Chapter 16: Problem 22
What \(\mathrm{H}^{+}\) concentration would you expect for the solutions below? $$ \begin{array}{ll}{\text { a. } \mathrm{pH}=9} & {\text { b. } \mathrm{pH}=7.3} \\\ {\text { c. } \mathrm{pH}=2.9} & {\text { d. } \mathrm{pH}=10.2}\end{array} $$
Short Answer
Step by step solution
Understanding the Relationship Between pH and [H鈦篯
Calculate [H鈦篯 for pH = 9
Calculate [H鈦篯 for pH = 7.3
Calculate [H鈦篯 for pH = 2.9
Calculate [H鈦篯 for pH = 10.2
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
pH calculation
To reverse this, if you're given a pH, you can find [H鈦篯 using the rearranged formula: \[ [\mathrm{H}^+] = 10^{-\text{pH}} \]. This is particularly handy when solving problems where you have to determine hydrogen ion concentrations from a given pH, much like in the exercises above.
- Keeps calculations easy and straightforward.
- Directly connect pH values with hydrogen ion concentrations.
Hydrogen ion concentration
Measured in moles per liter, [H鈦篯 reflects the number of hydrogen ions in a given volume of solution. Focusing on the specifics, each unit change in pH translates to a tenfold change in [H鈦篯. For example, a pH drop from 7 to 6 signals a tenfold increase in hydrogen ion concentration.
Calculating [H鈦篯 is crucial in chemistry and can help predict how substances will interact with one another:
- Acidity increases as [H鈦篯 rises
- Lower [H鈦篯 results in basic or neutral solutions
- Changes in [H鈦篯 affect chemical reactions and equilibria
Acid-base chemistry
Solutions with high [H鈦篯 are acidic, whereas those with more [OH鈦籡 are basic. In neutral solutions, like pure water, the concentrations of [H鈦篯 and [OH鈦籡 are equal, giving a pH of 7.
This balance, however, can shift when an acid or base is introduced. Knowing how to work with the concepts of acids and bases becomes essential when you wish to:
- Predict reaction outcomes
- Balance chemical equations
- Understand titration and buffer solutions
Logarithmic scale in chemistry
In practical terms, instead of dealing with incredibly small numbers like \(0.0000001\) M, you have a manageable figure such as 7.
This ease of representation is important:
- Makes complex calculations more straightforward
- Allows clearer comparison of different solutions
- Useful for graphical representation and analysis of chemical data