Chapter 7: Problem 29
Provide the formula for each of the following binary ionic compounds: (a) copper(I) oxide (b) iron(III) nitride (c) mercury(II) chloride (d) lead(IV) sulfide
Short Answer
Expert verified
(a) Cu鈧侽, (b) FeN, (c) HgCl鈧, (d) PbS鈧.
Step by step solution
01
Identify the Cation and Anion
For each compound, we need to determine the cation (positive ion) and the anion (negative ion) from the chemical name. In binary ionic compounds, the cation is usually a metal or a positive ion, while the anion is a non-metal or a negative ion:
(a) Copper(I) oxide contains Cu鈦 (copper ion with a +1 charge) as the cation and O虏鈦 (oxide ion) as the anion.
(b) Iron(III) nitride contains Fe鲁鈦 (iron ion with a +3 charge) as the cation and N鲁鈦 (nitride ion) as the anion.
(c) Mercury(II) chloride contains Hg虏鈦 (mercury ion with a +2 charge) as the cation and Cl鈦 (chloride ion) as the anion.
(d) Lead(IV) sulfide contains Pb鈦粹伜 (lead ion with a +4 charge) as the cation and S虏鈦 (sulfide ion) as the anion.
02
Balance Charges for Compound Formation
To form a neutral binary ionic compound, the total positive charge must equal the total negative charge.(a) For copper(I) oxide, Cu鈦 and O虏鈦 will combine as two Cu鈦 ions for each O虏鈦 to balance the charges: - \[ \text{Cu}_2\text{O} \](b) For iron(III) nitride, the charges of Fe鲁鈦 and N鲁鈦 balance in a 1:1 ratio: - \[ \text{FeN} \](c) For mercury(II) chloride, one Hg虏鈦 balances with two Cl鈦 ions: - \[ \text{HgCl}_2 \](d) For lead(IV) sulfide, one Pb鈦粹伜 balances with two S虏鈦 ions: - \[ \text{PbS}_2 \]
03
Write the Formula
Using the balanced formulas from Step 2, write the correct chemical formula for each ionic compound.(a) Copper(I) oxide: - \[ \text{Cu}_2\text{O} \](b) Iron(III) nitride: - \[ \text{FeN} \](c) Mercury(II) chloride: - \[ \text{HgCl}_2 \](d) Lead(IV) sulfide: - \[ \text{PbS}_2 \]
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91影视!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ionic Compound Formulas
When writing formulas for binary ionic compounds, it's vital to understand that these compounds are made up of two different elements: a metal and a non-metal. The metal, or cation, is usually listed first and is positively charged, while the non-metal, or anion, is negatively charged. This order is due to the nature of ionic bonds, which are said to be formed from an attraction between oppositely charged ions.
In a binary ionic formula, the charges of the ions must balance, resulting in a neutral compound. The subscript numbers in the chemical formula represent the smallest ratio of cations to anions required to balance these charges.
For example, in copper(I) oxide, the formula is written as \( \text{Cu}_2\text{O} \). This indicates that there are two copper ions for each oxide ion. Understanding the process of balancing these charges is essential for correctly writing the formulas of ionic compounds.
In a binary ionic formula, the charges of the ions must balance, resulting in a neutral compound. The subscript numbers in the chemical formula represent the smallest ratio of cations to anions required to balance these charges.
For example, in copper(I) oxide, the formula is written as \( \text{Cu}_2\text{O} \). This indicates that there are two copper ions for each oxide ion. Understanding the process of balancing these charges is essential for correctly writing the formulas of ionic compounds.
Cation and Anion Identification
Identifying cations and anions in ionic compounds is crucial because it determines how you'll balance the charges later. Cations are often metals that lose electrons, giving them a positive charge. Conversely, anions are non-metals that gain electrons, so they have a negative charge.
To identify these ions from a compound's name:
To identify these ions from a compound's name:
- Cations are generally named first and often involve metals. For instance, in iron(III) nitride, 'iron(III)' suggests the cation is iron with a +3 charge (Fe鲁鈦).
- Anions typically follow and are often designated by either the name of the non-metal ending in '-ide,' such as 'nitride,' which is N鲁鈦 in iron(III) nitride.
Balancing Charges
Balancing charges is the step that ensures your ionic compound is neutral overall, which is how compounds naturally occur. The total charge from the cations must equal the total charge from the anions. This balance is achieved by adjusting the subscripts in the formula.
Consider mercury(II) chloride: mercury(II) means Hg虏鈦. Chloride is Cl鈦. Since two chloride ions each contribute a -1 charge (-2 in total), they balance the +2 charge from one mercury ion.
The resulting balanced formula is \( \text{HgCl}_2 \). This method of charge balancing ensures that each compound you write down adheres to the basic rule of neutrality found in nature. It's like solving a simple math equation where the positive and negative parts must cancel each other out.
Consider mercury(II) chloride: mercury(II) means Hg虏鈦. Chloride is Cl鈦. Since two chloride ions each contribute a -1 charge (-2 in total), they balance the +2 charge from one mercury ion.
The resulting balanced formula is \( \text{HgCl}_2 \). This method of charge balancing ensures that each compound you write down adheres to the basic rule of neutrality found in nature. It's like solving a simple math equation where the positive and negative parts must cancel each other out.