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Consider a sample of \(24.0 \mathrm{~g}\) of \(\mathrm{O}_{2}\) molecules. (a) How many moles of \(\mathrm{O}_{2}\) molecules are present? (b) How many moles of \(\mathrm{O}\) atoms are present?

Short Answer

Expert verified
(a) There are \(0.75 \mathrm{mol}\) of Oâ‚‚ molecules in the sample. (b) There are \(1.5 \mathrm{mol}\) of O atoms in the sample.

Step by step solution

01

Calculate the moles of Oâ‚‚ molecules

To find out the moles of Oâ‚‚ molecules, we need to use the formula: \[ moles = \frac{mass}{molar\,mass} \] The given mass of the Oâ‚‚ molecules is \(24.0 \mathrm{g}\), and the molar mass of Oâ‚‚ is the sum of two oxygen atoms, and as each oxygen atom has a mass of \(16.0 \mathrm{g/mol}\), the molar mass of Oâ‚‚ is \(32.0 \mathrm{g/mol}\). Now we can calculate the number of moles: \[ moles\,of\,Oâ‚‚ = \frac{24.0 \mathrm{g}}{32.0 \mathrm{g/mol}} = 0.75 \mathrm{mol} \]
02

Calculate the moles of O atoms

Knowing the moles of Oâ‚‚ molecules, we can determine the number of moles of O atoms in the sample. Since each Oâ‚‚ molecule contains two O atoms, the number of moles of O atoms will be double the number of Oâ‚‚ moles: \[ moles\,of\,O = 2 \times moles\,of\,Oâ‚‚ \] \[ moles\,of\,O = 2 \times 0.75 \mathrm{mol} = 1.5 \mathrm{mol} \] The answer to the questions is: (a) There are \(0.75 \mathrm{mol}\) of Oâ‚‚ molecules in the sample. (b) There are \(1.5 \mathrm{mol}\) of O atoms in the sample.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
Understanding molar mass is crucial when you are dealing with chemical calculations and conversions. Molar mass is the mass of one mole of a substance (typically given in grams per mole, g/mol). For example, the molar mass of oxygen (O) is 16.0 g/mol. This value is derived from the atomic mass of oxygen, found on the periodic table. To calculate the molar mass of a compound, you sum the molar masses of the individual elements that make up that compound. For example, in an oxygen molecule (Oâ‚‚), there are two oxygen atoms. Therefore, the molar mass of Oâ‚‚ is calculated as:
  • Molar mass of Oâ‚‚ = 2 × 16.0 g/mol = 32.0 g/mol
Understanding molar mass is a foundation for converting mass to moles, an important step in many chemical calculations.
Oâ‚‚ Molecules
Oxygen molecules, denoted as Oâ‚‚, are diatomic, meaning they are composed of two oxygen atoms bonded together. In many chemical processes, oxygen is essential for reactions like combustion and respiration. When you are given a mass of Oâ‚‚, it's often necessary to determine how many moles of Oâ‚‚ molecules are present. This is done using the concept of molar mass along with mass to moles conversion, which allows us to transition from a macroscopic quantity (mass in grams) to a molecular quantity (moles). For example, if we have a 24.0 g sample of Oâ‚‚, we can calculate that there are 0.75 moles of Oâ‚‚ present by using the molar mass of Oâ‚‚ (32.0 g/mol).
Mass to Moles Conversion
Converting mass to moles is a common task in chemistry that helps connect the macroscopic and microscopic worlds. The conversion uses the formula:\[ moles = \frac{mass}{molar\,mass} \]This formula allows you to calculate the number of moles of a substance when you know its mass and molar mass. Let's consider a sample of 24.0 g of Oâ‚‚. Given that the molar mass of Oâ‚‚ is 32.0 g/mol, the calculation is:
  • Moles of Oâ‚‚ = \(\frac{24.0\, g}{32.0\, g/mol} = 0.75\, mol\)
The result, 0.75 mol, tells us how many moles of Oâ‚‚ molecules are in the sample. This conversion is vital for understanding and carrying out further chemical calculations.
Chemical Calculations
Chemical calculations often involve a series of steps to determine various quantities, such as moles, atoms, or molecules. In this context, knowing how many moles of a substance you have can help initiate other calculations, like finding the number of atoms. For example, once you know there are 0.75 moles of Oâ‚‚ molecules in a sample, calculating the moles of O atoms is straightforward. Each molecule of Oâ‚‚ contains two O atoms, so you multiply the moles of Oâ‚‚ by 2:
  • Moles of O atoms = 2 × Moles of Oâ‚‚ = 2 × 0.75 mol = 1.5 mol
Understanding these calculations opens the door to solving more complex problems in chemistry, such as predicting product yields in reactions or balancing chemical equations.

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