The mole fraction of water is \(\frac{\text{moles of } \text{H}_2\text{O}}{\text{total moles}} = \frac{29.97 \text{ mol}}{31.966 \text{ mol}} \approx 0.937 \).
05
Apply Raoult's Law
Use Raoult's Law \( P_{\text{solution}} = X_{\text{solvent}} \times P_{\text{pure solvent}} \) where \( P_{\text{pure solvent}} \) is the vapor pressure of pure water at \( 25^\text{C} \), which is \( 3.2 \text{kPa} \). Therefore, \( P_{\text{solution}} = 0.937 \times 3.2 \text{kPa} \approx 3.00 \text{kPa} \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Raoult's Law
Raoult's Law is a principle used to predict the vapor pressure of a solution. It states that the partial vapor pressure of a component in a solution is equal to the vapor pressure of the pure component multiplied by its mole fraction in the solution. The formula is given by: \( P_{\text{solution}} = X_{\text{solvent}} \times P_{\text{pure solvent}} \) where:
- \(P_{\text{solution}}\) = vapor pressure of the solution
- \(X_{\text{solvent}}\) = mole fraction of the solvent
- \(P_{\text{pure solvent}}\) = vapor pressure of the pure solvent
Mole Fraction
The mole fraction is a way of expressing the concentration of a component in a mixture. It is defined as the ratio of the number of moles of a particular component to the total number of moles in the solution. Mathematically, it can be written as: \( X_{\text{A}} = \frac{n_{\text{A}}}{n_{\text{total}}} \) where:
- \(X_{\text{A}}\) = mole fraction of component A
- \(n_{\text{A}}\) = number of moles of component A
- \(n_{\text{total}}\) = total number of moles in the mixture
Molar Mass
Molar mass, also known as molecular weight, is a physical property defined as the mass of a given substance (chemical element or chemical compound) divided by the amount of substance. It's usually expressed in units of grams per mole (g/mol). To calculate the molar mass of a compound, you add up the atomic masses of each element in its chemical formula. For example, the molar mass of magnesium chloride, \(\text{MgCl}_2\), is determined by:
- Atomic mass of Mg = 24.305 g/mol
- Atomic mass of Cl = 35.453 g/mol