/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 The initial radioactivity of a c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The initial radioactivity of a cobalt- 60 sample was 1200 dpm and after 21.2 years the activity dropped to \(75 \mathrm{dpm}\). What is the half-life of the radionuclide?

Short Answer

Expert verified
The half-life of cobalt-60 is approximately 5.30 years.

Step by step solution

01

Understand the Decay Formula

The decay of a radioactive substance is described by the formula \( A = A_0 \times e^{-kt} \), where \( A \) is the activity at time \( t \), \( A_0 \) is the initial activity, \( k \) is the decay constant, and \( e \) is the base of natural logarithms.
02

Identify Known Values

From the problem, we know that \( A_0 = 1200 \text{ dpm} \), \( A = 75 \text{ dpm} \), and \( t = 21.2 \text{ years} \). Our goal is to find the half-life (\( t_{1/2} \)) of the radionuclide.
03

Solve for Decay Constant (k)

Rearrange the decay formula to solve for \( k \): \( k = -\frac{1}{t} \ln\left(\frac{A}{A_0}\right) \). Plug in the known values: \( k = -\frac{1}{21.2} \ln\left(\frac{75}{1200}\right) \). Calculate the natural logarithm and the decay constant.
04

Calculate the Decay Constant

First, calculate \( \ln\left(\frac{75}{1200}\right) = \ln(0.0625) \approx -2.7726 \). Then, \( k = -\frac{1}{21.2} \times (-2.7726) \approx 0.13075 \text{ per year} \).
05

Use Formula for Half-life

The half-life \( t_{1/2} \) is given by \( t_{1/2} = \frac{0.693}{k} \). Substitute the value of \( k \) into this formula to find the half-life.
06

Calculate Half-life

Substitute \( k \approx 0.13075 \) into the half-life formula: \( t_{1/2} = \frac{0.693}{0.13075} \approx 5.30 \text{ years} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
Radioactive decay is a natural process by which an unstable atomic nucleus loses energy by emitting radiation. This process results in the transformation of the original atom into a different element or a different isotope of the same element. Radioactive decay occurs at the atomic level and can happen through several different pathways, including alpha decay, beta decay, and gamma decay.
  • Alpha decay: Involves the emission of an alpha particle (2 protons and 2 neutrons), reducing the atomic number by 2 and the mass number by 4.
  • Beta decay: Involves the transformation of a neutron into a proton (or vice versa), emitting a beta particle (an electron or positron).
  • Gamma decay: Involves the release of gamma photons, occurring when the nucleus transitions from a higher energy state to a lower one without changing the element's identity.

The rate at which a radioactive substance decays is described by specific mathematical equations. It is predictable and constant for a given substance, making it a powerful tool for dating geological and archaeological samples.
Decay Constant
The decay constant, represented by the symbol \( k \), is a key term in the formula used to calculate radioactive decay. It defines the probability per unit time that a nucleus will decay. Specifically, the decay constant is crucial for determining how fast a radioactive substance will decrease over time.
  • The decay constant is unique for each radioactive isotope and is related to its half-life.
  • A larger decay constant means the substance will decay more quickly.
  • The decay constant is measured in units of inverse time (e.g., per year, per second).

Mathematically, the decay constant \( k \) is related to the half-life \( t_{1/2} \) by the equation: \( t_{1/2} = \frac{0.693}{k} \). This relationship shows how these two parameters are interconnected and helps to calculate the half-life if \( k \) is known.
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a mathematical function that is the inverse of the exponential function \( e^x \). Understanding natural logarithms is crucial when dealing with the exponential decay equations in radioactive decay calculations.
  • The natural logarithm has a base \( e \), which is approximately equal to 2.71828.
  • It is used to linearize exponential growth or decay, making calculations more manageable.
  • In radioactive decay equations, the natural logarithm helps to solve for variables like the decay constant or the amount of substance remaining after a period of time.

In the context of the given problem, the natural logarithm of the ratio of final to initial activity helped determine the decay constant \( k \). This is a common step in solving decay-related problems.
Cobalt-60
Cobalt-60 is a radioactive isotope of cobalt, often used in medical applications and industrial radiography. It emits gamma rays, which makes it highly useful for these purposes. Cobalt-60 has a known half-life, making it a common subject in half-life and decay calculations.
  • Cobalt-60 undergoes beta decay to become an isotope of nickel, with the emission of beta particles and gamma rays.
  • Its decay is described using the same mathematical principles applicable to all radioactive substances.
  • The energy released in Cobalt-60 decay is harnessed in medical treatments like radiotherapy for cancer and sterilization of medical equipment.

Understanding the properties and decay of Cobalt-60 contributes significantly to various applications in scientific and medical fields, and illustrates the principles of radioactive decay in a practical manner.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.