Chapter 9: Problem 20
Calculate the number of particles in each of the following: (a) 7.57 g platinum, \(P t\) (b) \(3.88 \mathrm{~g}\) ethane, \(\mathrm{C}_{2} \mathrm{H}_{6}\) (c) 0.152 g aluminum chloride, \(\mathrm{AlCl}_{3}\)
Short Answer
Expert verified
(a) 2.34脳10虏虏 atoms, (b) 7.78脳10虏虏 molecules, (c) 6.87脳10虏鈦 formula units.
Step by step solution
01
Determine Molar Mass
First, identify the molar mass of each substance.
- **Platinum (Pt):** The atomic mass of Pt is approximately 195.08 g/mol.
- **Ethane (C鈧侶鈧):** The molar mass is calculated by adding twice the atomic mass of carbon (C, 12.01 g/mol) and six times the atomic mass of hydrogen (H, 1.01 g/mol). Therefore, the molar mass of C鈧侶鈧 is approximately 30.07 g/mol.
- **Aluminum Chloride (AlCl鈧):** The molar mass is calculated by adding the atomic mass of aluminum (Al, 26.98 g/mol) and three times the atomic mass of chlorine (Cl, 35.45 g/mol). Therefore, the molar mass of AlCl鈧 is approximately 133.33 g/mol.
02
Convert Mass to Moles
Using the formula \(\text{moles} = \frac{\text{mass in grams}}{\text{molar mass}}\), calculate the number of moles for each substance.- **Platinum (Pt):** \\[\frac{7.57 \, \text{g}}{195.08 \, \text{g/mol}} = 0.0388 \, \text{moles}\]- **Ethane (C鈧侶鈧):** \\[\frac{3.88 \, \text{g}}{30.07 \, \text{g/mol}} = 0.1292 \, \text{moles}\]- **Aluminum Chloride (AlCl鈧):** \\[\frac{0.152 \, \text{g}}{133.33 \, \text{g/mol}} = 0.00114 \, \text{moles}\]
03
Convert Moles to Number of Particles
Use Avogadro's number, \(6.022 \times 10^{23}\) particles/mol, to find the number of particles in each case by multiplying the number of moles by Avogadro's number.- **Platinum (Pt):** \[0.0388 \, \text{moles} \times 6.022 \times 10^{23} \, \text{particles/mol} = 2.34 \times 10^{22} \, \text{atoms}\]- **Ethane (C鈧侶鈧):** \[0.1292 \, \text{moles} \times 6.022 \times 10^{23} \, \text{particles/mol} = 7.78 \times 10^{22} \, \text{molecules}\]- **Aluminum Chloride (AlCl鈧):** \[0.00114 \, \text{moles} \times 6.022 \times 10^{23} \, \text{particles/mol} = 6.87 \times 10^{20} \, \text{formula units}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Molar Mass
Molar mass is a fundamental concept in chemistry. It is the mass of one mole of a given substance, expressed in grams per mole (g/mol). To understand why this is important, think of molar mass as the bridge that connects the mass of individual atoms to the quantities we work with in the laboratory. It allows us to convert grams into moles, making it easier to work with chemical equations and reactions in real-life scenarios. To calculate the molar mass, we simply add up the atomic masses of all the atoms present in a molecule. For example, to find the molar mass of ethane, \(C_2H_6\), we sum up the masses of 2 carbon atoms and 6 hydrogen atoms:
- Carbon (C): 12.01 g/mol 脳 2 = 24.02 g/mol
- Hydrogen (H): 1.01 g/mol 脳 6 = 6.06 g/mol
Avogadro's Number
Avogadro's number, \(6.022 \times 10^{23}\), is a key figure in chemistry known as a mole. It represents the number of particles (atoms, molecules, ions, or formula units) in one mole of a substance. But why is this number so significant?Avogadro's number provides the link between the microscopic world of atoms and the macroscopic world we experience. It enables precise calculations of quantities and reactions. For example, if we know the number of moles of a substance, we can quickly calculate the exact number of particles, which is incredibly useful in stoichiometry.Consider calculating the number of atoms in platinum using Avogadro's number:- Start with the moles you calculated from mass using molar mass.- Multiply the moles by Avogadro's number:\[ 0.0388 \, \text{moles of Pt} \times 6.022 \times 10^{23} \, \text{particles/mol} = 2.34 \times 10^{22} \, \text{atoms of Pt} \]This conversion is what makes Avogadro鈥檚 number such a powerful tool in chemistry.
Stoichiometry
Stoichiometry is a branch of chemistry that focuses on the quantitative relationships between the reactants and products in a chemical reaction. It enables chemists to predict the outcomes of reactions, balance chemical equations, and calculate the quantities of substances consumed and produced.
To understand stoichiometry better, think of a recipe for baking a cake. Just as you need specific amounts of ingredients like flour and sugar to make a perfect cake, a chemical reaction requires specific amounts of each reactant to produce the desired product. This ensures that no reactant is wasted, and the reaction proceeds efficiently.
Stoichiometry calculations often involve the following steps:
- Determine the balanced chemical equation for the reaction.
- Use the molar masses of reactants and products to convert mass into moles.
- Apply the mole ratios from the balanced equation to find moles of other substances.