Chapter 19: Problem 15
The uranium- 235 decay series begins with the emission of an alpha particle. The daughter product emits a beta particle to give which nuclide?
Short Answer
Expert verified
The nuclide is protactinium-231 (
^{231}_{91}Pa").
Step by step solution
01
Understand Alpha Decay
Alpha decay involves the emission of an alpha particle, which consists of 2 protons and 2 neutrons. This means that when uranium-235 (
^{235}_{92}U") undergoes alpha decay, it loses 4 mass units and 2 protons. So, the atomic number and mass number of the daughter nuclide are reduced by 2 and 4, respectively.
02
Calculate New Atomic and Mass Numbers
Subtract 4 from the mass number and 2 from the atomic number of uranium-235. The new atomic number is 92 - 2 = 90, and the new mass number is 235 - 4 = 231. This gives us the nuclide thorium-231 (
^{231}_{90}Th").
03
Understand Beta Decay
Beta decay involves the emission of a beta particle, which is an electron. During beta decay, a neutron in the nucleus converts to a proton, increasing the atomic number by 1 while the mass number remains unchanged.
04
Calculate Resulting Nuclide After Beta Decay
Apply beta decay to thorium-231 (
^{231}_{90}Th"). The atomic number increases by 1, resulting in 90 + 1 = 91. The mass number remains 231. This gives the new nuclide protactinium-231 (
^{231}_{91}Pa").
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Alpha Decay
In the fascinating world of nuclear chemistry, alpha decay is a significant process. It involves the emission of an alpha particle from an unstable nucleus. An alpha particle is a compact little package containing 2 protons and 2 neutrons. Together, these account for a total of 4 mass units. When a nucleus undergoes alpha decay, it loses these 4 units.
This means the atomic number decreases by 2, as it loses 2 protons, and the mass number decreases by 4. For example, when uranium-235 ( ^{235}_{92}U) decays via alpha emission, it transforms into a new element with an atomic number of 90 and a mass number of 231.
This means the atomic number decreases by 2, as it loses 2 protons, and the mass number decreases by 4. For example, when uranium-235 ( ^{235}_{92}U) decays via alpha emission, it transforms into a new element with an atomic number of 90 and a mass number of 231.
- Atomic Number Change: Decreases by 2
- Mass Number Change: Decreases by 4
Beta Decay
Beta decay is another common process encountered in nuclear chemistry, offering a different transformation for unstable nuclei. In beta decay, a neutron in the nucleus is converted into a proton, and a beta particle, which is essentially an electron, is emitted.
As a result, the atomic number increases by 1 because a neutron turns into a proton, but the mass number remains constant since the proton and neutron have approximately the same mass.
As a result, the atomic number increases by 1 because a neutron turns into a proton, but the mass number remains constant since the proton and neutron have approximately the same mass.
- Atomic Number Change: Increases by 1
- Mass Number Change: Remains the same
Uranium-235 Decay Series
The uranium-235 decay series is an intriguing chain of transformations that occur as this radioactive element seeks stability. Beginning with uranium-235, each step involves either alpha or beta decay, gradually transforming into different elements until a stable compound is formed.
The sequence typically begins with the emission of an alpha particle, leading to the creation of thorium-231. As discussed, thorium-231 then undergoes beta decay to transform into protactinium-231. This process repeats through multiple steps:
The sequence typically begins with the emission of an alpha particle, leading to the creation of thorium-231. As discussed, thorium-231 then undergoes beta decay to transform into protactinium-231. This process repeats through multiple steps:
- Starts With: Uranium-235 ( ^{235}_{92}U)
- Alpha Emission: Forms Thorium-231 ( ^{231}_{90}Th)
- Beta Emission: Results in Protactinium-231 ( ^{231}_{91}Pa)